1/8
From Maths Unplugged's Crash Course video on Permutations and Combinations! Question Mode: Flashcards only. Answer mode: Answer with Definition. Good luck!
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^nC_{n-r}
^nC_r
^nC_0
1
^nC_n
1
^nC_1
n
\dfrac{^nC_r}{^nC_{r-1}}
\dfrac{n-r+1}{r}
\dfrac{n}{r}\ ^{n-1}C_{r-1}
^nC_r
^nC_r + ^nC_{r+1}
^{n+1}C_{r+1}
^{n+1}C_{r+1}-^nC_{r+1}
^nC_r
^nC_x=\ ^nC_y \implies
either x=y or x+y=n