Statics Concepts

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Last updated 11:44 PM on 8/6/26
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72 Terms

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Force Classifications

  1. Contact (push/pull)

  2. Body (gravitation, magnetic)

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Force Application

  1. Concentrated

  2. Distributed

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Force Location

  1. External - change motion or develop reactions

  2. Internal - cause deformations

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Force Characteristics

Magnitude + Direction + Point of Application + Unit

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Transmissibility

Either force has the same external effect

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Force Systems

  1. Concurrent - LOAs intersect at a point —> can replace with on force (Fr = F1 + F2 + F3)

  2. Non-concurrent: LOAs don’t intersect

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Mo in scalar and vector notation

  1. Scalar: Mo = Fd

  2. Vector: Mo = r x F

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Varignon’s Theorem

The forces along a same LOA create the same moment

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Characteristics of a Moment of a Couple

  1. Equal magnitude

  2. Opposite direction

  3. Parallel LOAs

  4. Non-collinear

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Newton’s First Law

An object remains at rest if there is no unbalanced force acting on it

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Equations of Equilibrium (Concurrent)

ΣFx = 0

ΣFy = 0

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Equations of Equilibrium (Non-concurrent)

ΣFx = 0

ΣFy = 0

ΣMAny Point = 0

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Required Items of a Free Body Diagram

  1. Body detached from its surroundings

  2. Coordinate axis system

  3. Reactions & applied forces

  4. Dimensions and member labels

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<p>Support Conditions</p>

Support Conditions

  1. Roller (positive-y)

  2. Pin (positive-y and positive-x)

  3. Fixed (positive-x, positive-y, and positive-z)

  4. Cable (tension)

  5. Frictionless Slot (positive-y)

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Fr (in terms of a resulting force in centroid problems)

Equivalent concentrated force/area under the load curve

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Centroid

Geometric center of a line, area, or volume

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Conditions of a centroid

  1. Same as center of mass/gravity for homogenous material

  2. Not necessarily on the shape

  3. Always located on the axis/axes of symmetry

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Fluid Pressure

p = ρgh *valid only for incompressible fluids

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Two-Force Members

Member with forces applied only at its ends

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Characteristics of Two-Force Members

  1. Neglect self-weight

  2. No applied moments or couples

  3. Frictionless pins at the ends

  4. Positive = tension; Negative = compression

  5. The forces are

    1. Equal

    2. Opposite

    3. Collinear (same LOA)

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Truss

structure composed of two-force members joined at their ends by frictionless pins (basically interlocking triangles)

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Where and Why Trusses?

Where: bridges, roofs, cranes

Why: efficient, long-span, beautiful

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Assumptions of trusses

  1. Members connected at the ends only

  2. Loads are applied only to truss joints

  3. Self-weight neglected or placed at joints

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Truss cutting procedure

  1. ID members of interest

  2. Solve external forces, if necessary

  3. ID zero-force members

  4. Cut truss - joint/section method

  5. Solve for internal forces

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Truss cutting rules

  1. Cut members of interest

  2. Don’t cut through joints

  3. Cut through entire truss

  4. # unknowns <= # equations of equilibrium

  5. Assume tension

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Zero-Force Member

A member that carries no load

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Zero-force members Rules of Thumb (2 Member Joints)

Both members are zero-force members if:

  1. Two non-collinear members form a joint

  2. No external loads or reactions at joint

  3. Members do not have to form a right angle

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Zero-force members Rules of Thumb (3 Member Joints)

The non-collinear member is the zero-force member if:

  1. Two collinear and one non-collinear member form a joint

  2. No external loads or reactions at joint

  3. Members do not have to form a right angle

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Frame

A structure with at least one multi-force member

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Multi-force Member

A member with either

  • 3 or more forces acting on it, not just at its ends

  • 2 or more forces and one or more couples acting on it

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Frame & Machine procedure

  1. Solve for external reactions, if necessary

  2. Pull the pins

  3. ID two-force members

  4. ID multi-force members

  5. Apply Newton’s 3rd Law

  6. Include MDP+U & on which member with results

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Beams

Members with loads applied perpendicular to the longitudinal axis

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Statically Determinate Beam Classifications

  • Simply supported

  • Cantilever

  • Combination

<ul><li><p>Simply supported</p></li><li><p>Cantilever</p></li><li><p>Combination</p></li></ul><p></p>
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Statically Indeterminate Beam Classifications (# unk > # eq)

  • Continuous

  • Propped Cantilever

  • Fixed-fixed

<ul><li><p>Continuous</p></li><li><p>Propped Cantilever</p></li><li><p>Fixed-fixed</p></li></ul><p></p>
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Shear & Moment Diagrams

Graphs which plot internal shear and moment along the length of the member

  • Plot position on x-axis and plot shear/moment on y-axis

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dM/dx = V

Slope of moment curve = magnitude of shear curve at a point

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dV/dx = w(x)

Slope of shear curve = magnitude of load curve at a point

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M2-M1 = ΔM = ∫Vdx

Change in moment between two points = area under shear curve between two points

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V2-V1 = ΔV = ∫w(x)dx

Change in shear between two points = area under load curve between two points

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V&M Diagram Tips

  1. Always start and end at zero

  2. Concentrated loads cause jumps in shear diagram (up is +)

  3. Concentrated moments cause jumps in moment diagram (c-clockwise is +); causes no change to V-diagram

  4. At V=0, moment is a local minimum or maximum

  5. Always work V and M diagrams from left to right

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Areas

  • Trapezoid = ½ (a + b) x h

  • Parabolic = 2/3 (a x b)

  • Triangle = ½ (b x h)

  • Sub-parabolic = 1/3 (a x b)

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Uses of cables

  1. Suspension bridges

  2. Power transmission lines

  3. Tension only members

  4. Strand in prestressed tension

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Benefits of cables

  • Flexible

  • Light

  • Efficient

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Cross-section of a cable

Wires around a central core

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Typical Configurations of Cables

  • Parabolic

  • Catenary

  • Discrete

<ul><li><p>Parabolic</p></li><li><p>Catenary</p></li><li><p>Discrete</p></li></ul><p></p>
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W (cable)

Uniformly distributed load (in weight/length)

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To (cable)

Tension force in cable where θ = 0 (base of sag) —> horizontal component

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y (cable)

Vertical distance from base of sag to desired height

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Catenary Cable

  • Example: Power lines

  • At lower sag values, a parabolic approximation is good

  • Solved with computer analysis

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Discrete Cable

  • Neglect self-weight

  • Apply equations of equilibrium

  • Solve like a truss

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F (in terms of 3D Force)

Force vector

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F (in terms of 3D Force)

Magnitude of the force

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l, m, and n (in li+mj+nk)

Portion of direction

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n (in terms of 3D Force)

unit vector = (li + mj + nk)

where l2 + m2 + n2 = 1

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Right-hand rule (3D Forces)

  • Arrows indicate (+) direction

  • Using the right hand, run fingers in (+) x-direction, wrapping them around to the y-direction, and thumb is z-direction

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Moment (in 3D)

Mo = r x F

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Cross Product

<p></p>
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Notes about 3-Dimensional Equilibrium

  • ΣF = 0 (Fx, Fy, Fz = 0) and ΣM = 0 (Mx, My, Mz = 0)

  • The equilibrium conditions are independent of one another

  • All conditions must be met for complete equilibrium

  • Right-handed coordinate system with vector notation

  • Complete free-body diagram is very important

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Complete Fixity

Body is stable for translation and rotation (ΣF = 0, ΣM = 0)

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Incomplete Fixity

Body is not stable in all directions for translation and rotation

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Excessive Fixity

Body has redundant reactions

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Notes About Statical Determinancy

  • If > 6 reactions, indeterminate

  • If < 6 reactions, determinate but unstable

  • If = 6 reactions, determinate and stable

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Types of Friction

  • Dry friction (coulomb friction): occurs between two unlubricated solid surfaces

  • Fluid friction: occurs between adjacent layers in a fluid or gas

  • Internal friction: occurs in all solid materials subjected to cyclic loading

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Impending Motion

about to do something; either slip or tip

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μs and μk

coefficient of statics/kinetic friction

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Belt friction

Belts/cables/ropes wrapped around sheaves, drums, or pulleys

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How Belt Friction Works (Types of Cores)

  1. Fixed core: provides frictional resistance to the belt passing around it

  2. Rotating core: offsets the greater tension force, T2

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Examples of Pulleys

  • cranes

  • elevators

  • exercise equipment

  • sailboats

  • climbing gear

  • fishing reel

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x:1 Mechanical Advantage

  • x rope(s) “connected” to the weight

  • must cut x number of ropes for weight to fall (ignore the tension-part rope)

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Levers

F•d1 = W•d2

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Inclined Plane

F = Wsinθ

  • Raise weight up with little effort

  • Assuming low friction (use hand cart)

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Rollers

  • use levers to lift the object to be moved

  • place rollers (ex. pipes) under the object

  • move rollers from back to front as object moves