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Vocabulary-style flashcards providing full solutions and classifications for the algebra equations shown in the practice image.
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Solving an Equation Practice Set
A set of linear equations (problems 22 through 33) to solve for x and check solutions, determining whether each equation has one solution, no solution, or infinitely many solutions.
Equation 22: x+6=x
The equation has no solution because subtracting x from both sides results in the false statement 6=0.
Equation 23: 3x−1=1−3x
The solution is x=31, obtained by adding 3x and 1 to both sides to get 6x=2.
Equation 24: 3x+15=3(x+5)
The equation has infinitely many solutions because distributing on the right side yields the identity 3x+15=3x+15.
Equation 25: 4x−9=3.5x−9
The solution is x=0, obtained by adding 9 to both sides and subtracting 3.5x to get 0.5x=0.
Equation 26: 31(9x+3)=3x+1
The equation has infinitely many solutions because distributing 31 yields the identity 3x+1=3x+1.
Equation 27: 5x−7=4x−1
The solution is x=6, obtained by subtracting 4x and adding 7 to both sides.
Equation 28: 21x+21x=x+1
The equation has no solution because combining like terms yields x=x+1, which simplifies to the false statement 0=1.
Equation 29: 2x+4=−(−7x+4)
The solution is x=58, obtained by simplifying the right side to 7x−4 and solving 2x+4=7x−4.
Equation 30: 5.5−x=−4.5−x
The equation has no solution because adding x to both sides leads to the false statement 5.5=−4.5.
Equation 31: −3(2x−3)=−6x+9
The equation has infinitely many solutions because distributing −3 on the left side yields the identity −6x+9=−6x+9.
Equation 32: 10x−38−4x=6x
The equation has no solution because combining terms on the left yields 6x−38=6x, which simplifies to the false statement −38=0.
Equation 33: 6(7x+7)=7(6x+6)
The equation has infinitely many solutions because distributing both sides yields the identity 42x+42=42x+42.