Lecture 7 hydrology

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15 Terms

1
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what are the components of stream flow?

Direct channel precipitation (minor), overland flow (surface runoff), interflow (minor), baseflow (groundwater contribution to stream discharge)

2
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How to develop a “synthetic” hydrograph

Use a unit hydrograph (UH)

3
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Direct runoff hydrograph (DRH) a result of?

resulting from one unit (1 in or 1 cm) of effective rainfall (ER) occurring at a uniform rate, uniformly distributed over a watershed. With ER uniformly distributed within its duration or specified period of time and is uniformly distributed throughout the drainage-basin area

4
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for all uniform intensity storms of the same length and given drainage basin, what can we assume about the duration of direct runoff? (assumption 1)

duration of direct run off is constant

5
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For a given drainage basin, if two uniform-intensity storms of the same length produce different total volumes of direct runoff, what can we assume about the rates of direct runoff? (assumption 2)

the rates of direct runoff at corresponding times t, after the beginning of two storms, are in the same proportion to each other as the total volumes of direct runoff

6
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what is the relation between The time distribution of direct runoff from a given storm period and concurrent runoff from antecedent storm periods? (assumption 3)

they are independent

7
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principle of porportionality

assumptions 1 and 2

8
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principle of superposition

the total direct runoff resulting from multiple storm events is equal to the sum of the direct runoff from each individual storm event, assuming uniform conditions. (a.k.a assumption 3)

9
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complex effective rain hyetograph (ERH) of d-hour duration

With I as a constant ER intensity

<p>With I as a constant ER intensity</p>
10
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Formula for discharge with DRH (direct runoff hydrograph)

With I as a constant ER intensity (L/T), the D-hour UH as h(D, t), and the resulting DRH as Q(t), where ID denotes the depth of ER

<p>With I as a constant ER intensity (L/T), the D-hour UH as h(D, t), and the resulting DRH as Q(t), where ID denotes the depth of ER</p>
11
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When ID = 1, what can we say about UH and DRH

they are numerically the same

12
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find DRH of three UHs

If we don’t have a specified amount of UHs, then we change the 3 on top of the summation to be some constant n

<p>If we don’t have a specified amount of UHs, then we change the 3 on top of the summation to be some constant n</p>
13
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When do we use summation hydrograph (SH)

If the duration of ER is indefinitely long and its intensity is one unit per unit of time (say, 1 cm/hr)

<p>If the duration of ER is indefinitely long and its intensity is one unit per unit of time (say, 1 cm/hr)</p>
14
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If we want to change the duration of UH, what can we do? (with a multiple of D)

To create a Unit Hydrograph (UH) for a duration that’s a whole-number multiple of DD (e.g., 2D2D, 3D3D, etc.), simply apply the principle of superposition. This means adding together shifted and scaled versions of the original DD-hour UH.

<p>To create a Unit Hydrograph (UH) for a duration that’s a whole-number multiple of <span>DD</span> (e.g., <span>2D2D</span>, <span>3D3D</span>, etc.), simply apply the principle of superposition. This means adding together shifted and scaled versions of the original <span>DD</span>-hour UH.</p>
15
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Steps to extend for a duration thats not a multiple of D

1Construct the SH using given UH
2. Offset the position of SH by a period equal to the desired duration of D* hours
3. Compute the difference b/t the ordinates of these two SHs
4. Divide the differences in the ordinates by n, where n= D*/D