EE115 Q2 Flashcards on Voltage, Feedback Networks, and Diode Circuits

This type of diode has the lowest turn-on voltage

Schottky Diode

This type of diode has the lowest reverse breakdown voltage:

Zener Diode

It is known that the reverse breakdown observed in Zener diodes is due to two independent physical phenomena - avalage multiplication and Zener breakdown. Diodes with this VZ exhibit both:

The forward ON voltage of a diode is assumed (in the CVD approximation) between 0.6V and 0.7V typically. This implies that the diode is made of this type of a semiconductor material:

Silicon

All semiconductor diodes can be biased in reverse breakdown - just some are designed to have very high VZ. Typically,

which of the two, light-emitting diode (LED) or Photodiode (PD), has the lower reverse breakdown.

LED

The KVL relation written for a Voltage-Resistor-Diode loop is an equation of the following type:

Vsource = Vresistor + Vdiode

In a diode-based voltage limiter the output voltage is taken across this device:

Zener diode

In a diode-based rectifier circuit the output voltage is taken across this device:

load resistor

The peak-to-peak value of a voltage sinusoid with RMS value of 71 VRMS is approximately

2(2^(1/2)) 71 = 200V

Voltage sinusoid with an amplitude of 100Vp undergoes half-wave rectification. The peak-to-peak value of the resulting waveform is that many volts:

100V

Voltage sinusoid with an amplitude of 100Vp is half-wave rectified. The RMS value of the resulting waveform is that many VRMS:

Vrms = Vp/2 = 100/2 = 50V

Voltage sinusoid with an amplitude of 100Vp is full-wave rectified. The RMS value of the resulting waveform is that many VRMS:

Vrms = Vp*2 ^(-1/2) = 70.7 V

3.9V Zener diode is biased in breakdown using 10V supply and 510Ω. The current conducted by the Zener is approximately:

Is = (Vs-Vz)/R = 6.1/510 = 12mA

3.9V Zener diode is biased in breakdown using 10V supply and 510Ω. If a 680Ω load is attached in parallel to the Zener, the diode current will be approximately:

17.7mA

A voltage divider made of 10k and 1.1k drives the anode of a diode; the cathode is attached to GND and the diode appears in parallel to the 1.1k. It takes approximately that many volts at the input to turn ON the diode:

7.06V

Increasing the voltage supply to a bilateral switch IC has this impact to the ON-state resistance of the switches:

reduces resistance of the switches

A bilateral switch is closely related to this type of a logic gate:

Transmission gate

The logic function A ⋅ B + C can be implemented using that many switches and resistors:

2 switches 1 resistor

The switch network implementing the logic function A ⋅ B + C has that many switches connected in series.

2 switches in series

The Vh2l input trigger point of a comparator has lower value than its Vl2h trigger. The comparator type must be:

Schmitt Trigger Comparator (in hysteresis)

20k and 10k form the feedback network of an inverting hysteretic comparator. If the 20k connects the "+" terminal and the output, and the circuit is operating from dual tracking ± 10V the input trigger levels are approximately:

Vtl = 3.3V; VtH = -3.3V

20k and 10k form the feedback network of a non-inverting hysteretic comparator. If the 20k connects the "+" terminal and the output, and the circuit is operating from dual tracking ± 10V the input trigger levels are approximately:

Vtl = - 3.3V; VtH = 3.3V

20k and 10k form the feedback network of an inverting amplifier. If the 20k connects the "-" terminal to the output the close-loop gain of the amplifier is approximately:

-2

20k and 10k form the feedback network of a non-inverting amplifier. If the 20k connects the "-" terminal to the output the close-loop gain of the amplifier is approximately:

3

20k and 10k form the feedback network of an inverting amplifier; the 20k connects the "-" terminal to the output. If the input voltage is 1V in input current is approximately:

ideally 0/ .1 mA

20k and 10k form the feedback network of an non-inverting amplifier; the 20k connects the "-" terminal to the output. If the input voltage is 1V in input current is approximately:

ideally 0/ .1 mA

The so-called "virtual ground" refers to this op-amp terminal and this amplifier configuration:

inverting/noninverting op amp w/ feedback to negative terminal (0 volt at "-" terminal)

Two-input summing amplifier archives the following input-output relation: Vout = −2vi − 5vi2. If the feedback resistor is 10k the input resistors must have these values:

5k and 2k Ohms

Designer needs to deliver 25mW into 1k load. If the VTh of the input source is 100mVRMS she must implement a non-inverting amplifier with this close-loop voltage gain:

50

Sinusoid with 100mVRMS is applied to the input an amplifier with gain of 30 mV/mV. This is the minimum allowable supply voltage:

6.23