Proof

0.0(0)
studied byStudied by 0 people
full-widthCall with Kai
GameKnowt Play
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
Card Sorting

1/6

encourage image

There's no tags or description

Looks like no tags are added yet.

Study Analytics
Name
Mastery
Learn
Test
Matching
Spaced

No study sessions yet.

7 Terms

1
New cards

What are all the different types of proof?

Direct proof, proof by contraposition, proof by contradiction, non-constructive proof, constructive proof, proof by cases/exhaustion

2
New cards

What is direct proof?

Start with your assumptions and directly deduce your conclusions. e.g.

Theorem 2.1.

If m and n are odd integrers, then mn is also odd.

Proof:

Since m and n are odd integers, there are integers j and k such that m = 2j + 1 and n = 2k+1 . But then mn = (2j +1)(2k+1) = 2(2jk+j +k)+1 . Since (2jk+j +k) is an integer, we see that mn is odd.

3
New cards

What is proof by contraposition?

The statement ‘if P, then Q ’ is equivalent to the statement ‘if not Q, then not P.’ It is sometimes easier to prove the contrapositive.

Theorem 2.2.

Let n be an integer. If n2 is even, then n is even.

Proof.

Suppose that n is not even. Then n is odd. Letting n = m in Theorem 2.1, we see that nm = n2 is odd. Hence if n is not even, n2 is not even. Thus if n2 is even, n is even.

4
New cards

What is proof by contradiction?

We assume some statement to be true and then show that this implies a contradiction or absurdity, which implies that the statement must be false.

Theorem 2.3.

The square root of 2 is irrational.

Proof.

Suppose that √2 is rational. Then there are integers p and q such that √2 = p/q. By cancelling common factors, we may assume that p and q have no common factors. Since q√2 = p , we see that p2 = 2qis even. By Theorem 2.2, it follows that p is even

and there is some integer r such that p = 2r . But then 2q2 = p2 = (2r)2 = 4r2, so that q2 = 2ris even. However, if p and q are both even, then they have a common factor of 2. This contradicts the fact that they have no common factor. Hence, √2 is not rational.

5
New cards

What is a non-constructive proof?

In a non-constructive proof, we conclude that something must be true by showing that a particular thing must exist, without being able to give an explicit instance of that thing. The most famous (and controversial) example is Cantor’s proof that the real numbers are uncountably infinite. Here we present an example due to Dov Jarden from the 1950s.

Theorem 2.4.

An irrational number to an irrational power can be rational.

Proof.

By Theorem 2.3, √2 is irrational. If √2√2 is rational then we are done. If √2√2 is irrational, then (√2√2)√2 = √2√2√2 = √2= 2 is rational.

Notice that in this proof we do not know whether the example of an irrational power of an irrational being rational is √2√2 or (√2√2)√2.

6
New cards

What is a constructive proof?

In a constructive proof, we explicitly come up with instance showing that something is true. For example, e and log 2 are both irrational and by definition elog2 = 2 , which proves Theorem 2.4. However, proving that e is irrational is non-trivial. Here is an alternative constructive proof. First we need a lemma.

Lemma 2.5.

The number log2 9 is irrational.

Proof.

Suppose that log2 9 is rational, so that there are non-zero integers p and q such that log2 9 = p/q . By the definition of log2, 2p/q = 2log2 9 = 9 . This implies that 2p = 9q. However, a similar proof to that of Theorem 2.1 shows that 9q is odd, where as 2p

is even. This contradiction implies that log2 9 must be irrational.

We now have a constructive proof of Theorem 2.4:

Proof.

From the above, √2 and log29 are both irrational, but √2log2 9 = √2

log2(9) = √22 log2 32log2 3 = 3

7
New cards

What is proof by cases/exhaustion?

Work through every case