Chapter 25 - Aromatic Compounds

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24 Terms

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benzene

naturally occurring aromatic hydrocarbon

molecular = C6H6

empirical = CH

bond angle = 120

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issues with Kekule’s model of benzene/why the delocalised model is more accurate

-benzene is less reactive than alkenes/does not readily react to addition

-enthalpy change of hydrogenation of benzene is less exothermic/more stable than expected

-all the carbon bond lengths are the same

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-benzene is less reactive than alkenes/does not readily react to addition

-in benzene pi electrons are delocalised + in alkenes pi electrons are localised

-benzene has a lower electron density than alkenes so induces a weaker dipole in bromine so does not decolourise bromine water

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-enthalpy change of hydrogenation of benzene is less exothermic/more stable than expected

-the enthalpy change of hydrogenation of cyclohexene to cyclohexane is -120kJmol-1

-so the theoretical enthalpy change of hydrogenation of benzene would be -120 × 3 due to 3 double bonds = -360kJmol-1

-however the actual enthalpy change was -208kJmol-1 which is 152kJmol-1 more energetically stable than expected

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-all the carbon bond lengths are the same

-benzene should contain 2 different bond lengths as single bond length is 0.153nm and double bond length is 0.134nm

-but X-ray crystallography/diffraction revealed that the 6 carbon-carbon bonds were all of length 0.140nm

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differences between Kekule’s model + delocalised model

-they both have p-orbitals overlapping to form pi bonds

-but in delocalised model the pi bonds are delocalised + in Kekule’s model the pi bonds are localised

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Kekule’s model of benzene (DRAW STRUCTURE + BONDS)

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<p>.</p>
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delocalised model of benzene (DRAW STRUCTURE + BONDS)

the 6 pi electrons in benzene are free to move between all 6 carbon atoms in the ring and are not localised within three distinct double bonds

<p><span>the <strong>6 pi electrons </strong>in benzene are <strong>free to move </strong>between <strong>all 6 carbon atoms in the ring </strong>and are <strong>not localised </strong>within three distinct double bonds</span></p>
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electrophilic substitution of benzene

an electrophile has substituted hydrogen from the benzene ring

-benzene has a high electron density above and below ring due to delocalised electrons

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NITRATION reagents + reaction conditions

-concentrated sulfuric acid + concentrated nitric acid

-reflux at 50C

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electrophilic substitution -NITRATION

stage 1 = creating a nitronium ion NO2+

1) H2SO4 + HNO3 ⇌ [H2NO3]+ + HSO4-

2) [H2NO3]+ ⇌ NO2+ + H2O

overall = H2SO4 + HNO3 → NO2+ + HSO4- + H2O

stage 2 = draw

stage 3 = acid catalyst regenerated

H+ + HSO4- → H2SO4

<p><strong><u>stage 1</u></strong> = creating a nitronium ion <strong>NO2+</strong></p><p>1) <span style="color: blue">H2SO4 </span>+ HNO3 ⇌ [H2NO3]+ + HSO4-</p><p>2) [H2NO3]+ ⇌ <strong>NO2+</strong> + H2O</p><p>overall = <strong>H2SO4 + HNO3 → NO2+ + HSO4- + H2O</strong></p><p><strong><u>stage 2</u></strong> = draw</p><p><strong><u>stage 3</u></strong> = <span style="color: blue">acid catalyst</span> regenerated</p><p><strong>H+ + HSO4- → </strong><span style="color: blue"><strong>H2SO4</strong></span></p>
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HALOGENATION reagents + reaction conditions

-halogen carrier = AlCl3 or FeCl3, AlBr3 or FeBr3
-is needed as benzene has a lower electron density than an alkene so won’t be able to induce a dipole in bromine

-halogen

-room temp + pressure

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electrophilic substitution -HALOGENATION

-bromination or chlorination

stage 1 = creating bromonium or chloronium ion Br+ or Cl+

Br2 + FeBr3 Br+ + FeBr4-

stage 2 = draw

stage 3 = catalyst regenerated

FeBr4- + H+ → HBr + FeBr3

<p>-bromination or chlorination</p><p><strong><u>stage 1</u></strong> = creating bromonium or chloronium ion<strong> Br+</strong> or <strong>Cl+</strong></p><p>Br2 +<span style="color: blue"> FeBr3 </span>→ <strong>Br+</strong> + FeBr4-</p><p><strong><u>stage 2</u></strong> = draw</p><p><strong><u>stage 3</u></strong> = <span style="color: blue">catalyst</span> regenerated</p><p><strong>FeBr4- + H+ → HBr + </strong><span style="color: blue"><strong>FeBr3</strong></span></p>
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Friedel-Craft’s ACYLATION

stage 1 = creating acylium ion RCO+

RCOCl + AlCl3 RCO+ + AlCl4-

stage 2 = draw

stage 3 = catalyst regenerated

H+ + AlCl4- → AlCl3 + HCl

<p><strong><u>stage 1</u></strong> = creating acylium ion <strong>RCO+</strong></p><p>RCOCl + <span style="color: blue">AlCl3 </span>⇌ <strong>RCO+</strong> + AlCl4-</p><p><strong><u>stage 2</u></strong> = draw</p><p><strong><u>stage 3</u></strong> = <span style="color: blue">catalyst </span>regenerated</p><p><strong>H+ + AlCl4- → </strong><span style="color: blue"><strong>AlCl3 </strong></span><strong>+ HCl</strong></p>
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ACYLATION + ALKYLATION reagents + conditions

-acyl chloride for acylation OR haloalkane for alkylation

-halogen carrier

-reflux at 60C

-anhydrous conditions

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Friedel-Craft’s ALKYLATION

stage 1 = RCl + AlCl3 R+ + AlCl4-

stage 2 = draw

stage 3 = catalyst regenerated

H+ + AlCl4- → HCl + AlCl3

<p><strong><u>stage 1</u></strong> = RCl + <span style="color: blue">AlCl3 </span>⇌ <strong>R+</strong> + AlCl4-</p><p><strong><u>stage 2</u></strong> = draw</p><p><strong><u>stage 3</u></strong> = <span style="color: blue">catalyst </span>regenerated</p><p><strong>H+ + AlCl4- → HCl + </strong><span style="color: blue"><strong>AlCl3</strong></span></p>
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naming benzene compounds

1) stem + suffix = benzene

2) prefix - should have lowest number combination + in alphabetical order

3) for di- and tri- compounds, the first side chain is given the lowest number possible

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side chain names

OH = hydroxy

NO2 = nitro

NH2 = amino

CN = cyano

benzene side chain = phenyl- - when H atom is removed from other functional group and replaced with benzene ring

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phenol weak acid properties

1) partially soluble in water - OH group can form hydrogen bonds with water but aromatic group is non-polar so cannot

2) weak acid - orange - partially dissociates - more acidic than alcohols but less acidic than carboxylic acids

3) neutralisation reaction with NaOH + dissolves - can react strong bases such as NaOH to form a soluble salt and water

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electrophilic substitution of phenol -DRAW TOO

-orange solution to a white solid precipitate in a colourless solution

-trisubstitution of bromine occurs and forms 2, 4, 6-tribromophenol

reaction conditions = room temp + pressure, halogen carrier NOT required

<p>-<span style="color: rgb(224, 102, 11)"><strong>orange </strong></span>solution to a <strong>white solid precipitate</strong> in a <u>colourless</u> solution</p><p>-<strong>trisubstitution </strong>of bromine occurs and forms <strong>2, 4, 6-tribromophenol</strong></p><p><u>reaction conditions</u> = <strong>room </strong>temp + pressure, halogen carrier <strong>NOT </strong>required</p>
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nitration of phenol -DRAW TOO

-reaction conditions = dilute nitric acid, no sulfuric acid, room temp + pressure

-trisubstitution does not occur = the nitro group (NO2) us a deactivating group

<p>-<u>reaction conditions</u> = <strong>dilute </strong>nitric acid, <strong>no </strong>sulfuric acid, <strong>room </strong>temp + pressure</p><p>-trisubstitution does <strong>not </strong>occur = the nitro group (NO2) us a <span style="color: blue">deactivating </span>group</p>
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how is phenol more reactive than benzene?

-benzene + phenol contain delocalised pi electrons

-but the lone pair of electrons on oxygen from OH group on phenol is partially delocalised into the ring

-the OH group then activates the aromatic ring so phenol has a greater electron density

-so phenol is able to induce a dipole in bromine + is more susceptible to electrophilic attack while benzene cannot

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<p><span style="color: red">activating </span>groups </p>

activating groups

-push electrons into the delocalised ring so increases electron density making molecule more reactive so reacts more readily with electrophiles

-they direct the group to the 2, 4 and 6 positions (2 and 6 are the same)

examples = -NH2, -OH

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deactivating groups

-pulls electrons out of the delocalised ring and towards themselves so decreases electron density making molecule less reactive so reacts less readily with electrophiles

-they direct the group to the 3 and 5 positions (3 and 5 are the same)

example = -NO2