Chapter 25 - Aromatic Compounds

0.0(0)
studied byStudied by 0 people
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
Card Sorting

1/19

encourage image

There's no tags or description

Looks like no tags are added yet.

Study Analytics
Name
Mastery
Learn
Test
Matching
Spaced

No study sessions yet.

20 Terms

1
New cards

benzene

naturally occurring aromatic hydrocarbon

molecular = C6H6

empirical = CH

bond angle = 120

2
New cards

issues with Kekule’s model of benzene/why the delocalised model is more accurate

-benzene is less reactive than alkenes/does not readily react to addition

-enthalpy change of hydrogenation of benzene is less exothermic/more stable than expected

-all the carbon bond lengths are the same

3
New cards

-benzene is less reactive than alkenes/does not readily react to addition

-in benzene pi electrons are delocalised + in alkenes pi electrons are localised

-benzene has a lower electron density than alkenes so induces a weaker dipole in bromine so does not decolourise bromine water

4
New cards

-enthalpy change of hydrogenation of benzene is less exothermic/more stable than expected

-the enthalpy change of hydrogenation of cyclohexene to cyclohexane is -120kJmol-1

-so the theoretical enthalpy change of hydrogenation of benzene would be -120 × 3 due to 3 double bonds = -360kJmol-1

-however the actual enthalpy change was -208kJmol-1 which is 152kJmol-1 more energetically stable than expected

5
New cards

-all the carbon bond lengths are the same

-benzene should contain 2 different bond lengths as single bond length is 0.153nm and double bond length is 0.134nm

-but X-ray crystallography/diffraction revealed that the 6 carbon-carbon bonds were all of length 0.140nm

6
New cards

differences between Kekule’s model + delocalised model

-they both have p-orbitals overlapping to form pi bonds

-but in delocalised model the pi bonds are delocalised + in Kekule’s model the pi bonds are localised

7
New cards

Kekule’s model of benzene (DRAW STRUCTURE + BONDS)

.

<p>.</p>
8
New cards

delocalised model of benzene (DRAW STRUCTURE + BONDS)

the 6 pi electrons in benzene are free to move between all 6 carbon atoms in the ring and are not localised within three distinct double bonds

<p><span>the <strong>6 pi electrons </strong>in benzene are <strong>free to move </strong>between <strong>all 6 carbon atoms in the ring </strong>and are <strong>not localised </strong>within three distinct double bonds</span></p>
9
New cards

electrophilic substitution of benzene

an electrophile has substituted hydrogen from the benzene ring

-benzene has a high electron density above and below ring due to delocalised electrons

10
New cards

NITRATION reagents + reaction conditions

-concentrated sulfuric acid + concentrated nitric acid

-reflux at 50C

11
New cards

electrophilic substitution -NITRATION

stage 1 = creating a nitronium ion NO2+

1) H2SO4 + HNO3 ⇌ [H2NO3]+ + HSO4-

2) [H2NO3]+ ⇌ NO2+ + H2O

overall = H2SO4 + HNO3 → NO2+ + HSO4- + H2O

stage 2 = draw

stage 3 = acid catalyst regenerated

H+ + HSO4- → H2SO4

<p><strong><u>stage 1</u></strong> = creating a nitronium ion <strong>NO2+</strong></p><p>1) <span style="color: blue">H2SO4 </span>+ HNO3 ⇌ [H2NO3]+ + HSO4-</p><p>2) [H2NO3]+ ⇌ <strong>NO2+</strong> + H2O</p><p>overall = <strong>H2SO4 + HNO3 → NO2+ + HSO4- + H2O</strong></p><p><strong><u>stage 2</u></strong> = draw</p><p><strong><u>stage 3</u></strong> = <span style="color: blue">acid catalyst</span> regenerated</p><p><strong>H+ + HSO4- → </strong><span style="color: blue"><strong>H2SO4</strong></span></p>
12
New cards

HALOGENATION reagents + reaction conditions

-halogen carrier = AlCl3 or FeCl3, AlBr3 or FeBr3
-is needed as benzene has a lower electron density than an alkene so won’t be able to induce a dipole in bromine

-halogen

-room temp + pressure

13
New cards

electrophilic substitution -HALOGENATION

-bromination or chlorination

stage 1 = creating bromonium or chloronium ion Br+ or Cl+

Br2 + FeBr3 Br+ + FeBr4-

stage 2 = draw

stage 3 = catalyst regenerated

FeBr4- + H+ → HBr + FeBr3

<p>-bromination or chlorination</p><p><strong><u>stage 1</u></strong> = creating bromonium or chloronium ion<strong> Br+</strong> or <strong>Cl+</strong></p><p>Br2 +<span style="color: blue"> FeBr3 </span>→ <strong>Br+</strong> + FeBr4-</p><p><strong><u>stage 2</u></strong> = draw</p><p><strong><u>stage 3</u></strong> = <span style="color: blue">catalyst</span> regenerated</p><p><strong>FeBr4- + H+ → HBr + </strong><span style="color: blue"><strong>FeBr3</strong></span></p>
14
New cards

Friedel-Craft’s ACYLATION

stage 1 = creating acylium ion RCO+

RCOCl + AlCl3 RCO+ + AlCl4-

stage 2 = draw

stage 3 = catalyst regenerated

H+ + AlCl4- → AlCl3 + HCl

<p><strong><u>stage 1</u></strong> = creating acylium ion <strong>RCO+</strong></p><p>RCOCl + <span style="color: blue">AlCl3 </span>⇌ <strong>RCO+</strong> + AlCl4-</p><p><strong><u>stage 2</u></strong> = draw</p><p><strong><u>stage 3</u></strong> = <span style="color: blue">catalyst </span>regenerated</p><p><strong>H+ + AlCl4- → </strong><span style="color: blue"><strong>AlCl3 </strong></span><strong>+ HCl</strong></p>
15
New cards

ACYLATION + ALKYLATION reagents + conditions

-acyl chloride for acylation OR haloalkane for alkylation

-halogen carrier

-reflux at 60C

-anhydrous conditions

16
New cards

Friedel-Craft’s ALKYLATION

stage 1 = RCl + AlCl3 R+ + AlCl4-

stage 2 = draw

stage 3 = catalyst regenerated

H+ + AlCl4- → HCl + AlCl3

<p><strong><u>stage 1</u></strong> = RCl + <span style="color: blue">AlCl3 </span>⇌ <strong>R+</strong> + AlCl4-</p><p><strong><u>stage 2</u></strong> = draw</p><p><strong><u>stage 3</u></strong> = <span style="color: blue">catalyst </span>regenerated</p><p><strong>H+ + AlCl4- → HCl + </strong><span style="color: blue"><strong>AlCl3</strong></span></p>
17
New cards

naming benzene compounds

1) stem + suffix = benzene

2) prefix - should have lowest number combination + in alphabetical order

3) for di- and tri- compounds, the first side chain is given the lowest number possible

18
New cards

side chain names

OH = hydroxy

NO2 = nitro

NH2 = amino

CN = cyano

benzene side chain = phenyl- - when H atom is removed from other functional group and replaced with benzene ring

19
New cards

phenol weak acid properties

1) partially soluble in water - OH group can form hydrogen bonds with water but aromatic group is non-polar so cannot

2) weak acid - orange - partially dissociates - more acidic than alcohols but less acidic than carboxylic acids

3) neutralisation reaction with NaOH + dissolves - can react strong bases such as NaOH to form a soluble salt and water

20
New cards

electrophilic substitution of phenol

orange solution to a white solid precipitate in a colourless solution