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Injective (one-to-one)
f(a) = f(b) implies a = b
surjective (onto)
all outputs are accounted for by an input. (calculate output in terms of input)
set minus (A \ B)
A intersection B’. all of A that doesn’t overlap with B
Cartesian Product (AxB)
the set of all pair combinations of A and B
power set (P(A))
the set of all subsets of A (including the empty set)
composition (gof)
gof = g(f(x)). the output set of f(x) must be the input set of g(x)
inversion
an evil twin of a function where both compositions of the pair result in just the input
a|b
a divides b. b = a*k where k is an integer
modus ponens
(p→q)^p => q
simplification
p^q=>p
implication
p→q <=> not(p) or q
conjugation
any two statements can be brought together with an and (^) statement
contrapositive
a→b <=> not(a) → not(b)
c
proper subset. A c B if A is a subset of B but B isn’t a subset of A
= (for sets)
A is a subset of B and B is a subset of A
simple graph
doesn’t have loops
circuit
path starting and ending on same vertex
modus tollens
(p→not(q)) ^ q => not(p)