4: mechanistic organic chem

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158 Terms

1
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what is the relationship between s/p character and reactivity?

higher s character = electrons held closer to the nucleus = less reactive

higher p character = electrons held further from the nucleus = more reactive

2
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draw the molecular orbital diagram from a carbonanion

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3
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describe the different hybridisations of carbon and their relative reactivities

the extent of p orbital contribution depends on the amount available i.e. alkynes have 2 p orbitals involved in triple bond.

2s + 2p(x) = 2 sp hybrid orbitals = linear

2s + 2 2p = 3 sp2 hybrid orbitals = trigonal planar

2s + 3 2p = 4 sp3 hybrid orbitals = tetrahedral

sp = 50% s 50% p = ~unreactive

sp2 = 33% s 66% p

sp3 = 25% s 75% p = ~reactive

4
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draw the arrangement of orbitals that gives rise to ∏ and sigma bonding

5
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how does the separation of filled and empty orbitals affect stabilisation?

small separation = good stabilisation

large seaparation = poor stabilisation

6
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what are the (main) conditions for orbital interaction?

  1. matched symmetry

  2. good overlap

  3. similar energies

7
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describe lewis acids and lewis bases in terms of orbitals

lewis base = donate electron density = high energy (unstable) HOMO

lewis acid = accept electron density = low energy (stable) LUMO

8
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explain why lewis adducts are so stable

lewis base = high energy HOMO

lewis acid = low energy LUMO

in conjunction, this minimise the minimise the orbital separation and increase stabilisation

9
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what is Bredit’s rule? explain

a double bond is not possible at the bridgehead of two small rings

= poot orbital overlap

<p>a double bond is not possible at the bridgehead of two small rings</p><p>= poot orbital overlap </p>
10
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<p>label this reaction coordinate diagram </p>

label this reaction coordinate diagram

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11
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define a transition state

= maxima on the reaction coordinate diagram

= partially formed bonds

= does not exist for finite time and cannot be isolated/observed

12
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define an intermediate

= exists between energy barriers in “well” on reaction coordinate diegram

= fully formed bonds

= isolatable/observable

13
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define the ΔG° for a reaction in terms of entropy/enthalpy

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14
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define the ΔG° for a reaction at equilibrium

defines the position of equilibrium

<p>defines the position of equilibrium </p>
15
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how does ΔG° control the spontaneity of reaction

-ve ΔG° favours the forward reaction and product formation

+ve ΔG° favours the backwards reaction and reactant formation

16
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how can ΔG° be altered?

-ve ΔH°:

  • stronger bonds forming (-ve H) than breaking (+ve H)

  • less strain in products than reactant

+ve ΔS°

  • increase in disorder is favoured

17
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describe how choice of polar solvent can favour products or reactants

polarity: reactants > products

  • polar solvent favours reactants

polarity: products > reactants

  • polar solvent favours products

polar solvents cluster around charges in reactants and products (solvation) so that charge is delocalised.

solvation = interactions formed = -ve H = favoured

18
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what are the two types of solvent?

protic

= contain O-H or N-H

= solvate +ve and -ve charges

aprotic

= do not contain O-H or N-H

= solvate only +ve charges

19
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describe the dielectric constant

= measure of polarity

large dielectric constant = polar

small dielectric constant = non-polar

= measure of ability to solvate charge

20
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examples of protic solvents

h2o, meoh, etoh, tbuoh, acoh

21
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examples of aprotic solvents

dmso, dmf, acn or mecn, dcm, thf, etoac, et2o

22
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draw the structure of DMSO

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23
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draw the structure of DMF

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24
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draw the structure of ACN/MeCN

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25
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draw the structure of THF

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26
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rank protic solvents in terms of solvation ability

H2O > MeOH > EtOH > tBuOH > AcOH (delocalised = weaker)

27
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rank aprotic solvents in terms of solvation ability

DMSO > DMF > ACN/MeCN > acetone > DCM > THF> EtOAc > Et2O

28
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what are the 4 types of solvent; describe each

polar protic = +ve & -ve = good solvation

polar aprotic = +ve = good solvation

apolar protic = +ve & -ve = poor solvation

apolar aprotic = +ve = poor solvation

29
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what is the rate determining step?

= step with largest activation energy

= determines the overall rate of reaction

30
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what does the rate of the RDS depend on?

  • number of collision between reacting molecules in a given period

  • fraction of collisions with sufficient energy for reaction

  • fraction of collisions with correct orientation for reaction

31
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describe the role of the RDS is determining the order of reaction

reactants involved prior to and in the RDS influence the rate of reaction.

reactants involved after the RDS will not influence the rate of reaction.

32
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describe the rate constant

fundamental property of a reaction

depends on:

  • temperature

  • pressure

  • solvent

  • DOES NOT DEPEND ON CONCENTRATION

33
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<p>give an equation for the ratio of product for the concurrent reactions described by the equations</p>

give an equation for the ratio of product for the concurrent reactions described by the equations

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34
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<p>define the rate of formation when:</p><ul><li><p>[CN-] = [N3-]</p></li><li><p>32 x [CN-] = [N3-] </p></li></ul><p><strong>given k[CN] = 16 k[N3]</strong></p>

define the rate of formation when:

  • [CN-] = [N3-]

  • 32 x [CN-] = [N3-]

given k[CN] = 16 k[N3]

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35
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define molar free energy of activation, ΔG‡

= difference in energy between a ground state and a transition state

= related to the rate constant, k.

~ analogous to activation energy

36
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how do ΔG‡ and E(a) differ?

ΔG‡ = contains ΔS‡ and ΔH‡

E(a) = contains ΔH‡

37
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give an equation that relates rate constant with ΔG‡

ΔG‡ = ΔS‡ and ΔH‡ related

vs

Ea = ΔH‡ related

A = ΔS‡ related

small |ΔG‡| = large k = fast reaction

large |ΔG‡| = small k = slow reaction

= analogous to activation energy

38
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what are the ranges for enthalpy and entropy of activation?

ΔH‡ = 40 - 125 kJ mol(-1)

ΔS‡ = -150 - 60 J K(-1) mol(-1)

ΔH‡ = always positive due to breaking of bonds without reforming (forming TS) = always disfavoured

smaller = ~favoured

larger = ~disfavoured

ΔS‡:

-ve = disfavoured

+ve = favoured

39
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describe a dissociate RDS in terms of enthalpy and entropy

favoured by entropy = increase in disorder

disfavoured by enthalpy = bonds broken

40
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describe an associative RDS in terms of enthalpy and entropy

disfavoured by entropy = increase in order

favoured by enthalpy = balance in bond breaking/forming

41
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<p>describe.a diels alder reaction in terms of entropy</p>

describe.a diels alder reaction in terms of entropy

  • requires simultaneous bond formation = highly ordered TS

  • associated RDS

highly disfavoured by entropy

42
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define an elementary reaction

= a single step in a reaction mechanism proceeding in a particular direction

43
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define molecularity of an elementary step

= the number of molecules involved in the formation of a single transition state (ignoring those only involved in solvation)

= may be different depending on direction

44
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what are the two molecularities of elementary steps?

  • unimolecular

  • bimolecular

molecularities above this are exceedingly slow since they require the simultaneous collision of ≥3 molecules

45
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describe microscopic reversibility

= the mechanism of the (lowest energy) reverse reaction must retrace each step of the mechanism of the (lowest energy) forward reaction (in microscopic detail)

= RDS are mirrored i.e. formation of intermediate in both directions

<p>= the mechanism of the (lowest energy) reverse reaction must retrace each step of the mechanism of the (lowest energy) forward reaction (in microscopic detail) </p><p>= RDS are mirrored i.e. formation of intermediate in both directions </p>
46
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how can reactions be accelerated?

  • increase concentration(s) of reactant(s)

  • increase temperature

  • reduce ΔG‡ of the RDS = raise ground state energy and/or lower TS energy

47
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describe SN2 reactions

  • bimolecular; second order

  • concerted; 1 step

  • inversion of configuration

48
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draw the mechanism of an SN2 reaction

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49
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describe SN2 reactions in terms of ΔS‡ and ΔH‡

associative TS

disfavoured by ΔS‡

favoured by ΔH‡

50
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draw a reaction coordinate diagram of an SN2 reaction

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51
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what can be determined from ΔG‡ vs ΔG°?

ΔG‡ = rate constant, k = RDS varies rate

ΔG° = equilibrium constant, K = varies position of equilibrium

52
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draw the MO diagram for the transition (Nu-C)

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53
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describe SN2 reaction in terms of orbital overlap

back lobe (opposite to L):

  • phase matched

  • good overlap

front lobe (at L):

  • phases matched

  • poor overlap

<p>back lobe (opposite to L):</p><ul><li><p>phase matched</p></li><li><p>good overlap </p></li></ul><p>front lobe (at L):</p><ul><li><p>phases matched</p></li><li><p>poor overlap </p></li></ul><p></p>
54
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why is Nu attack favoured from the back lobe/inhibited at the front lobe?

  • poor orbital overlap/alignment

  • electrostatic repulsions from L and R

55
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describe soft and hard electrophiles/nucleophiles

soft = polarisable = large, uncharged, diffuse

hard = less polarisable = small, highly charged

56
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examples of soft and hard electrophiles/nucleophiles

nucleophiles

soft = I(-), RS(-), NC(-) = large attacking atom/charge distribution over atoms

hard = F(-), RO(-) = small attacking atom/concentrated charge

electrophiles

soft = alkyl halide (large halide i.e. I)

hard = H(+), alkyl halide (small halide i.e. Cl), carbonyls, SiMe3(+)

57
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describe the energy of soft/hard electrophile LUMO/nucleophile HOMO

electrophiles:

soft = low LUMO

hard = high LUMO

nucleophiles:

soft = high HOMO

hard = low HOMO

58
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what kind of electrophiles are alkyl halides and what kind of NUCLEOPHILE IS FAVOURED IN SN2?

alkyl halides = soft electrophiles = low LUMO

interact best with soft nucleophiles = high HOMO

i.e. I(-), RS(-), NC(-)

59
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describe enolates variable nucleophilicity

soft at B carbon

hard at charged O

<p>soft at B carbon </p><p>hard at charged O</p>
60
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draw the reaction of enolate with:

  • silylating agents (Me3Si-Cl)

  • alkyl halides (Me-I)

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61
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describe the speed of SN2 reactions on different °s of alkyl halides

1° = YES; fast

2° = majorly no; if yes, slow

3° = NO

62
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described the speed of SN2 reactions on different length 1° alkyl halides

smaller chain = faster SN2

63
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describe the speed of SN2 reactions with different size of nucleophiles

bulky nucleophiles = slow

64
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<p>describe the SN2 reaction of Me-I with these nucleophiles</p><p></p>

describe the SN2 reaction of Me-I with these nucleophiles

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65
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what can reduce ΔG‡ w.r.t. leaving group

  • weak C-L bond

  • L(-) stability

66
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what acts as a proxy for leaving group ability?

pKa

= defines the stability of the anion

weak acids: tend to protonated form

  • strong H-A bond

  • poor stabilisation of A(-)

strong acids: tend to deprotonated form

  • weak H-A bond

  • good stabilisation of A(-)

therefore:

strong acid = small pKa = good leaving groups

weak acid = large pKa = poor leaving groups

67
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define pKa and how it relates to acid strength

pKa 1/acid strength

68
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describe the relative leaving group abilities of the halides

69
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give examples of poor leaving groups

  • F(-)

  • RS

  • CN

  • OH

  • OR

70
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describe why there is no SN2 at sp2 (majorly) or sp (ever) atoms

  • line of attack is blocked

  • C has higher s character = stronger C-X bond

  • C-X sigma bond often not the LUMO

<ul><li><p>line of attack is blocked</p></li><li><p>C has higher s character = stronger C-X bond</p></li><li><p>C-X sigma bond often not the LUMO </p></li></ul><p></p>
71
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what can reduce ΔG‡ w.r.t nucleophile

  • strong C-Nu bond

  • Nu instability/reactivity

72
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what acts as a proxy for nucleophilicity (SAME ATOM/SAME SIZE)?

pKa of conjugate acid

weak conjugate acids: tend to protonated form

= conjugate base is less stabilised (less likely to be protonated) by weak conjugate acid

strong acids: tend to deprotonated form

= conjugate base is more stabilised (likely to be protonated) by strong conjugate acid

therefore:

strong conjugate acid = small pKa = poor nucleophile

weak conjugate acid = large pKa = good nucleophile

73
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examples of nucleophiles and relative reactivities

most nucleophilic → least nucleophilic

74
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summarise pKa and LG/Nu ability

acid strength ∝ 1/pKa ∝ LG ability

conjugate acid strength ∝ 1/pKa ∝ 1/Nu ability

75
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describe the variable solvation of charges by protic solvents

hard negative charges = strong charge-dipole interactions = good solvation

soft negative charges = weak charge-dipole interactions = poor solvation

76
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what does the nucleophilicity of attacking atoms of different sizes depend on?

solvent

aprotic solvents:

negative charges are not solvated = nucleophilicity ∝ basicity

protic solvents:

hard negative charges are solvated = weakly nucleophilic

(charge is delocalised in TS so less interaction with solvent)

soft negative charges are poorly solvated = strongly nucleophilic

77
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for what kind of SN2 reactions are polar aprotic solvents particularly good for?

uncharged electrophile + charged nucleophile

polar aprotic solvents only solvate +ve charges. +ve component/counterion of nucleophile is well solvated while the -ve part is poorly solvated = naked and highly reactive.

78
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what kind of solvent is preferred in:

  • charged nucleophile + uncharged electrophile

  • uncharged nucleophile + uncharged electrophile

  • charged nucleophile + uncharged electrophile

= (polar) aprotic

= TS has delocalised charge w.r.t reactants/products

  • uncharged nucleophile + uncharged electrophile

= polar (aprotic or protic)

= TS/products is more polar than reactants = stabilised by polar solvent

79
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what is used to facilitate SN2 between non-polar RX and ionic compounds?

  • 2 immiscible solvents

  • phase transfer catalyst

80
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example of a phase transfer catalyst

= soluble in both organic and aqueous phases

81
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describe phase transfer catalysis

non-polar RX + ionic compound + 2 immiscible solvents

  • non-polar RX will dissolve in organic phase; ionic compound will dissolve and ionise in aqueous phase

  • phase transfer catalyst drags -ve ion into organic phase to balance charge; -ve ion is naked and highly reactive = SN2

  • phase transfer catalyst coordinates to -ve ion product of SN2 and drags back into aqueous phase

<p>non-polar RX + ionic compound + 2 immiscible solvents</p><ul><li><p>non-polar RX will dissolve in organic phase; ionic compound will dissolve and ionise in aqueous phase</p></li><li><p>phase transfer catalyst drags -ve ion into organic phase to balance charge; -ve ion is naked and highly reactive = SN2</p></li><li><p>phase transfer catalyst coordinates to -ve ion product of SN2 and drags back into aqueous phase </p></li></ul><p></p>
82
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what can be used as a nucleophilic catalyst and explain

iodide I(-)

  • nucleophilicity in protic solvent: I(-) > Nu(-)

I(-) = large anion = soft = poorly solvated by protic solvent

  • iodide displaces L faster than Nu(-)

  • leaving group ability: I(-) > L

HI = strong acid = good LG

  • Nu(-) displaces in R-I faster than in R-L

<p>iodide I(-)</p><ul><li><p>nucleophilicity in protic solvent: I(-) &gt; Nu(-)</p></li></ul><p>I(-) = large anion = soft = poorly solvated by protic solvent</p><ul><li><p>iodide displaces L <strong>faster</strong> than Nu(-)</p></li></ul><p></p><ul><li><p>leaving group ability: I(-) &gt; L</p></li></ul><p>HI = strong acid = good LG</p><ul><li><p>Nu(-) displaces in R-I <strong>faster</strong> than in R-L</p></li></ul><p></p>
83
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why are cyclisations favoured over bimolecular reactions?

by entropy

cyclisations:

  • dissociative TS

  • ΔS = 0

bimolecular:

  • associative TS

  • ΔS = -ve (loss of translational entropy via associative TS)

84
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relative reactions rate for different ring sizes (cyclisations)

5 > 6 > 3 > 4 & 7 > other rings

85
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why do cyclisation forming small (3/4) rings have slow reaction rates?

ring strain:

in products increases ΔH*

in TS increases ΔH‡

86
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why do cyclisation forming large (>6) rings have slow reaction rates?

probability of ends colliding with correct orientations is small

87
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what is effective molarity

EM = k(intra) / k(inter)

unimolecular: the concentration of [A] required to match k(intra)

88
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why would effective molarity (EM) be low?

favourable orbital alignment/other stereoelectronic factor present in inter absent in intra

89
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describe how reaction would proceed here with NaOEt

SN2 at 3° C-X possible due to favoured 3 membered ring

<p>SN2 at 3° C-X possible due to favoured 3 membered ring  </p><p></p>
90
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describe intra SN2 on cyclohexane

Nu and LG must be 1,2-trans diaxial and antiperiplanar

= orbital alignment

91
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what does X-exo/endo-trig/tet mean?

X = ring size in the TS

exo/endo:

exo = bond broken outside ring of TS

endo = bond broken within ring of TS

trig/tet:

trig = LG attached to trigonal C (sp2)

tet = LG attacked to tetrahedral C (sp3)

92
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what are Baldwin’s guidelines to favourable cyclic reactions

exo > endo

= favoured by good orbital alignment

3 to 7-exo-tet > 3 to 7-endo-tet

93
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what form does the lowest energy TS of an SN2 take?

= linear

94
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describe neighbouring group participation (= anchimeric assistance)

(strained) cyclic intermediate increases reaction rate

  • sometimes lead to rearrangement

  • sometimes affects stereochemistry of products

= intramolecular nucleophilic catalysis (i.e. iodide nucleophilic catalysis)

95
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describe the effect of neighbouring group participation here

3-exo-tet cyclisation

<p>3-exo-tet cyclisation </p>
96
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<p>draw the mechanism of this reaction </p>

draw the mechanism of this reaction

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97
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explain why the anti diastereomer is faster than the syn diastereomer

= neighbouring group participation

<p>= neighbouring group participation </p>
98
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explain the Curtin Hammett principle

the ratio of products formed from one starting material present in two rapidly equilibrating conformations depends only on the energy difference between the two transition states

99
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draw the two pathways of this reaction

LEFT IS WRONG = NEEDS TRANSDIAXIAL

<img src="https://knowt-user-attachments.s3.amazonaws.com/4393bf90-73a6-4e3a-b73f-944745f34ead.png" data-width="100%" data-align="center"><p><strong>LEFT IS WRONG = NEEDS TRANSDIAXIAL </strong></p>
100
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describe SN1 reactions

  • unimolecular; first order

  • stepwise; 2 step

  • loss of stereochemistry