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adding OH- to solution
reduces amount of H+, which will cause a shift on the side with H+
adding more solids don’t change the equilibrium
GAS or AQUEOUS moles
*may speed up the reaction?? double check??
when adding something to a reversible reaction at equilibrium,
it will not be completely “used up”
the amount goes up, decreases a little as it is used up, but more remains than originally at equilibrium
when removing something from a reversible reaction at equilibrium,
it won’t be completely replenished by shift
there will be less than the amount at the original equilibrium
cooling a reversible reaction shifts
toward the exothermic direction
heating a reversible reaction shifts
towards the endothermic reaction
if ΔH is on the product side
endothermic reaction is reverse, exothermic reaction is forward
if ΔH is on the reactant side
exothermic reaction is reverse, endothermic reaction is forward
K changes IF
TEMPERATURE changes
shift right w/ temp change
K increases
shift left w/ temp change,
K decreases
adding water to an aqueous system at equilibrium will
increase volume, shift to make more moles of solution
endothermic
product energy >> reactant energy
exothermic
reactant energy >> product energy
catalysts
do NOT affect equilibrium position, only speeds up the process of getting to the equilibrium
“flattens” the hill on curve, less energy needed
circle states of matter before you start!!!!
!!!!!
law of mass action
reaction rate is proportional to the product of the molar concentrations of the reactants, each raised to its coefficient
Kc
only gases and aqueous systems can have molarity
Kp
MUST be in atm
particle equilibrium
replace M with number of particles of each reactant/product
SOLIDS
may participate in ice charts, but NO molarities or atm
catalyst justification
catalysts don’t change equilibrium, they just speed up the process of getting to it
equally speed up both forward and reverse rates
lowers activation energy for both sides by the same amount
NO LIQUIDS!!! NO GASES!!!
while adding an inert gas will increase total pressure
no impact on partial pressures
equilibrium constant
NO correlation with speed of a reversible reaction, only forward/reverse rates
particle equilibrium
visually at equilibrium when respective numbers of particles stay the same
changes in pressure because of changes of volume & partial pressures
if pressure increases by decreasing volume of container, system responds by shifting to the side with fewer moles of gas, reducing the number of gas particles
Kp remains constant
adding inert gas at constant volume
no changes to partial pressures
*IF K DOESNT CHANGE, PARTIAL PRESSURES REMAIN THE SAME bc no change in temp
*if pressure remains constant, adding inert gas will decrease partial pressures
aqueous systems & pressure changes
NOTHING!! BC ITS AQUEOUS AND DISSOLVED IN WATER
increasing the pressure of a liquid does not change its volume!!!
be wary of states of matter!! always!!!!
!!!!
adding water to an aqueous system without water as a reactant or product
water dilutes all species equally, decreasing all concentrations
in order to maintain K value, equilibrium must shift towards the side with more moles of solute