Hardy-Weinberg Principle

0.0(0)
studied byStudied by 0 people
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
Card Sorting

1/3

encourage image

There's no tags or description

Looks like no tags are added yet.

Study Analytics
Name
Mastery
Learn
Test
Matching
Spaced

No study sessions yet.

4 Terms

1
New cards

Name the conditions needed to apply the Hardy-Weinberg principle:

- The population is large

- Mating within the population is random

- Population is isolated

- There are no selection pressures

- No mutations arise

2
New cards

Hardy-Weinberg principle equations (these are given in the exam)

p + q = 1

p² + 2pq + q² = 1

3
New cards

p + q = 1

p² + 2pq + q² = 1

What do each letter mean?

p = frequency of the dominant allele (e.g. all the R)

q = frequency of the recessive allele (e.g. all the r)

p² = frequency of the homozygous dominant genotype (e.g. all the RR)

2pq = frequency of the heterozygous genotype (e.g. all the Rr)

q² = frequency of the homozygous recessive genotype (e.g. all the rr)

4
New cards

36 out of 400 plants are dwarf (recessive phenotype).

Calculate the frequency of the tall gene.

Determine the number of heterozygous pea plants.

q² = 36/400 = 0.09

q = √0.09 = 0.03

p = 1-0.3 = 0.7

p² = 0.49

2pq = 2x (0.7 x 0.3)

2pq = 0.42