Year 9 Engineering Geometry: Similarity and Pythagoras' Theorem

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Vocabulary and essential concepts from the Year 9 Engineering Geometry Practice Test covering similarity tests, Pythagoras' theorem, and scale factors.

Last updated 10:18 AM on 8/11/26
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15 Terms

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Hypotenuse

The longest side of a right-angled triangle, located directly opposite the right angle.

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Pythagoras' Theorem

The formula used to find missing side lengths in right-angled triangles, expressed as a2+b2=c2a^2 + b^2 = c^2 where cc is the hypotenuse.

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AA Similarity Test

A test to prove two triangles are similar if two corresponding angles are equal (which implies the third angle must also be equal).

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SSS Similarity Test

A test to prove similarity where the ratios of all three corresponding side pairs are equal, such as 10/4=15/6=20/8=2.510/4 = 15/6 = 20/8 = 2.5.

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SAS Similarity Test

A test to prove similarity where two pairs of corresponding sides are in the same ratio and their included angles are equal.

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Scale Factor

The value calculated by dividing a length in one similar shape by the corresponding length in the other, such as 15×6=2.515 \times 6 = 2.5.

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Similarity Statement

A mathematical notation using the squiggle symbol (\sim) to show two shapes are similar with vertices in corresponding order, such as ABCDEFABC \sim DEF.

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Scale (e.g., 1:20)

A ratio used in engineering drawings where 11 unit of measurement on the model or drawing represents a specific number of units (e.g., 2020) on the full-size object.

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Verification of a Right Angle

The process of checking if the squared sum of the two shorter sides equals the square of the longest side (a2+b2=c2a^2 + b^2 = c^2); if equal, the triangle is right-angled.

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12212^2

The square of 1212, which equals 144144.

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17217^2

The square of 1717, which equals 289289.

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196\sqrt{196}

The square root of 196196, which equals 1414.

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70\sqrt{70} (to 1 decimal place)

The square root of 7070, approximately equal to 8.48.4.

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Metric Conversion: Centimetres to Metres

The process of dividing a length in centimetres by 100100 to find the equivalent length in metres, such as 320cm=3.2m320\,cm = 3.2\,m.

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Corresponding Sides

Pairs of sides that occupy the same relative position in two similar figures, such as side ABAB in triangle ABCABC matching side DEDE in triangle DEFDEF.