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What is a buffer
A solution that resists changes in pH when small amounts of acid or base are added
Components required for a buffer
A weak acid and its conjugate base, or a weak base and its conjugate acid
Example of an acid buffer
Acetic acid and sodium acetate
Example of a basic buffer
Epinephrine and epinephrine HCl
Identify if a solution is a buffer
Must contain a weak acid and its salt OR a weak base and its salt
Identify non-buffer solution
Contains strong acid/base or does not contain conjugate pairs
Why strong acids cannot form buffers
They fully dissociate and cannot establish equilibrium
Why strong bases cannot form buffers
They fully dissociate and cannot establish equilibrium
Write the buffer equation for a weak acid and its salt
pH = pKa + log([salt]/[acid])
Write the buffer equation for a weak base and its salt
pH = pKw – pKb + log([base]/[salt])
When to use acidic Henderson–Hasselbalch equation
When system has a weak acid + conjugate salt
When to use basic Henderson–Hasselbalch equation
When system has a weak base + conjugate salt
What is the pKa of acetic acid used in the example
4.76
In 100 mL of 0.1 M acetic acid, how many moles are present
0.01 moles
Calculate sodium acetate needed for pH 5.2 buffer
0.0273 moles in 100 mL
What happens when acid is added to acetic acid/sodium acetate buffer
Acetate ion neutralizes H₃O⁺ (acid) to form acetic acid
What happens when base is added to acetic acid/sodium acetate buffer
Acetic acid reacts with OH⁻ (base) to form acetate + water
What is the pH of an ephedrine/ephedrine HCl buffer (ratio 10, pKb 4.64)
pH = 10.36
When buffer capacity is highest
When pH = pKa
Buffer capacity definition (β)
Amount of acid or base needed to change pH by one unit per liter of buffer
What is the buffer capacity of blood
0.025 moles/L per pH unit
Why pharmaceutical buffers should have low buffer capacity
To minimize irritation and avoid altering physiological pH
Why parenteral and ophthalmic solutions should be minimally buffered
To prevent irritation due to high buffer capacity
Physiological buffer examples
Bicarbonate, phosphate, and protein buffers
What physiological buffers exist in blood
Hemoglobin/oxyhemoglobin and NaHCO₃/H₂CO₃
What buffers the eye’s lacrimal fluid
Natural buffer system with high capacity around pH 7.4
Why buffer capacity and volume are important
They determine pH changes when added to body fluids
When buffers should not be used
When large capacity may alter physiological pH (e.g., injections)
Preferred pH range for parenteral solutions
Near physiological pH (≈ 7.4)
State one way to reduce irritation from buffers
Avoid large pH differences from physiological fluids
What does a high buffer capacity mean
Buffer strongly resists pH change; may cause irritation in vivo
What does a low buffer capacity mean
Buffer easily changes pH; preferred for injections and ophthalmics
Main buffer system in the body
Carbonic acid/bicarbonate (H₂CO₃/NaHCO₃)
Strong electrolyte definition
Completely dissociates in water (e.g., HCl, NaOH)
Weak electrolyte definition
Partially dissociates (e.g., weak acids, weak bases)
Non-electrolyte definition
Does not dissociate (e.g., sugars, alcohols)
Salt of strong acid + strong base
Produces neutral solution (pH ~ 7)
Salt of strong acid + weak base
Produces acidic solution
Salt of weak acid + strong base
Produces basic solution
Salt of weak acid + weak base
pH depends on Ka vs Kb
Irritation caused by buffer mismatch
pH far from physiological pH causes burning/stinging
Effect of adding strong acid to buffer
Buffer neutralizes H⁺ with minimal pH change
Effect of adding strong base to buffer
Buffer neutralizes OH⁻ with minimal pH change
What determines the pH of a buffer
The ratio of salt to acid (or base to salt)
If acid concentration > salt concentration
pH < pKa (more acidic)
If salt concentration > acid concentration
pH > pKa (more basic)
Buffer region definition
pH = pKa ± 1
Blood pH normal range
7.35–7.45
pKa definition
pH at which an acid is 50% dissociated
Using pKa to choose a buffer
Choose an acid with pKa near target pH
Kw expression
[H⁺][OH⁻] = 1 × 10⁻¹⁴
Relation between pKa and Ka
pKa = –log(Ka)
Relation between pKb and Kb
pKb = –log(Kb)
Relation between pKa and pKb
pKa + pKb = 14