Group Chemistry - Group 7 (halogens)

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15 Terms

1
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Understand reasons for the trend in melting and boiling temperatures

  • simple covalent diatomic molecules

  • weak London forces between each molecule

  • as you go down the group, the number of electrons per molecule increases

  • so the strength of the london forces increases

  • therefore more energy is required to overcome the stronger intermolecular london forces

  • and the mpt / bpt increases

<ul><li><p>simple covalent diatomic molecules </p></li><li><p>weak London forces between each molecule</p></li><li><p>as you go down the group, the number of electrons per molecule increases</p></li><li><p>so the strength of the london forces increases </p></li><li><p>therefore more energy is required to overcome the stronger intermolecular london forces </p></li><li><p>and the mpt / bpt increases</p></li></ul><p></p>
2
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Understand reasons for the trends in physical state at room temperature

  • as mpt / bpt increase down the group

  • colour gets darker down the group

  • volatility decreases down the group

3
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Understand reasons for the trends in electronegativity

Electronegativity = the ability of an atom to attract a bonding pair of electrons in a covalent bond

Going down the group: 

  • atomic radius increase

  • incoming electron experiences greater amount of shielding

  • so halogen’s ability to accept an electron (oxidising power) decreases down the group

  • therefore electronegativity decreases down the group

<p>Electronegativity = the ability of an atom to attract a bonding pair of electrons in a covalent bond</p><p>Going down the group:&nbsp;</p><ul><li><p>atomic radius increase</p></li><li><p>incoming electron experiences greater amount of shielding</p></li><li><p>so halogen’s ability to accept an electron (oxidising power) decreases down the group</p></li><li><p>therefore electronegativity decreases down the group </p></li></ul><p></p>
4
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Understand reasons for the trend in reactivity of group 7 elements down the group

Down group 7:

  • atoms are larger 

  • outer electrons further away from positive nucleus

  • larger atoms find it more difficult to attract incoming electrons needed to form 1- anion 

  • therefore reactivity decreases 

<p>Down group 7:</p><ul><li><p>atoms are larger&nbsp;</p></li><li><p>outer electrons further away from positive nucleus</p></li><li><p>larger atoms find it more difficult to attract incoming electrons needed to form 1- anion&nbsp;</p></li><li><p>therefore reactivity decreases&nbsp;</p></li></ul><p></p>
5
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Understand the trend in reactivity of group 7 elements in terms of the redox reactions of Cl2, Br2 and I2 with halide ions in aqueous solution, followed by the addition of an organic solvent

  1. Place about 2cm³ of the halide solution in a test tube and then add a similar depth of the halogen solution. Place a bung in the test tube and shake.

  2. look carefully for colour changes, bearing in mind that if no reaction takes place the halogen solution will have been diluted and become paler in colour

  3. add 2cm³ of cyclohexane. Place the bung in the test tube and shake. Make a note of the colour.

Adding cyclohexane should make it more obvious if a displacement reaction has taken place because the colour of a halogen in an organic solvent is the same as the colour of its vapour.

<ol><li><p>Place about 2cm³ of the halide solution in a test tube and then add a similar depth of the halogen solution. Place a bung in the test tube and shake. </p></li><li><p>look carefully for colour changes, bearing in mind that if no reaction takes place the halogen solution will have been diluted and become paler in colour</p></li><li><p>add 2cm³ of cyclohexane. Place the bung in the test tube and shake. Make a note of the colour. </p></li></ol><p>Adding cyclohexane should make it more obvious if a displacement reaction has taken place because the colour of a halogen in an organic solvent is the same as the colour of its vapour.</p><p></p>
6
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Understand, in terms of changes in oxidation number, the following reactions of the halogens:

Oxidation reactions with group 1 and 2 metals

  • with metals such as magnesium, the halogens react to form ionic metal halides. 

  • Br2 (l) + Mg (s) → MgBr2 (s)

  • Mg → Mg2+ + 2e- (oxidation)

  • Br2 + 2e- → 2Br- (reduction)

7
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Understand, in terms of changes in oxidation number, the following reactions of the halogens:

The disproportionation reaction of chlorine water and the use of chorine in water treatment

Test for chlorine gas: with damp blue litmus paper

Result: the blue litmus paper initially turns red and then gets bleached

Cl2 (g) + H2O (l) → HCl (aq) + HOCl (aq)

where HCl is hydrochloric acid and HOCl is chloric (I) acid

At very low concentrations, chlorine is used to disinfect tap water. It forms chloric acid when it reacts with water. Chloric (I) acid is a powerful oxidising agent and a weak acid. It is an effective disinfectant because the molecules can pass through the cell walls of bacteria. Once inside the bacterium, the HClO molecules break the cell open and kill the organism by oxidising and chlorinating molecules which make up its structure.

Swimming pools can be sterilised with much higher concentrations of chlorine compounds which react to form chloric (I) acid when they dissolve in water.

8
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Understand, in terms of changes in oxidation number, the following reactions of the halogens:

The disproportionation reaction of chlorine with cold, dilute aqueous sodium hydroxide to form bleach

Cl2 (g) + 2NaOH (aq) → NaClO (aq) + NaCl (aq) + H2O (l)

  • Cl2 (g) + 2OH- (aq) → ClO- (aq) + Cl- (aq) + H2O (l)

  • this is a disproportionation reaction

  • where NaClO is bleach

9
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Understand, in terms of changes in oxidation number, the following reactions of the halogens:

The disproportionation reaction of chlorine with hot alkali

If sodium hydroxide and chlorine are reacted at about 80 degrees Celsius, then the products are sodium chlorate (V), NaClO3, as well as sodium chloride and water.

  • 3Cl2 (g) + 6NaOH (aq) → NaClO3 (aq) + 5NaCl (aq) + 3H2O (l)

  • 3Cl2 (g) + 6OH- (aq) → ClO3- (aq) + 5Cl- (aq) + 3H2O (l)

  • This is a disproportionation reaction 

10
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Understand the following reactions:

Solid group 1 halides with concentrated sulphuric acid, to illustrate the trend in reducing ability of the hydrogen halides

Chloride, Cl-

With potassium chloride the only reaction that occurs is:

KCl (s) + H2SO4 (aq) → HCl (g) + KHSO4 (aq)

No change in oxidation number, therefore reaction is not a redox reaction. 

Bromide, Br- 

A similar reaction occurs with all the potassium halide. Write an equation showing the formation of hydrogen bromide. 

KBr (s) + H2SO4 (aq) → K2SO4 (aq) + HBr (g)

With potassium bromide a redox reaction also occurs, as well as the above reaction. The Br- ions are oxidised to Br2 and the SO4 2- ions are reduced to SO2. 

2Br- + 4H+ + SO4 2- → Br2 + SO2 + 2H2O

Bromide ions are better reducing agents than chlorine ions. 

Iodide, I- 

With potassium iodide other redox reactions also occur (as well as the reactions above). With KI, the I- ions are oxidised to I2 and the SO4 2- ions are reduced to S and H2S.

6I- + SO4 2- + 8H+ → 3I2 + S + 4H2O

SO4 2- + 10H+ + 8I- → 4I2 + H2S + 4H2O

When Br- ions react with concentrated H2SO4, sulfur is reduced from +6 to +4.

In a similar reaction using I- ions, the sulfur is reduced + 6 to -2.

Therefore I- halide has the stronger reducing action on concentrated H2SO4, as it shows the greatest extent of reduction.

I- > Br- > Cl-

A reducing agent loses electrons in a reaction.

The I- ions has the biggest ionic radius and the most amount of shielding so the attraction between the positive nucleus and outermost e- is weaker so the e- is more easily lost. 

<p>Chloride, Cl- </p><p>With potassium chloride the only reaction that occurs is: </p><p>KCl (s) + H2SO4 (aq) → HCl (g) + KHSO4 (aq)</p><p>No change in oxidation number, therefore reaction is not a redox reaction.&nbsp;</p><p></p><p>Bromide, Br-&nbsp;</p><p>A similar reaction occurs with all the potassium halide. Write an equation showing the formation of hydrogen bromide.&nbsp;</p><p>KBr (s) + H2SO4 (aq) → K2SO4 (aq) + HBr (g)</p><p>With potassium bromide a redox reaction also occurs, as well as the above reaction. The Br- ions are oxidised to Br2 and the SO4 2- ions are reduced to SO2.&nbsp;</p><p>2Br- + 4H+ + SO4 2- → Br2 + SO2 + 2H2O</p><p>Bromide ions are better reducing agents than chlorine ions.&nbsp;</p><p></p><p>Iodide, I-&nbsp;</p><p>With potassium iodide other redox reactions also occur (as well as the reactions above). With KI, the I- ions are oxidised to I2 and the SO4 2- ions are reduced to S and H2S. </p><p>6I- + SO4 2- + 8H+ → 3I2 + S + 4H2O </p><p>SO4 2- + 10H+ + 8I- → 4I2 + H2S + 4H2O </p><p></p><p>When Br- ions react with concentrated H2SO4, sulfur is reduced from +6 to +4. </p><p>In a similar reaction using I- ions, the sulfur is reduced + 6 to -2. </p><p>Therefore I- halide has the stronger reducing action on concentrated H2SO4, as it shows the greatest extent of reduction.</p><p></p><p>I- &gt; Br- &gt; Cl- </p><p>A reducing agent loses electrons in a reaction. </p><p>The I- ions has the biggest ionic radius and the most amount of shielding so the attraction between the positive nucleus and outermost e- is weaker so the e- is more easily lost.&nbsp;</p>
11
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Understand the following reactions:

Precipitation reactions of the aqueous anions Cl-, Br- and I- with aqueous silver nitrate solution, followed by aqueous ammonia solution

  1. Add a few drops of nitric acid (aq) to the solution being tested

  • This removes any other ions that could give a precipitate with silver nitrate (aq)

  1. Add silver nitrate (aq) dropwise to the solution being tested 

  • this produces a ppt for Cl-, Br- and I- ions 

  1. Add ammonia (aq) (dilute + conc) to the ppt 

  • this is used to see if the ppt re-dissolves to help confirm their identity.

<ol><li><p>Add a few drops of nitric acid (aq) to the solution being tested </p></li></ol><ul><li><p>This removes any other ions that could give a precipitate with silver nitrate (aq) </p></li></ul><ol start="2"><li><p>Add silver nitrate (aq) dropwise to the solution being tested&nbsp;</p></li></ol><ul><li><p>this produces a ppt for Cl-, Br- and I- ions&nbsp;</p></li></ul><ol start="3"><li><p>Add ammonia (aq) (dilute + conc) to the ppt&nbsp;</p></li></ol><ul><li><p>this is used to see if the ppt re-dissolves to help confirm their identity.</p></li></ul><p></p>
12
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Understand the following reactions:

Hydrogen halides with ammonia and with water (to produce acids)

Reaction with ammonia: 

  • if a hydrogen halide gas and ammonia gas are mixed, a white cloud of the ammonium halide appears

  • N.B. This is NOT a gas, it is tiny solid airborne particles which eventually settle as dust.

  • NH3 (g) + HCl (g) → NH4Cl (s)

  • This can be used as a test for a hydrogen halide - but it will not show which halogen is present

<p>Reaction with ammonia:&nbsp;</p><ul><li><p>if a hydrogen halide gas and ammonia gas are mixed, a white cloud of the ammonium halide appears</p></li><li><p>N.B. This is NOT a gas, it is tiny solid airborne particles which eventually settle as dust.</p></li><li><p>NH3 (g) + HCl (g) → NH4Cl (s)</p></li><li><p>This can be used as a test for a hydrogen halide - but it will not show which halogen is present </p></li></ul><p></p>
13
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Be able to make predictions about fluorine and astatine and their compounds, in terms of knowledge of trends in halogen chemistry

fluorine - pale yellow gas

astatine - dark black solid

14
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The reaction of halogens with non-metals

  • with non-metals, such as phosphorus, halogens react to form covalent halides

  • ¼ P4 (s) + 3/2 Cl2 (g) → PCl3 (l)

  • The Cl changes from 0 to -1 therefore it is reduced and is acting as the oxidising agent

  • The P changes from 0 to +3 therefore it is oxidised and is acting as the reducing agent

15
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Describe properties of the hydrogen halides:

  • all halogens form covalently bonded compounds with hydrogen

  • at room temp they are colourless gases that fume in moist air

  • all hydrogen halides are simple molecules therefore not much energy is needed to overcome the weak intermolecular forces

  • they are extremely soluble in water

  • - this is partly because they are polar molecules and water is a polar solvent

  • however it is mainly because in aqueous solution the molecules fully dissociate into ions, which then become hydrated, releasing lots of heat energy (very exothermic)

  • HX + (aq) → H+ (aq) + X- (aq)

  • the presence of H+ ions means that solutions of the hydrogen halides are acidic

  • the acidic character of hydrogen halides means they can react with bases, for example, ammonia and potassium or sodium hydroxides.

  • group 1 halides are ionic compounds

  • they are white crystalline solids, soluble in water giving colourless solutions