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The vector u results when a vector u-v is added to the vector v
True, adding the vectors algebraically gives you this.
An example of a linear combination of vectors v1 and v2 is the vector (1/2)v1
True, a linear combination has the form c1v1+c2v2. Choosing scalars c1=1/2 and c2=0 yields (1/2)v1+0v2=(1/2)v1
The solution set of the linear system whose augmented matrix is [a1 a2 a3 b] is the same as the solution set of the equation x1a1+x2a2+x3a3=b.
True, both statements express identical constraints on the variables x1, x2, x3.
The equation Ax=b is referred to as a vector equation
False, it is referred to as a matrix equation. A vector equation is written in linear combination form, such as x1a1+x2a2+…+xnan=b
If the equation Ax=b is inconsistent, then b is not in the set spanned by the columns of A.
True, the span of the columns of A consists of all vectors that can be written as Ax. If Ax=b has no solution/is inconsistent, b cannot be formed as a linear combination of A’s columns, meaning b is not in the span (columns of A).
If A is an mxn matrix whose columns do not span R^m, then the equation Ax=b is inconsistent for some b in R^m.
True, the columns of A span R^m iff Ax=b has a solution for every b ∈ R^m.
A homogeneous equation is always consistent
True, a homogeneous equation Ax=0 always has at least one solution, namely the trivial solution x=0, because A(0)=0
If x is a nontrivial solution of Ax=0, then every entry in x is nonzero
False, a nontrivial solution merely requires x to not be equal to 0 (at least one entry is nonzero). Other entries in x are permitted to be zero (ie. x = the column of [1 0])
The equation Ax=b is homogenous if the zero vector is a solution
True, substituting x=0 into Ax=b gives A(0)=b, which simplifies to b=0. An equation of the form Ax=0 is homogeneous by definition.
The solution set of Ax=b is obtained by translating the solution set of Ax=0.
False, this is only true when Ax=b is consistent/has one solution. If Ax=b has no solutions, its solution set is the empty set, which cannot be obtained by translating the solution set of Ax=0.
Any column of A always belongs to the span of A’s columns
True
m x n = row x column
True (# of rows x # of columns)
The columns of an mxn matrix span R^m iff every row has a pivot position in echelon form
True
A system has a non-trivial solution when…
there’s at least one free variable (column without a pivot)