Ap Chem Thou Shalt Not Forget

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136 Terms

1
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Compounds can be separated into elements by

chemical changes

2
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Mixtures can be separated by

physical changes

3
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Filtering separates mixtures

based on differences in particle size

4
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Distillation separates mixtures based on

differences in boiling point

5
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Chromatography separates mixtures based on

differences in polarity

6
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In paper chromatography,

the component that is most similar in polarity to the "mobile phase" moves up

the farthest.

7
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Mass is conserved during

chemical and physical changes

8
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When reading a volume of a liquid in a container, you can estimate by

reading in between the graduated

markings. That can give you one more sig. fig. in your volume.

9
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Ranking measuring devices from least precise to most precise→

beaker, graduated cylinder, volumetric

flasks, burette

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The volumetric flask has ____ on it to measure _____.

only ONE line; one specific volume.

11
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Density =

mass/volume

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The % composition by mass for a pure compound

does not change

13
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Oxidation #'s:

H = +1 (except in a hydride when it is -1) O = −2 (except in a peroxide when it is -1).

14
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LEO goes GER

OIL RIG

Losing electrons is oxidation. Gaining electrons is reduction.

Oxidation is loss

Reduction is gain

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oxidation occurs at the

Anode (AN OX)

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reduction occurs at the

Cathode (RED CAT)

17
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Electrons in a battery flow from

anode (−) to cathode (+).

18
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Salt bridge: Cations flow to the _____, and the anions flow to the ______.

cathode; anode.

19
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the cathode ____ mass and the anode _____ mass.

gains; loses

20
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(Eo): If you reverse a reaction

if you double a reaction

the sign of Eo cell changes; Eo cell DOES NOT change!!

21
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Eo cell = (volts)

Eo cell = (volts)

Eo Red (GER) - Eo Red (LEO)

Eo Reduction + Eo Oxidation

22
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The half-reaction with a more (+) Eo Red (more volts - winner)

is the reaction that takes place at the cathode...GER.

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The half-reaction with a more (-) Eo Red (less volts - loser)

is the reaction that takes place at the anode...LEO.

24
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When adding the two half reactions together, the electrons MUST _____________

cancel out

25
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ΔGo =

= -n F Eo

= -(# of electrons transferred)(F constant)(Ecell)

26
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If ΔGo is (−)

then Eo cell is (+)

27
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(electrochem) If Q increases

then the voltage (Eo cell) of the battery goes down.

28
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Electroplating/Electrolysis Calculation:

grams =

(Molar Mass of the metal) (amps)(seconds)/(n)(F)

=(MM)(I)(t)/nF

29
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Thermodynamically favorable (spontaneous) reactions have a

(−)ΔG.

30
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Reactions with (−)ΔH and (+)ΔS are ALWAYS ____________

thermodynamically favorable

"enthalpy driven & entropy driven"

31
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Reactions that increase the # of moles of gas have a

(+)ΔS.

32
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If ΔG is (−)

then Keq >1.

33
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ΔH and ΔS are usually _________

NOT given in the same units!!

When using ΔGo =ΔHo−TΔSo, make sure they match units.

34
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ΔG = 0

at equilibrium (ΔG)

35
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When using ΔGo = −RT lnK, the R is _________________ so ΔG will be in the units of

8.314 J/mol K

Joules.

36
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Sometimes a reaction with a (−)ΔG does not proceed at a measurable rate. They are said to be __________. _______________ is a common reason for a process to be _______________________.

under "kinetic control."; High activation energy; under kinetic control.

37
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Exothermic reactions:

(-) ΔH; heat is a product; temp increases

38
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Endothermic reactions:

(+) ΔH; heat is a reactant; temp decreases

39
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ΔHrxn =

Bonds broken − Bonds formed (reactant bonds are broken; product bonds are formed)

40
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Breaking bonds is ________

Forming bonds is _________

endothermic (takes to break)

exothermic (frees to form)

41
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ΔHrxn=

ΔHproducts− ΔHreactants

(Don't forget to multiply by the coefficients!!)

42
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(bonds) if a reaction is exothermic

produc bonds are stronger/more stable than the

reactant bonds.

43
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ΔH:

a) doubling a reaction

b) revering a reaction

c) adding reactions

a) ΔH will double.

b) The sign for ΔH changes.

c)Add the ΔH's.

44
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Buffers are created by

by a weak acid + CB (salt) or by a weak base + CA (salt).

45
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[H+] =

MaKa / [salt]

You can use # of moles instead of molarity in this formula.

46
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Adding a common ion to a weak acid (or base)

decreases the % ionization & therefore the pH gets closer to 7.

47
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(at the equivalence point) MaVa=

MbVb (at the equivalence point)

48
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M1V1=

M2V2=

49
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Titrations: Weak acid + Strong Base has a pH at the equivalence point

(titrations) that's above 7

50
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Titrations: Weak Base + Strong Acid has a pH at the equivalence point that's

(titrations) below 7

51
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Titrations: Strong Acid + Strong Base has a pH ______ at

the equivalence point.

(Titrations) at 7

52
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(1⁄2 equivalence point for a "weak + strong" titration.) pH=

=pKa & [HA]=[A-]

53
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More buffer capacity=

more moles of weak acid/weak base & CB/CA

54
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Solubility Equilibrium: 2 ions

Ksp= X^2

55
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Solubility Equilibrium: 3 ions

Ksp = 4X^3

56
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Solubility Equilibrium: "x" =

molar solubility in units of moles/liters

57
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the larger the "x vaule"

the more soluble the salt is

58
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if Q> Ksp

precipitate will form

59
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Always soluble in water - usually the spectator ions

sodium Na

nitrate NO3-

ammonium NH4+ potassium K

& Group I cations

60
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The pH of acids are

less than 7

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the pH of bases are

greater than 7

62
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the pH of pure water is only ___ at ___

7; a temperature of 25 C

63
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Brønsted-Lowry acids

donate [H+]

64
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Brønsted-Lowry bases

accept [H+]

65
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Hydronium ion is

[H3O+]

66
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[H+] is a

proton

67
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Strong Bases

Group 1 hydroxides & Group 2 hydroxides (Some Group II hydroxides are only slightly

soluble, but whatever dissolves can completely ionize.)

68
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Strong acids

HNO3 - Nitric

H2SO4 - Sulfuric

HClO4 - Perchloric

HBr - Hydrobromic

HI - Hydroiodic

HCl - Hydrochloric

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pH=

-log[H+]

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[H+]=

10^-pH

71
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The weaker an acid/base

The stronger the conjugate base/acid

72
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The stronger the acid/base

The weaker the conjugate base/acid

73
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Acid-Base reactions favor the direction of

the strong side

(k>1 ~ reactants strong)

(k<1 ~ products strong)

74
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"x" in the ice box calculation is

[H+] for a weak acid & [OH−] for a weak base.

75
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% Ionization of a weak acid =

[H+] / Ma

76
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% ionization increases as

acid concentration decreases (adding more water increases the amount of ionization)

77
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if a salt contains a conjugate base of a weak acid

the salt is going to be slightly basic basic

(CBOWA's are (-) ions.)

78
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if a salt contains a conjugate of a weak base

the salt is going to be slightly acidic

(CAOWB's are (+) ions.)

79
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If a salt contains conjugates of strong acid/bases

the ion is neutral. ex: KBr is a neutral salt (KOH

+ HBr)

80
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A larger Ka value means

a stronger acid

81
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A larger Kb value means

a stronger base

82
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Relative strengths of acids:

a. smaller cations are

b. more (+) charge on a cation

c. more oxygens (or electronegative atoms) on an anions make it

a. more acidic

b. more acidic

c. more acidic since the proton is more ionizable

83
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Keq =

[products]^x

/[reactants]^y

x and y represent the coefficients in the balanced chemical equation.

84
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Only states of matter that appear in an equilibrium expression:

(aq) & (g)

85
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equilibrium expression: brackets

[molarity]

86
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equilibrium expression: paratheses

(Pgas) - atm

87
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Large Keq

more products at equilibrium

88
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small Keq

more reactants at equilibrium

89
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Reversing a reaction

1/Keq

90
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doubling a reaction

(Keq)^2

91
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Adding reactions

Multiply the K's together

92
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Le Chatelier's Principle:

States that if a stress is applied to a system at equilibrium, the system shifts in the direction that relieves the stress.

93
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If Q >Keq

reaction shifts to the left: toward the reactants

94
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Q < Keq

then the reaction shifts to the right: toward the products

95
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Catalysts and inert gases __________ an equilibrium

Do NOT shift

96
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Changes in pressure (by changing volume of a container) can shift an equilibrium ONLY IF

The number of moles of gas particles are different on each side

97
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An increase in pressure favors a shift in the equilibrium towards

the side with less moles of gas (volume decrease, pressure increase)

98
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In order for a reaction to occur:

- particles must collide

- at the correct orientation

- with a minimum energy to break bonds (activation energy)

99
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How to write a rate law for an elementary step:

2A + B → C + D

Rate =k[A]^2 [B]^1

100
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Rate constant (k) Units:

1st order = s^-1

2nd order = M^-1 s^-1