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benzene
naturally occurring aromatic hydrocarbon
molecular = C6H6
empirical = CH
bond angle = 120
issues with Kekule’s model of benzene/why the delocalised model is more accurate
-benzene is less reactive than alkenes/does not readily react to addition
-enthalpy change of hydrogenation of benzene is less exothermic/more stable than expected
-all the carbon bond lengths are the same
-benzene is less reactive than alkenes/does not readily react to addition
-in benzene pi electrons are delocalised + in alkenes pi electrons are localised
-benzene has a lower electron density than alkenes so induces a weaker dipole in bromine so does not decolourise bromine water
-enthalpy change of hydrogenation of benzene is less exothermic/more stable than expected
-the enthalpy change of hydrogenation of cyclohexene to cyclohexane is -120kJmol-1
-so the theoretical enthalpy change of hydrogenation of benzene would be -120 × 3 due to 3 double bonds = -360kJmol-1
-however the actual enthalpy change was -208kJmol-1 which is 152kJmol-1 more energetically stable than expected
-all the carbon bond lengths are the same
-benzene should contain 2 different bond lengths as single bond length is 0.153nm and double bond length is 0.134nm
-but X-ray crystallography/diffraction revealed that the 6 carbon-carbon bonds were all of length 0.140nm
differences between Kekule’s model + delocalised model
-they both have p-orbitals overlapping to form pi bonds
-but in delocalised model the pi bonds are delocalised + in Kekule’s model the pi bonds are localised
Kekule’s model of benzene (DRAW STRUCTURE + BONDS)
.
delocalised model of benzene (DRAW STRUCTURE + BONDS)
the 6 pi electrons in benzene are free to move between all 6 carbon atoms in the ring and are not localised within three distinct double bonds
electrophilic substitution of benzene
an electrophile has substituted hydrogen from the benzene ring
-benzene has a high electron density above and below ring due to delocalised electrons
NITRATION reagents + reaction conditions
-concentrated sulfuric acid + concentrated nitric acid
-reflux at 50C
electrophilic substitution -NITRATION
stage 1 = creating a nitronium ion NO2+
1) H2SO4 + HNO3 ⇌ [H2NO3]+ + HSO4-
2) [H2NO3]+ ⇌ NO2+ + H2O
overall = H2SO4 + HNO3 → NO2+ + HSO4- + H2O
stage 2 = draw
stage 3 = acid catalyst regenerated
H+ + HSO4- → H2SO4
HALOGENATION reagents + reaction conditions
-halogen carrier = AlCl3 or FeCl3, AlBr3 or FeBr3
-is needed as benzene has a lower electron density than an alkene so won’t be able to induce a dipole in bromine
-halogen
-room temp + pressure
electrophilic substitution -HALOGENATION
-bromination or chlorination
stage 1 = creating bromonium or chloronium ion Br+ or Cl+
Br2 + FeBr3 → Br+ + FeBr4-
stage 2 = draw
stage 3 = catalyst regenerated
FeBr4- + H+ → HBr + FeBr3
Friedel-Craft’s ACYLATION
stage 1 = creating acylium ion RCO+
RCOCl + AlCl3 ⇌ RCO+ + AlCl4-
stage 2 = draw
stage 3 = catalyst regenerated
H+ + AlCl4- → AlCl3 + HCl
ACYLATION + ALKYLATION reagents + conditions
-acyl chloride for acylation OR haloalkane for alkylation
-halogen carrier
-reflux at 60C
-anhydrous conditions
Friedel-Craft’s ALKYLATION
stage 1 = RCl + AlCl3 ⇌ R+ + AlCl4-
stage 2 = draw
stage 3 = catalyst regenerated
H+ + AlCl4- → HCl + AlCl3
naming benzene compounds
1) stem + suffix = benzene
2) prefix - should have lowest number combination + in alphabetical order
3) for di- and tri- compounds, the first side chain is given the lowest number possible
side chain names
OH = hydroxy
NO2 = nitro
NH2 = amino
CN = cyano
benzene side chain = phenyl- - when H atom is removed from other functional group and replaced with benzene ring
phenol weak acid properties
1) partially soluble in water - OH group can form hydrogen bonds with water but aromatic group is non-polar so cannot
2) weak acid - orange - partially dissociates - more acidic than alcohols but less acidic than carboxylic acids
3) neutralisation reaction with NaOH + dissolves - can react strong bases such as NaOH to form a soluble salt and water
electrophilic substitution of phenol -DRAW TOO
-orange solution to a white solid precipitate in a colourless solution
-trisubstitution of bromine occurs and forms 2, 4, 6-tribromophenol
reaction conditions = room temp + pressure, halogen carrier NOT required
nitration of phenol -DRAW TOO
-reaction conditions = dilute nitric acid, no sulfuric acid, room temp + pressure
-trisubstitution does not occur = the nitro group (NO2) us a deactivating group
how is phenol more reactive than benzene?
-benzene + phenol contain delocalised pi electrons
-but the lone pair of electrons on oxygen from OH group on phenol is partially delocalised into the ring
-the OH group then activates the aromatic ring so phenol has a greater electron density
-so phenol is able to induce a dipole in bromine + is more susceptible to electrophilic attack while benzene cannot
activating groups
-push electrons into the delocalised ring so increases electron density making molecule more reactive so reacts more readily with electrophiles
-they direct the group to the 2, 4 and 6 positions (2 and 6 are the same)
examples = -NH2, -OH
deactivating groups
-pulls electrons out of the delocalised ring and towards themselves so decreases electron density making molecule less reactive so reacts less readily with electrophiles
-they direct the group to the 3 and 5 positions (3 and 5 are the same)
example = -NO2