CHE2A EXAM 1 REVIEW (ch1-4)

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72 Terms

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Scientific method
A logical, systematic approach to the solution of a scientific problem
A logical, systematic approach to the solution of a scientific problem
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Natural law
explains what happens
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theory
explains WHY something happens
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Density =
mass/volume
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Kelvin =
273 + C
273 + C
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Farenheit =
9/5(C) + 32
9/5(C) + 32
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Celcius =
(F-32) x 5/9
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Common Conversions
0°C = 273.15 K
1 in = 2.54 cm
1 mL = 1 cm^3
1 bar = 100 kPa
1 atm = 101.325 kPa
760 torr = 1 atm
1 mol = 6.022 x 10^23 particles
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Rules for sig figs (multiplication/division)
use number of sig figs of least sig fig number

ex. *1.4* x 5.376 = 7.5
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Rules for sig figs (addition/subtraction)
use number of decimal places as number w/ least decimal places

ex. 1.30 x *2.7* = 3.5
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law of conservation of mass
total mass of substances present after a chemical reaction is the same as the total mass of substances before the reaction
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law of definite proportions
(law of constant composition)
all samples of a compound have the same composition
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law of multiple proportions
If 2 elements combine to form different compounds, the ratio of masses of the second element that react with a fixed mass of the first element will be a simple, whole-number ratio
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isotopes
Atoms of the same element that have different numbers of neutrons
Atoms of the same element that have different numbers of neutrons
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number of protons defines ...
the element (atomic number)
the element (atomic number)
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number of neutrons defines ...
isotopes, mass of element (protons + neutrons)
isotopes, mass of element (protons + neutrons)
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number of electrons defines ...
charge of element
charge of element
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molecular formula
shows the types and numbers of atoms combined in a single molecule of a molecular compound
shows the types and numbers of atoms combined in a single molecule of a molecular compound
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empirical formula
The simplest whole number ratio of atoms of each element in a compound
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Where are *alkali metals* located on the periodic table?
Column 1
Column 1
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Where are *alkaline earth metals* located on the periodic table?
Column 2
Column 2
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Where are *transition metals* located on the periodic table?
Columns 3-12
Columns 3-12
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Where are *chalcogens* located on the periodic table?
Column 16
Column 16
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Where are *halogens* located on the periodic table?
Column 17
Column 17
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Where are *noble gases* located on the periodic table?
Column 18
Column 18
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Where are *the main groups* located on the periodic table?
Column 1, 2, 13-18
Column 1, 2, 13-18
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What are *periods* on the periodic table?
horizontal rows
horizontal rows
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Where are *nonmetals* located on the periodic table?
Metals = left of staircase
Nonmetals = right of staircase
Metals = left of staircase
Nonmetals = right of staircase
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9 transition metals with uncertain charges
*+2 or +3 charges*
Cr (Chromium)
Fe (Iron)
Co (Cobalt)

*+1 or +2 charges*
Cu (Copper)
Ag (Silver)
Au (Gold)
Hg (Mercury)

*+2 or +4 charges*
Sn (Tin)
Pb (Lead)
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Oxygen common oxidation state
-2
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Hydrogen common oxidation state
+1
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Fluorine common oxidation state
-1
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Naming *covalent compounds*
between 2 nonmetals
= PREFIXES

ex. SF10 = Sulfur decafluoride
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Covalent compound prefixes
1: mono
2: di
3: tri
4: tetra
5: penta
6: hexa
7: hepta
8: octa
9: nona
10: deca
1: mono
2: di
3: tri
4: tetra
5: penta
6: hexa
7: hepta
8: octa
9: nona
10: deca
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Naming *binary ionic compounds (type 1)*
with a metal with specified charge
= full name cation, anion +ide

ex. CsF = Cesium Fluoride
with a metal with specified charge
= full name cation, anion +ide

ex. CsF = Cesium Fluoride
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Naming *binary ionic compounds (type 2)*
with a metal with UNspecified charge
= ROMAN NUMERALS

ex. FeO3 = Iron (III) Oxide
with a metal with UNspecified charge
= ROMAN NUMERALS

ex. FeO3 = Iron (III) Oxide
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Naming *acids (with NO oxygen)*
add hydro- and -ic

ex. HF = hydrofluoric acid
add hydro- and -ic

ex. HF = hydrofluoric acid
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Naming *acids (with oxygen)*
*for -ate endings*
= add - ic

ex. HClO3 = chloric acid

*for -ite endings*
= add -ous

ex. HClO2 = chlorous acid
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Charges of periodic table
knowt flashcard image
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Common polyatomic ions (MEMORIZE)
*NH4+ = ammonium*
NH3+ = ammonia
NO2- = nitrite
*NO3- = nitrate*
SO3 = sulfite (2- charge)
*SO4 = sulfate (2- charge)*
*OH- = hydroxide*
CN- = cyanide
*PO4 = phosphate (3- charge)*
*CO3 = carbonate (2- charge)*
C2H3O2- = acetate
MnO4- = permanganate
*CrO4 = chromate (2- charge)*
O2 = peroxide (2- charge)
ClO2- = chlorite
*ClO3- = chlorate*
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Polyatomic ion prefixes
per- = +1
-ate = __
-ite = -1
hypo- = -2
per- = +1
-ate = __
-ite = -1
hypo- = -2
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Atomis Mass =
*sum of [(isotopic masses) x (fractional abundance)]*

ex. 99.630% N-14 and .37% N-15 = (.99630)(14)+(.0037)(15) = 14.0037 u
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Molar Mass =
*sum of amount of grams per element in compound*

ex. Na2SO4 = 2(Na) + S + 4(O) = 2(22.99) + 32.07 + 4(16) = 142.05 g/mol
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Percent Mass =
*(mass of element ÷ mass of compound) x 100*

ex (using formula). CoCl2 x 6H2O find mass % of water
6(2.016+16) ÷ 237.93 g/mol x 100 = 45.44%

ex (using grams). 87.28 g P, 112.72 g O, 200g total compound
87.28 g P ÷ 200 g x 100= 43.64% P
112.72 g O ÷ 200 g x 100 = 56.36% O
*(mass of element ÷ mass of compound) x 100*

ex (using formula). CoCl2 x 6H2O find mass % of water
6(2.016+16) ÷ 237.93 g/mol x 100 = 45.44%

ex (using grams). 87.28 g P, 112.72 g O, 200g total compound
87.28 g P ÷ 200 g x 100= 43.64% P
112.72 g O ÷ 200 g x 100 = 56.36% O
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Combustion reaction
reaction where an organic compound (contains C, H, and sometimes others) reacts with O2 to create CO2 + H2O
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Combination reaction (synthesis)
2 or more species combine to form compound

*A + B --> AB*
2 or more species combine to form compound

*A + B --> AB*
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Decomposition reaction
compound decomposes into 2 or more species

*AB --> A + B*
compound decomposes into 2 or more species

*AB --> A + B*
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Single Replacement reaction
a chemical change in which one element replaces a second element in a compound

*AB + C --> A + BC*
a chemical change in which one element replaces a second element in a compound

*AB + C --> A + BC*
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Double Replacement reaction
a chemical change that involves an exchange of positive ions between two compounds

*AB + CD --> AD +BC*
a chemical change that involves an exchange of positive ions between two compounds

*AB + CD --> AD +BC*
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Redox reaction
A chemical reaction involving the transfer of one or more electrons from one reactant to another; also called oxidation-reduction reaction
A chemical reaction involving the transfer of one or more electrons from one reactant to another; also called oxidation-reduction reaction
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Limiting Reactant steps
1. Balance equation
2. Calculate moles or mass of reactants
3. Calculate moles/mass of opposite reactant that is produced from using each reactant
4. Smaller production = limiting reagant
5. Use moles/mass of limiting reagant to calculate product
6. To find excess: subtract available moles/mass of excess with used moles/mass of excess
1. Balance equation
2. Calculate moles or mass of reactants
3. Calculate moles/mass of opposite reactant that is produced from using each reactant
4. Smaller production = limiting reagant
5. Use moles/mass of limiting reagant to calculate product
6. To find excess: subtract available moles/mass of excess with used moles/mass of excess
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Percent Yield =
*actual yield ÷ theoretical yield x 100*

aka. given amount ÷ calculated amount x 100
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Molarity =
*moles of solute ÷ volume in liters*
*moles of solute ÷ volume in liters*
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Empirical Formula steps (from mass %)
1. base mass % out of 100 g of compound (each % = g)
2. Determine moles of each element
3. Divide each mole by smallest mole value
4. Whole number values = subscripts of each element in compound
1. base mass % out of 100 g of compound (each % = g)
2. Determine moles of each element 
3. Divide each mole by smallest mole value
4. Whole number values = subscripts of each element in compound
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Molecular Formula steps (from empirical formula)
*molar mass ÷ empirical formula mass* = factor to multiply subscripts by
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Dilution =
*Molarity (M1) x Volume (V1) = Molarity (M2) x Volume (V2)*

ex. 1 L of 11.75 M HCl reacts with 2 L NaOH, find molarity NaOH
(11.75 M)(1 L) = (M2)(2 L) = M2 = 5.9 M NaOH
*Molarity (M1) x Volume (V1) = Molarity (M2) x Volume (V2)*

ex. 1 L of 11.75 M HCl reacts with 2 L NaOH, find molarity NaOH
(11.75 M)(1 L) = (M2)(2 L) = M2 = 5.9 M NaOH
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Titration =
(molarity of subject) (volume of subject) = (molarity of titrant) (volume of titrant)
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Strong electrolytes
completely dissociate into ions when dissolved in water

- strong acids (aq)
- strong bases (aq)
- ionic compounds (aq)
- salts (aq)
completely dissociate into ions when dissolved in water

- strong acids (aq)
- strong bases (aq)
- ionic compounds (aq)
- salts (aq)
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Weak electrolytes
don't completely disassociate in water

- weak acids
- weak bases
- molecular compounds
- organic compounds
- liquids
- solids
- gases
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Precipitate reactions
reactions that result in the formation of an insoluble product (precipitate)

molecular formula:
ex. AgNO3 (aq) + KCl (aq) --> AgCl (s) + KNO3 (aq)
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Precipitate reactions: Net ionic equation
ionic equations that include only the particles that participate in the reaction (no spectator ions)

ex. HCl(aq) + NaOH(aq) --> NaCl(aq) + H2O (l)
full ionic equation:
H+ + Cl- + Na+ + OH- --> 2H+ + Cl- + Na+ + OH-
net ionic equation:
*H+(aq) + OH-(aq) --> H2O(l)*
ionic equations that include only the particles that participate in the reaction (no spectator ions)

ex. HCl(aq) + NaOH(aq) --> NaCl(aq) + H2O (l)
full ionic equation:
H+ + Cl- + Na+ + OH- --> 2H+ + Cl- + Na+ + OH-
net ionic equation:
*H+(aq) + OH-(aq) --> H2O(l)*
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What is an acid?
compound that provides H+
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What is a base?
compound that provides OH-

- NOT including compounds that do not contain a metal in addition to OH- (not CH3OH, not MeOH)
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Strong Acids (MEMORIZE)
- HCl
- HBr
- HI
- HClO4
- HClO3
- HNO3
- H2SO4
- HCl
- HBr
- HI
- HClO4
- HClO3
- HNO3
- H2SO4
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Strong Bases (MEMORIZE)
- LiOH
- NaOH
- KOH
- RbOH
- CsOH
- Ca(OH)2
- Mg(OH)2
- Sr(OH)2
- Ba(OH)2
- LiOH
- NaOH
- KOH
- RbOH
- CsOH
- Ca(OH)2
- Mg(OH)2
- Sr(OH)2
- Ba(OH)2
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redox reactions (oxidation-reduction reactions)
chemical reactions that transfer electrons between reactants

- oxidized = loses electrons (reducing agent - electron donor)
- reduced = gains electrons (oxidizing agent - electron acceptor)
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remember OIL RIG
*O*xidation *I*s *L*osing electrons
*R*eduction *I*s *G*aining electrons
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Half reactions
equations that show either oxidation or reduction alone
equations that show either oxidation or reduction alone
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Half reaction balancing steps
1. elements (not H2O)
2. oxygen (use H2O)
3. hydrogen (use H+)
4. charge (use electrons)
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Half reactions: reduction
ex. SO2 + Cr2O7 (-2) ---> SO4 (-2) + Cr (+3) + H2O
1. reduction equation: Cr2O7 (-2) ---> 2Cr(+3)
ox states: Cr went from +6 to +3 (gained 3 electrons - reduced)
2. balance oxygen
Cr2*O7* (-2) ---> 2Cr(+3) + *7H2O*
3. balance hydrogen
Cr2O7 (-2) + *14H+*---> 2Cr(+3) + *7H2*O
4. balance charges
Cr2O7 (-2) + 14H+---> 2Cr(+3) + 7H2O
(Cr2 = +12 to 2Cr(+3) = +6) 12-6 = add 6 electrons to left

Cr2O7 (-2) + 14H+ + *6e* ---> 2Cr(+3) + 7H2O
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Half reactions: oxidation
ex. SO2 + Cr2O7 (-2) ---> SO4 (-2) + Cr (+3) + H2O
1. oxidation equation: SO2 ---> SO4(-2)
ox states: S went from +4 to +6 (lost 2 electrons - oxidized)
2. balance oxygen
SO2 + *2H2O* ---> S*O4*(-2)
3. balance H+
SO2 + *2H2*O ---> SO4(-2) + *4H+*
4. balance charge
SO2 + 2H2O ---> SO4(-2) + 4H+
(S=+4 to S=+6) so, 4-6 = add 2 electrons to right

SO2 + 2H2O ---> SO4(-2) + 4H+ + *2e*
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Half reactions: adding reduction and oxidation
reduction: Cr2O7 (-2) + 14H+ + 6e ---> 2Cr(+3) + 7H2O
oxidation: SO2 + 2H2O ---> SO4(-2) + 4H+ + 2e

Cr2O7 (-2) + 14H+ + 6e + SO2 + 2H2O ---> 2Cr(+3) + 7H2O + SO4(-2) + 4H+ + 2e

14H+/4H+ cancels, 6e/2e cancels, 7H2O/2H2O cancels

*Cr2O7 (-2) + 10H+ + 4e + SO2 ---> 2Cr(+3) + 5H2O + SO4(-2)*