Chemistry Formulas and Physical Constants Review

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Comprehensive vocabulary flashcards covering fundamental physical chemistry formulas, physical constants, thermodynamic relationships, electrochemistry equations, and periodic trend proportionalities.

Last updated 6:41 PM on 9/4/26
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89 Terms

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Molar mass (MM)

M=massnumber of molesM = \frac{\text{mass}}{\text{number of moles}}

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Number of moles (nn)

n=massmolar massn = \frac{\text{mass}}{\text{molar mass}}

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Molarity

Moles of solute / volume of solution (in L\text{L})

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Molality

Moles of solute / mass of solvent (in kg\text{kg})

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Mole fraction of AA (xAx_A)

xA=nAnA+nBx_A = \frac{n_A}{n_A + n_B}

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Percentage by mass

(mass of solutemass of solution)×100\left(\frac{\text{mass of solute}}{\text{mass of solution}}\right) \times 100

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Empirical formula

Simplest whole-number ratio of atoms

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Molecular formula

n×(empirical formula)n \times (\text{empirical formula})

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Ideal gas equation

PV=nRTPV = nRT

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Bohr's quantization equation

mvr=nh2πmvr = \frac{nh}{2\pi}

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Radius of nthn\text{th} Bohr orbit

rn=n2h2Δ0πme2=n2a0r_n = \frac{n^2 h^2 \varepsilon_0}{\pi m e^2} = n^2 a_0, where a0=0.529 A˚a_0 = 0.529\,\text{Å}

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Energy of nthn\text{th} orbit (H\text{H} atom)

En=−13.6n2 eV=−2.18×10−18n2 JE_n = -\frac{13.6}{n^2}\,\text{eV} = -\frac{2.18 \times 10^{-18}}{n^2}\,\text{J}

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Frequency of revolution (Bohr)

Μ=v2πrn\nu = \frac{v}{2\pi r_n}

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Ionisation energy of H\text{H} atom

Ei=13.6n2 eVE_i = \frac{13.6}{n^2}\,\text{eV}

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De Broglie equation

λ=hmv\lambda = \frac{h}{mv}

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Planck's constant (hh)

6.626×10−34 J⋅s6.626 \times 10^{-34}\,\text{J}\cdot\text{s}

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Mass of electron (mem_e)

9.11×10−31 kg9.11 \times 10^{-31}\,\text{kg}

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Effective nuclear charge (ZeffZ_{\text{eff}})

Zeff=Z−σZ_{\text{eff}} = Z - \sigma (where σ=shielding constant\sigma = \text{shielding constant})

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Atomic radius proportionality

Proportional to 1Zeff\frac{1}{Z_{\text{eff}}}

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Ionization enthalpy proportionality

Proportional to Zeffn\frac{Z_{\text{eff}}}{n}

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Electron gain enthalpy proportionality

Proportional to −Zeffn-\frac{Z_{\text{eff}}}{n}

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Electronegativity proportionality

Proportional to Zeffn2\frac{Z_{\text{eff}}}{n^2}

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Trends across a period (left to right)

Atomic radius decreases, ionization enthalpy increases, electron affinity becomes more negative, electronegativity increases

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Trends down a group (top to bottom)

Atomic radius increases, ionization enthalpy decreases, electron affinity becomes less negative, electronegativity decreases

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Percent ionic character

(ÎŒobservedÎŒionic)×100\left(\frac{\mu_{\text{observed}}}{\mu_{\text{ionic}}}\right) \times 100

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Dipole moment (Ό\mu)

ÎŒ=q×r\mu = q \times r

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Percent s-character

(11+eΔE/RT)×100\left(\frac{1}{1 + e^{\Delta E / RT}}\right) \times 100

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Bond order

Nb−Na2\frac{N_b - N_a}{2} (bonding minus antibonding electrons, over 2)

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spsp hybridisation bond angle

180∘180^\circ (linear)

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sp2sp^2 hybridisation bond angle

120∘120^\circ (trigonal planar)

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sp3sp^3 hybridisation bond angle

109.5∘109.5^\circ (tetrahedral)

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sp3dsp^3d hybridisation bond angles

90∘90^\circ and 120∘120^\circ (trigonal bipyramidal)

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sp3d2sp^3d^2 hybridisation bond angle

90∘90^\circ (octahedral)

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Dipole moment in Debye

Ό (D)=4.803×q (esu)×r (cm)\mu\,(\text{D}) = 4.803 \times q\,(\text{esu}) \times r\,(\text{cm})

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Gas constant RR (two values)

0.0821 L⋅atm⋅mol−1⋅K−1=8.314 J⋅mol−1⋅K−10.0821\,\text{L}\cdot\text{atm}\cdot\text{mol}^{-1}\cdot\text{K}^{-1} = 8.314\,\text{J}\cdot\text{mol}^{-1}\cdot\text{K}^{-1}

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Boyle's law

PV=constantPV = \text{constant} (at constant TT and nn)

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Charles' law

V∝TV \propto T at constant PP; V1T1=V2T2\frac{V_1}{T_1} = \frac{V_2}{T_2}

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Avogadro's law

V∝nV \propto n at constant PP and TT; V1n1=V2n2\frac{V_1}{n_1} = \frac{V_2}{n_2}

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van der Waals equation

(P+an2V2)(V−nb)=nRT\left(P + \frac{a n^2}{V^2}\right)(V - nb) = nRT

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van der Waals constants aa and bb

a=attraction constanta = \text{attraction constant}, b=volume constantb = \text{volume constant}

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Heat at constant pressure (qq)

q=nCpΔTq = n C_p \Delta T

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Heat at constant volume (qq)

q=nCvΔTq = n C_v \Delta T

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First law of thermodynamics

ΔU=q+w\Delta U = q + w

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Pressure-volume work

w=−PextΔVw = -P_{\text{ext}} \Delta V

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Relation between ΔH\Delta H and ΔU\Delta U

ΔH=ΔU+Δ(ng)RT\Delta H = \Delta U + \Delta(n_g) RT

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Gibbs free energy

ΔG=ΔH−TΔS\Delta G = \Delta H - T\Delta S

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ΔG\Delta G for a cell reaction

ΔG=−nFE\Delta G = -nFE

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Relation between ΔG∘\Delta G^\circ and KeqK_{\text{eq}}

ΔG∘=−RTln⁡Keq\Delta G^\circ = -RT \ln K_{\text{eq}}, or Keq=e−ΔG∘/RTK_{\text{eq}} = e^{-\Delta G^\circ / RT}

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Equilibrium constant KcK_c

Kc=[C]c[D]d[A]a[B]bK_c = \frac{[C]^c [D]^d}{[A]^a [B]^b}

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Relation between KpK_p and KcK_c

Kp=Kc(RT)ΔnK_p = K_c (RT)^{\Delta n}

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Δn\Delta n in Kp=Kc(RT)ΔnK_p = K_c(RT)^{\Delta n}

Moles of gaseous products $$-$ moles of gaseous reactants

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ΔG∘\Delta G^\circ in terms of log⁡Kc\log K_c

ΔG∘=−2.303RTlog⁡Kc\Delta G^\circ = -2.303 RT \log K_c

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Value of 2.303R2.303 R

19.14 J⋅mol−1⋅K−119.14\,\text{J}\cdot\text{mol}^{-1}\cdot\text{K}^{-1}

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Nernst equation (at 298 K298\,\text{K})

Ecell=Ecell∘−(0.0591n)log⁡QE_{\text{cell}} = E^\circ_{\text{cell}} - \left(\frac{0.0591}{n}\right) \log Q

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EMF of a concentration cell

Ecell=(0.0591n)log⁥(C2C1)E_{\text{cell}} = \left(\frac{0.0591}{n}\right) \log\left(\frac{C_2}{C_1}\right)

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Relation between ΔG∘\Delta G^\circ and E∘E^\circ

ΔG∘=−nFE∘\Delta G^\circ = -nFE^\circ

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Faraday's law of electrolysis

m=ZItm = Z I t, where Z=E96500Z = \frac{E}{96500} (E=equivalent weightE = \text{equivalent weight}, I=current in AI = \text{current in A}, t=time in st = \text{time in s})

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1 Faraday

96500 C96500\,\text{C}

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pH

pH=−log⁡[H+]\text{pH} = -\log[\text{H}^+]

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pOH

pOH=−log⁡[OH−]\text{pOH} = -\log[\text{OH}^-]

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pH+pOH\text{pH} + \text{pOH} at 298 K298\,\text{K}

1414

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Ionic product of water KwK_w

[H+][OH−]=1.0×10−14[\text{H}^+][\text{OH}^-] = 1.0 \times 10^{-14} at 298 K298\,\text{K}

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KaK_a for a weak acid HA\text{HA}

Ka=[H+][A−][HA]K_a = \frac{[\text{H}^+][\text{A}^-]}{[\text{HA}]}

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KbK_b for a weak base B\text{B}

Kb=[BH+][OH−][B]K_b = \frac{[\text{BH}^+][\text{OH}^-]}{[\text{B}]}

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Relation between KaK_a and KbK_b

Ka×Kb=KwK_a \times K_b = K_w

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Relation between pKa\text{pK}_a and pKb\text{pK}_b

pKa+pKb=14\text{pK}_a + \text{pK}_b = 14

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Hydration enthalpy proportionality

Proportional to 1ionic radius\frac{1}{\text{ionic radius}}

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Lattice enthalpy proportionality

Proportional to z+z−r0\frac{z^+ z^-}{r_0}

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Solubility product for AmBn\text{A}_m\text{B}_n

Ksp=[An+]m[Bm−]nK_{\text{sp}} = [\text{A}^{n+}]^m [\text{B}^{m-}]^n

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Common ion effect

Solubility decreases on adding a common ion

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Acidic strength of oxyacids of the same element

Increases with number of O\text{O} atoms

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Oxidising strength of oxyacids

Increases with oxidation number of the central atom

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Disproportionation of H2O2\text{H}_2\text{O}_2

2H2O2→2H2O+O22 \text{H}_2\text{O}_2 \rightarrow 2 \text{H}_2\text{O} + \text{O}_2 (H2O2\text{H}_2\text{O}_2 acts as both oxidising and reducing agent)

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General formula of alkanes

CnH2n+2\text{C}_n\text{H}_{2n+2}

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General formula of alkenes

CnH2n\text{C}_n\text{H}_{2n}

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General formula of alkynes

CnH2n−2\text{C}_n\text{H}_{2n-2}

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General formula of mono-aromatics

CnH2n−6\text{C}_n\text{H}_{2n-6}

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Degree of unsaturation

DU=2C+2+N−H−X2\text{DU} = \frac{2C + 2 + N - H - X}{2}, where X=halogenX = \text{halogen}

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Wurtz reaction

2R–X+2Na→R–R+2NaX2\text{R–X} + 2\text{Na} \rightarrow \text{R–R} + 2\text{NaX}

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Wurtz–Fittig reaction

R–X+R’–X+2Na→R–R’+2NaX\text{R–X} + \text{R'–X} + 2\text{Na} \rightarrow \text{R–R'} + 2\text{NaX}

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Kolbe's electrolysis

2RCOO−Na++2H2O→R–R+2CO2+H2+2NaOH2\text{RCOO}^-\text{Na}^+ + 2\text{H}_2\text{O} \rightarrow \text{R–R} + 2\text{CO}_2 + \text{H}_2 + 2\text{NaOH}

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Avogadro's number

NA=6.022×1023 mol−1N_A = 6.022 \times 10^{23}\,\text{mol}^{-1}

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Speed of light

c=3.00×108 m⋅s−1c = 3.00 \times 10^8\,\text{m}\cdot\text{s}^{-1}

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Charge on an electron

e=1.602×10−19 Ce = 1.602 \times 10^{-19}\,\text{C}

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Faraday constant

F=96500 C⋅mol−1F = 96500\,\text{C}\cdot\text{mol}^{-1}

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Boltzmann constant

kB=1.381×10−23 J⋅K−1k_B = 1.381 \times 10^{-23}\,\text{J}\cdot\text{K}^{-1}

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Standard pressure

1 atm=1.013×105 Pa1\,\text{atm} = 1.013 \times 10^5\,\text{Pa}

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Standard temperature

298 K=25 ∘C298\,\text{K} = 25\,^\circ\text{C}

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ΔG\Delta G in terms of ΔG∘\Delta G^\circ and QQ

ΔG=ΔG∘+RTln⁡Q\Delta G = \Delta G^\circ + RT \ln Q