Solving Linear Equations Practice

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Vocabulary-style flashcards providing full solutions and classifications for the algebra equations shown in the practice image.

Last updated 2:11 PM on 9/12/26
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<p>Solving an Equation Practice Set</p>

Solving an Equation Practice Set

A set of linear equations (problems 22 through 33) to solve for xx and check solutions, determining whether each equation has one solution, no solution, or infinitely many solutions.

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Equation 22: x+6=xx + 6 = x

The equation has no solution because subtracting xx from both sides results in the false statement 6=06 = 0.

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Equation 23: 3x1=13x3x - 1 = 1 - 3x

The solution is x=13x = \frac{1}{3}, obtained by adding 3x3x and 11 to both sides to get 6x=26x = 2.

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Equation 24: 3x+15=3(x+5)3x + 15 = 3(x + 5)

The equation has infinitely many solutions because distributing on the right side yields the identity 3x+15=3x+153x + 15 = 3x + 15.

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Equation 25: 4x9=3.5x94x - 9 = 3.5x - 9

The solution is x=0x = 0, obtained by adding 99 to both sides and subtracting 3.5x3.5x to get 0.5x=00.5x = 0.

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Equation 26: 13(9x+3)=3x+1\frac{1}{3}(9x + 3) = 3x + 1

The equation has infinitely many solutions because distributing 13\frac{1}{3} yields the identity 3x+1=3x+13x + 1 = 3x + 1.

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Equation 27: 5x7=4x15x - 7 = 4x - 1

The solution is x=6x = 6, obtained by subtracting 4x4x and adding 77 to both sides.

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Equation 28: 12x+12x=x+1\frac{1}{2}x + \frac{1}{2}x = x + 1

The equation has no solution because combining like terms yields x=x+1x = x + 1, which simplifies to the false statement 0=10 = 1.

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Equation 29: 2x+4=(7x+4)2x + 4 = -(-7x + 4)

The solution is x=85x = \frac{8}{5}, obtained by simplifying the right side to 7x47x - 4 and solving 2x+4=7x42x + 4 = 7x - 4.

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Equation 30: 5.5x=4.5x5.5 - x = -4.5 - x

The equation has no solution because adding xx to both sides leads to the false statement 5.5=4.55.5 = -4.5.

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Equation 31: 3(2x3)=6x+9-3(2x - 3) = -6x + 9

The equation has infinitely many solutions because distributing 3-3 on the left side yields the identity 6x+9=6x+9-6x + 9 = -6x + 9.

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Equation 32: 10x834x=6x10x - \frac{8}{3} - 4x = 6x

The equation has no solution because combining terms on the left yields 6x83=6x6x - \frac{8}{3} = 6x, which simplifies to the false statement 83=0-\frac{8}{3} = 0.

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Equation 33: 6(7x+7)=7(6x+6)6(7x + 7) = 7(6x + 6)

The equation has infinitely many solutions because distributing both sides yields the identity 42x+42=42x+4242x + 42 = 42x + 42.