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P(E or F) = P(E) + P(F) - P(E and F)
Prob of E or F happening
P(E and F) = P(E) × P(F)
Prob of two events happening
Prob of one event and then another
(Independant Events)
With Replacement
P(E and F) = P(E) × P(F\E)
Prob of one event and then another
(Dependant Events)
Without Replacement
P(E^c) = 1−P(E)
Used when the prob of E is Difficult to find
Also when doing at least
P(E\F) = P(E and F) / P(E)
Prob of F given that E has occured
p × q × r …
How many different ways a sequence of events can happen
nPr = n! / (n-r)!
How many different ways a subset r,
can be taken from n distinct items
where the order matters (no repetitions)
nCr = n! / r!(n-r)!
How many different ways a suubset r,
can be taken from n distinct irems where
the order does’t matter (no repetitions)
n! / (n₁! n₂! ... n_k!)
Number of ways a set, n, that has
subsets non-distinct items can be arranged