Ch. 2 Electrostatics

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20 Terms

1
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force of gravity formula

gravitational constant: 6.67 × 10^-11 Nm²/kg²

<p>gravitational constant: 6.67 × 10^-11 Nm²/kg²</p>
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coulomb’s law

k=9.0 × 10^9 NR²/C²

<p>k=9.0 × 10^9 NR²/C²</p>
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r-r’

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Electric Field of a Point Charge

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Force of a Charge

Fq=qE

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Electric Fields of Continuous Distributions

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Electric Flux Formula

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Gaussian Surface

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Gauss’s Law

∇⋅E=ρ/ε₀

<p>∇⋅E=ρ/ε₀</p>
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Insulating & Conducting Surfaces

Qenc=σA

Insulating Surface: σ/2ε₀

Conducting Surface: σ/ε₀

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Electric Potential

V(xo)-V(xa)=kQ/rb-kQ/ra)=-∫(xa→xb) E⋅dl

  • as long as xa/=xb, then this formula is path independent

  • if xa=xb, then E⋅dl = 0

  • ∇x E =0, the curl of an electric field vanishes when it is a possible electric field

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Electric Potential due to a Point Charge

V=kQ/r

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Electric Field & Electric Potential Relation

E=-∇V

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Volt → Energy Conversion

1 Volt = 1 Joule/Coulomb

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Electric Potential due to Continuous Distribution

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Work due to Electric Potential

W=qV

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sum of charge distribution

W=Q²/8πε₀²R=1/2∫ρVdτ

U=(ε₀/2)E²

<p>W=Q²/8πε₀²R=1/2∫ρVdτ</p><p>U=(ε₀/2)E²</p>
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Laplacian of Electric Potential

∇²V=ρ/ε₀

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Relationship between Electric Field, Electric Charge, and Electric Potential

E=-∇V=k∫ρ(r’)/(r-r’)dτ

V=-∫E⋅dl=k∫ρ(r’)/(r-r’)dτ

ρ=-ε₀∇²V=ε₀(∇⋅E)

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Capacitors

Q=CV

C=ε₀A/d