bio inheritence

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31 Terms

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diploid

  • have 2 copies of every chromosome (one maternal, one paternal) with the exception of the sex chromosomes, these pairs are all homologous)

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haploid

  •  have 1 copy of every chromosome, produced from diploid germ cells via meiosis

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zygote

  • Fusion of 2 haploid gametes (sperm + egg) via fertilsation will result in the formation of a zygote that can grow into a new organism via mitosis

  • If chromosome number was not halved in gametes, then the number of chromosomes would double in every generation (polyploidy)


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genotype

  • Sexually reproducing organisms inherit their DNA sequences from both parents - they will have 2 copies of every type of chromosome (one paternal, oe maternal)

  • While homologous chromosomes share the same genes, but because they came from different sources (maternal vs paternal origin) their base sequences may differ 

    • Alternate forms of a gene are called alleles, diploid cells will posses 2 alleles for each gene

  • The allele combination for any given gene is referred to as the genotype and can be characterized as 

    • Homozygous - when the alleles are the same

    • Heterozygous - when the alleles are different 

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phenotype

  • Observable characteristics of an organism - physical characteristics (curly hair, hair color, eye color) and structural (abilitiy to distinguish between diff colors) characteristics

  • Determined by gene makeup of environmental factors

    • Genotype only: blood type, ey color, genetic conditions like haemophilia

    • Enviroenmental only: learned behaviors, cellular traumas, infectious diseases

    • Both: skin coloration, height, weight, metabolic conditions

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phenotypic plasticity

  • Capacity for an organism to alter their features in response to environmental triggers by varying patterns of gene expression

  • Ex. freshwater snails 

    • Snails with smaller and more round shells are more crush resistant and better protected from predation

    • Freshwater snails may alter their shell structure in the presence of predator fish by changing the expression patterns of biomineralization

  • Ex. production of melanin when exposed to sunlight to protect the skin from UV damage

    • Change in gene expression results in increased production of melanin in the skin 


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genetic crosses

  • Principles of inheritance demonstrated by undertaking breeding experiments in flowering plants

  • Pollen is transferred from the anthers of one plant to stigma of other

  • When gametes fuse, they form a zygote that develops into an embryo inside a seed

  • The parents are known as the P generation and the offspring are the F1 generation

  • F2 generation are offspring of F 1


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dominance

  • Many traitrs follow a classic dominant/recessive pattern of inheritance whereby one allele (dominant) is expressed over the other (recessive)

  • Genes code for a polypeptide and recessive alleles of genes are produced by mutation from dominant alleles 

  • Homozygous dominant and heterozygous forms are phenotypically indistinguishable and the recessive allele is only expressed in a  homozygous state 


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Phenylketronuria

  • Disease due to re cessive allele

  • Allele is produced by mutation of the gene coding for the enzyme phenylalanine hydroxilase

  • Enzyme converts phenylalanine into tyrosine

  • A person with 2 recessive alleles of PKU gene cannot produce the functioning enzyme which causes phenylalanine to accumulate in the body and tyrosine deficiency will develop

  • Consequence: intellectual disability and mental disordrs

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gene

  • Length of DNA with a base sequence that cn be hundreds or thousands of bases long

  • Different alleles of a gene differ from each other by one or few bases

  • Positions in a gene where different bases can be present are called single nucleotide polymorphism

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multiple alleles

  • There can be many different alleles for the same gene

  • A gene pool is all the genes of an individual in a population

  • Each individual receives a maximum of 2 alleles form the gene pool

  • Presence of multiple alleles creates complexity in inheritence patterns that extend beyond a binary dominant/recessive paradigm

    • Some traits exhibit a dominance hierarchy in their phenotypes

    • Others may demonstrate a blended or combined phenotype

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codominance

  • Codominance occurs when pairs of alleles are both expressed equally in the phenotype of a heterozygous individual

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codominance: ABO blood group

  • The ABO blood group system in humans is an example of multiple Alleles

Phenotype

Genotype

Blood Type A

IAIA  or IAi

Blood type B

IBIB or IBi

Blood type AB

IAIB

Blood type O

ii

  • There are 6 possible genotype sbut only 4 phenotyoes

  • O allele is recessive

  • Genotype AB is an example of codominance

  • reasons for 2 blood groups to be codominant:

    • All three alleles cause the production of a glycoprotein in the membrane of red blood cells

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incomplete dominance

  • While comdominance occurs when 2 characterustics are both expressed autonomously in the phenotype, incomplete dominance occurs when the characteristics blend together

    • Eg mirabilis Jalapa when plants with dark pink flowers (CPCP) are crossed with white flowered plants (CWCW), the offspring will have light pink flowers ((CPCW)


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sex linkage

  • In humans, sex determination involves a pair of chromosomes calle dthe X and Y chromosomes

  • Female psess xx chromosomes while males posses xy

  • The y chromosomes contain the genes responsible for developing male sex characterustics - in it's absence, the female sex organs will develop ovaries

  • Hence the male gamete will dteermine the sex of offspring - as the female egg will always contain an x chromosome

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sex chromosome abnormalities

  • XXY - boy with klinefelters syndrome

  • X - girl with turner’s syndrome

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sex of individual

  • Male : the y chromosome contains a key gene called the SRY gene known as the TDF responsible for the development of testies in male embryo

  • Female - no Y chromosome → No TDF → development of ovaries

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sex linked inheritance

  • inheritance pattern when a gene controlling a characteristic is located on a sex chromosome

  • Because males and females have diffrent sex chromosome combinations, the patterns of inheritence will differ according to sex

  • Sex linked alleles are rperesnted as superscripts attached to the relevant sex chromosme ( XA  or  XB)

  • Because the y chromosme contains very few genes, the majority of sex linked traits are x- linked


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hemophilia

  • Genetic disorder wherby the body’s ability to control blood clotting is impaired

  • The formation of a blood clot is controlled by a cascade of coagulation factors whose genes are located on the X chromosome

    • When one of these factors becomes deffective, the clotting cascade becomes ineffective - bleeding continues for a long time

  • This is an exmaple of a x-linked recessive condition, meaning it occurs more frequently in males

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pedigree charts

  • Chart of genetic history of family over several generations

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autosomal inheritance

  • Autosomal dominant

    • If both parents are affected and an offspring is unaffected, the trait must be dominant (parents are both heterozygous)

    • If both parents are unaffected, all offspring must be unaffected (homozygous recessive)

  • Autosomal recessive

    • If both parents are unaffected and an aoffspring is affected, the trait must be recessive (parents are heterozygous)

    • If both parents show a trait, all offspring must also exhibit the trait (homozygous recessive)

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x - linked inheritance

  • Genetic disorders caused by mutations to

    • X linked dominant

      • If a male shows a trait, shown by all daughter cells as well as his mother

      • An unaffected mother cannot have affected sons or affected father

      • More common in females

    •  X linked recessive

      • If a female shows a trait, shown by all sons as well as fatyehr

      • An unaffected mother can have affected sons if she is a carrier (heterozygous)

      • X - linked recessive traits tend to be more common in males


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polygenetic traits

  • Variation in phenotypes for a particular characteristic can either be continuous or discrete

  • Phenotypic characteristics are not soley determined by genotype, but also influenced by environmental factors 

  • For example, skin color is controlled by multiple melanin producing genes and also affected by factors such as sun exposure 

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continous

  • the trait is influenced by multiple genes (polygenetic), environmental factors may influence the trait, ex: tree height, body mass of animals, skin color, human wrist circumference

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discrete

  • the trait is influenced by one or a few genes, enviornmental factors do not usually influence the trait, ex: ABO blood groups, number of egges laid by birds, left or right handed dnail shells, smooth wrinke peas

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box and whisker plot

  • Statistical tool that can be used to represent data for a continuous variable such as heigh

  • Plot shows minimum, maximum, medial values, and demonstrates the range via a lower and upper quartile

  • Allows researches to easily asses how variable the data is and whether or not it is skewed in a particular direction

  • Allows for statistical dtermination of outliers 

  • For a box-and-whisker plot, a data point is categorized as an outlier if it is either above the third quartile or below the first quartile by a value of more than 1.5 time the interquartile range (IQR) 




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gene assortment

  • Independent assortment is the segregation of the alleles of two genes so that the outcome with each gene has no effect on the outcome with the other 

  • The combinations of alleles that remain together are therefore random

  • The movement of the chromosomes to diffrent poles is random and the consequence is that every allele has 50% chance of being pulled too either pole

  • The alleles of a gene therefore segregate independently from the alleles if another gene 


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dihybrid cross

  • Step 1: Designate characters to represent the alleles (capital for dominant, lower case for recessive)

  • Step 2: write down the genotype and phenotype for the parents (P generation)

    • Always pair alleles from the same gene and always write capitals first (eg AaBb)

  • Step 3: write down all the potention gamete combinations for both parents

    • Foil method

  • Step 4: use a punett sequare to work out potential genotypes of offspring

  • Step 5: write out the phenotype rations of potential offspring


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gene linkage

  • 20,000 genes in genome that code for polypeptide, each gene has a base sequence and a locus

  • Locus: specific position of a gene on one of the chromosomes

  • Genes that are located close to each other on the same chromosome do not assort independently and instead show linkage 

    • Most linkages occur on autosomes (can be linked on X)

  • Gene linkage is indicated if the F2 ratio differs significantly from the expected ratio for unliked genes (9:3:1)

  • Likged genes will be inherited together

  • Linkes genes are represented as vertical pairs (AB//ab)

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recombinants

  • Individual with diffrent combination of alleles/traits from either parents 

  • Occur as a result of gene recombination which happens during meiosis

  • Random orientation of bivalents results in new combinations (unlinked genes). 

  • Crossing over produced new combinations (for linked genes)

  • Frrquency of recombination between 2 genes can be measured by crossing individuals that are heterozygous for both genes to individuals that are homozygous recessive for both genes 

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chisquared test

  • Statistical measure that are used to determine whether the diffrence between a observed and expected frequency distribution is statistically significant

  •  Step 1: Identity hypothesis (null versus alternative)

    • Null: There is no significant diffrence between observed and expected frequencies

    • Alternative: There is a significant difference between observed and expected frequences

  • Step 2: Construct a table of frequences (observed versus expected)

  • Step 3: Apply the chi-squared formula

  • Step 4: Determine the degree of freedom (df)

    • = n - 1 (n is number of classes)

  • Step 5: Identify the p-value (should be <0.05)