transition metal catalysis

0.0(0)
studied byStudied by 0 people
0.0(0)
call with kaiCall with Kai
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
GameKnowt Play
Card Sorting

1/19

encourage image

There's no tags or description

Looks like no tags are added yet.

Last updated 8:08 PM on 2/1/26
Name
Mastery
Learn
Test
Matching
Spaced
Call with Kai

No analytics yet

Send a link to your students to track their progress

20 Terms

1
New cards

why are transition metals good catalysts?

  • have variable oxidation states

  • so are able to form a range of compounds by gaining/losing e- w/in their d orbitals

2
New cards

in which process does vanadium act as a catalyst? give the eqns for this process:

Contact Process - industrial process for making H2SO4 :

  • S + O2 → SO2

  • SO2 + ½ O2 → (V2O5 catalyst) SO3

  • SO3 + H2O → H2SO4

3
New cards

give and explain pair of eqns for the use of V2O5 as a catalyst in the Contact Process:

V2O5 oxidises SO2 to SO3 and is itself oxidised to V2O4:

  • V2O5 + SO2 → V2O4 + SO3

the reduced catalyst is then oxidised back to its original state:

  • V2O4 + ½ O2 → V2O5

4
New cards

what is a heterogeneous catalyst? how do reactions occur?

catalyst which exists in a different phase from the reactants

<p>catalyst which exists in a different phase from the reactants</p>
5
New cards

explain how a heterogenous catalyst works:

  • reactants adsorb onto active sites on the surface of the heterogenous catalyst

  • bonds weaken/reaction takes place

  • products desorb from surface

6
New cards

give 2 egs of heterogenous catalysts and their eqns:

Fe in the Haber process:

  • N2 (g) + 3H2 (g) → (Fe (s) catalyst) 2NH3 (g)

V2O5 in the Contact process:

  • SO2 (g) + ½ O2 (g) → (V2O5 (s) catalyst) SO3 (g)

7
New cards

how can we minimise the cost of a reaction using a heterogenous catalyst?

  • maximise SA so increase no. of molecules that can react at the same time

  • this can be achieved by using powder/small pellets/support medium

8
New cards

give and explain an example of a support medium and provide the eqn:

  • catalytic converters contain a ceramic lattice coating in a thin layer of Rh/Pt/Pd

  • 2CO (g) + 2NO (g) → (Rh (s) catalyst) 2CO2 (g) + N2 (g)

9
New cards

what is catalyst poisoning? how does this occur?

  • catalysts can be poisoned when impurities adsorb onto the active sites of the catalyst, blocking them

  • this decreases the efficiency of catalysis, increasing costs

10
New cards

give 2 examples of catalyst poisoning:

  • lead can coat the inner surface of a catalytic converter

  • sulfur can poison the active sites on the iron catalyst in the Haber process, forming iron sulfide (sulfur found in fossil fuels used to produce H2)

11
New cards

what is a homogeneous catalyst?

catalyst which exists in the same phase as the reactants (typically liquids/solutions)

12
New cards

how do homogeneous catalysts work?

  • work by forming an intermediate species which then reacts to form the products

  • the EA needed to form the intermediate species is lower than that needed to make the products directly

13
New cards

give an example of a homogeneous catalyst and give the eqn for the reaction it catalyses:

Fe2+ ions catalyse the reaction between peronodisulfate ions and iodide ions:

  • S2O82- (aq) + 2I-(aq) → (Fe2+ (aq) catalyst) I2 (aq) + 2SO42- (aq)

14
New cards

why is the reaction between peronodisulfate ions and iodide ions slow without a catalyst?

-ve charges repel so high Ea

15
New cards

give a pair of eqns to show how Fe2+ acts as a catalyst in the reaction between peronodisulfate ions and iodide ions:

S2O82- (aq)  + 2Fe2+ (aq) → 2Fe3+ (aq) + 2SO42- (aq)

2Fe3+ (aq) + 2I(aq) → I2 (aq) + 2Fe2+ (aq)

16
New cards

other than having variable oxidation states, explain why Fe2+ ions are good catalysts for the reaction between peronodisulfate ions and iodide ions:

+ve ions attract -ve ions in catalysed process

17
New cards

give an example of a homogeneous catalyst which undergoes autocatalysis and give the overall eqn for the reaction it catalyses:

Mn2+ ions autocatalyse the reaction between C2O42- and MnO4- :

  • Mn2+ is a product of the reaction and acts as a catalyst

  • ∴ as the reaction progresses, amount of product increases

  • 2MnO4- (aq) + 16H+ (aq) + 5C2O42- (aq) → 2Mn2+ (aq) + 8H2O (l) + 10CO2 (g)

18
New cards

give a pair of ionic eqns to show how Mn2+ ions act as a catalyst in the reaction between C2O42- and MnO4- :

  • 4Mn2+ (aq) + MnO4- (aq) + 8H+ (aq) → 5Mn3+ (aq) + 4H2O (l) (Mn2+ oxidised back to Mn3+ by MnO4-)

  • 2Mn3+ (aq) + C2O42- (aq) → 2Mn2+ (aq) + 2CO2 (g) (Mn3+ reduced to Mn2+ by C2O42-)

19
New cards

how does Mn2+ lower the Ea of the reaction between C2O42- and MnO4- ?

Ea lowered because oppositely charged ions attract

20
New cards

give and explain the shape of a conc-time graph of MnO4-:

  • initially gradient shallow as RoR low as reaction is uncatalysed as too few Mn2+ ions made ∴ high Ea

  • RoR increases w/ time as more of autocatalyst is made

  • graph begins to level off as MnO4- used up

<ul><li><p>initially gradient shallow as RoR low as reaction is uncatalysed as too few Mn<sup>2+</sup>&nbsp;ions made&nbsp;<span>∴ high E</span><sub><span>a</span></sub></p></li><li><p>RoR increases w/ time as more of autocatalyst is made</p></li><li><p>graph begins to level off as MnO<sub>4</sub><sup>-</sup>&nbsp;used up</p></li></ul><p></p>