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MBB2
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The single sample z-test
we saw in our module that we can calculate a z-score for our sample mean to determine if it is expected or unusual, assuming the null hypothesis is true
z= M - u/ sigmam
where: z = the z-score for our sample mean; M = our sample mean; u= population mean; and sigmam= standard error of the mean. Note that population standard deviation is known
Population vs Sample Standard Deviation
However, population standard deviation is rarely known
In instances when we don’t know the population standard deviation, we can’t use a z-test and the normal distribution to assess our sample mean. That’s okey! Instead, we can use a t-test and the ‘t-distribution’
We use sample standard deviation as an estimate of population standard deviation. Single sample t-tests and z-tests are very similar otherwise
z-test vs t-test
z-test standard error ( we know sigma)
sigmam=sigma/sqareroot(n)
z-test formula
z=M-u/sigmam
t-test standard error (we estimate sigma with s)
sM=s/sqareroot(n)
t-test formula
t=M-u/sM
z-test vs t-test
Almost all aspects of the process are the same when conducting either a single sample t-test or z-test
We still use Null Hypothesis Significance Testing.
We still assign a value that indicates no effect to the null hypothesis, and proceed assuming the null is true
We still apply an alpha level of 5% and determine the probability of our mean occurring. The result determines whether the null hypothesis is rejected or not
One difference about the t-distribution
In the t-distribution, the critical limit corresponding to our alpha level of 5% will not be fixed at ± 1.96 as it was with the z-test and normal distribution
Instead, the t-distribution requires that we consider sample size and degrees of freedom (df), when determining the probability of the sample mean.
Degrees of Freedom are one less than our sample size for a single sample t-test (n-1)
The central limit varies along with df
Example: Does Head injury Affect IQ?
Imagine that we have a sample of 10 people with an acquired head injury. Has IQ been affected
The null hypothesis would be that head injury has not affected IQ. H0:u=100
Sample data: M= 94.20, s= 6.16, n= 10
Let’s calculate a t-score for our sample mean
t= M-u/sM
The probability of our sample mean occurring is low. Reject the null hypothesis
This evidence suggests that the population of people with this acquired brain injury have lower IQ