Chemistry - 3.2.3 Group 7, the halogens

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7 Terms

1
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Describe and explain the general trend in atomic radius across Period 3?

• Atomic radius decreases across the period (1)
• Nuclear charge increases (1)
• Same shielding → stronger nuclear attraction (1)

2
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Compare and explain the differences between the reactions of H2SO4 with NaCl, NaBr and NaI

• NaCl + H₂SO₄ → HCl (acid-base, not redox) (1)
• NaBr + H₂SO₄ → HBr, then Br₂ + SO₂ (1)
• NaI + H₂SO₄ → HI, then I₂ + H₂S/S/SO₂ (1)
• Trend: Halide reducing power increases down group (1)

3
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Halogens are used in disproportionation reactions with both water and cold, dilute sodium hydroxide. Compare the reactions, giving balanced equations, and state the uses of the products formed.

• With water: Cl₂ + H₂O → HCl + HClO (1)
• With cold NaOH: Cl₂ + 2NaOH → NaCl + NaClO + H₂O (1)
• Both are disproportionation (1)
• NaClO/HClO used as bleach/disinfectant (1)
• NaCl formed as a by-product (1)

4
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Explain the variation in first ionisation energy across Period 3 from sodium to argon.

• General increase across period (1)
• Increased nuclear charge, same shielding (1)
• Dip at Al: 3p electron higher energy than 3s (1)
• Dip at S: paired electrons in 3p repel (1)

5
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Explain why the first ionisation energy of aluminium is lower than that of magnesium.

• Al electron removed from 3p orbital (1)
• 3p higher in energy than 3s (1)
• Easier to remove → lower ionisation energy (1)

6
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Explain why the reaction between sodium iodide and concentrated sulfuric acid produces a bad smell and a yellow solid. Write equations to support your answer.

• NaI + H₂SO₄ → HI + NaHSO₄ (1)
• HI reduces H₂SO₄ → H₂S + S + I₂ (1)
• Yellow solid = sulfur (1)
• Bad smell = H₂S (1)

7
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Describe and explain the trend in reducing power of the halide ions down the group.

• Reducing power increases down group (1)
• Ions larger with more shielding (1)
• Electron lost more easily (1)
• Attraction between nucleus and outer electrons weaker (1)