Maths

studied byStudied by 4 people
0.0(0)
Get a hint
Hint

The Trapezium rule

1 / 78

flashcard set

Earn XP

Description and Tags

Not finished

79 Terms

1

The Trapezium rule

Area = 0.5 h (y0 + y3 + 2 (y1 + y2)

First + last + (2 x rest)

New cards
2

Variable acceleration

Integrate Integrate

S V A

Differentiate Differentiate

New cards
3

Simple random sampling

Takes a random selection from the population to use as a sample. The entire population must be known and identifiable. Each random sample will be different and some will contain bias. The probability of a strongly biased sample is reduced as sample size increases.

New cards
4

Stratified sampling

If the parent population has clear subgroups, it is possible to take a sample. The quick calculation to determine the number for each subgroup to be randomly selected as part of the sample is: (number in subgroup/ number in population) x sample size. This technique requires a lot of information to begin about the population.

New cards
5

Quota sampling

Similar to stratified, though the ā€˜quotaā€™ of items to be included from different subgroups isnā€™t necessarily proportional. It also doesnā€™t require a random sample from within the subgroup, so bias is extremely likely.

New cards
6

Systematic sampling

A method where a sample is selected from a population at regular intervals; for example, every 10th individual in a list. This method is straightforward but can introduce bias if there's a hidden pattern in the population.

New cards
7

Midpoints

((X1+X2)/2), ((Y1+Y2)/2)

New cards
8

Distance between two points

āˆš((x_2-x_1)Ā²+(y_2-y_1)Ā²)

New cards
9

Gradient of a chord

Y2-Y1/X2-X1

New cards
10

Parallel lines

The same gradient

New cards
11

Perpendicular lines

Negative reciprocal gradient

New cards
12

Y intercept

When X=0

New cards
13

X intercept

When Y=0

New cards
14

Perpendicular bisector

1) midpoint

2) neg recip gradient

3) Y-Y1= M(X-X1)

4) rearrange into Y=MX+C

New cards
15

Quadratic formula

<p></p>
New cards
16

Discriminant

BĀ²-4ac

New cards
17

One real root

When the discriminant = 0

New cards
18

Two distinct roots

When the discriminant > 0

New cards
19

No real roots

When the discriminant <0

New cards
20

Two rational roots

Perfect square

(X+ 1/2b)Ā² +0

New cards
21

1000= 10Ā³

Log10(1000)=3

New cards
22

LogbB

1

New cards
23

Logb1

0

New cards
24

LogcA+logcB

LogcAB

New cards
25

LogcA-logcB

LogcA/B

New cards
26

Logc(A^B)

BlogcA

New cards
27

LogcāˆšA

1/2logcA

New cards
28

LogeX

lnX

New cards
29

If f(a/b) = 0

Then (bx-a) is a factor

New cards
30

If it isnā€™t a factor

It is a remainder

New cards
31

Remainder Theorem

The Remainder Theorem states that if a polynomial f(x) is divided by (x-a), the remainder is equal to f(a). This can be used to quickly find remainders without completing the full division.

New cards
32

Y=X

knowt flashcard image
New cards
33

Y=XĀ²

knowt flashcard image
New cards
34

Y=XĀ³

knowt flashcard image
New cards
35

Y= 1/X

knowt flashcard image
New cards
36

YĀ²+XĀ²=rĀ²

knowt flashcard image
New cards
37

Translation of Y=f(x) by the vector [ab]

Y=f(X-a)+b

New cards
38

Stretch on the x axis by the factor k

Y=f(1/k X)

New cards
39

Stretch on the Y axis by the factor K

Y=KF(X)

New cards
40

Reflection on the x axis

Y= -f(x)

New cards
41

Reflection on the y axis

Y=f(-X)

New cards
42

Reflection on y=x

Swap the x and y

Eg. Y=f(x) ā†¦ X=f(y)

New cards
43

Finding the centre and radius of a circle

Complete the square

New cards
44

Circle theorem

If <ABC = 90Ā°, then AC is a diameter of the circle with A,B,C on the circumference

New cards
45

Tangent

Line touching a circle at a distinct point

New cards
46

Normal

Line perpendicular to tangent

New cards
47

Given Y= ab^x

Log10Y= log10A+ log10B

Exponential curve

Log10Y and X

1) take logs of both sides

2) simplify

Gradient= log10b

Y intercept = log10a

New cards
48

Y=aX^b

Log10Y= log10A+Blog10X

Polynomial line

Log10Y and log10X

1) take logs of both sides

2) simplify

Gradient= b

Y intercept = log10a

New cards
49

Natural numbers

Positive integers

New cards
50

Integers

All numbers on the numberline

New cards
51

Rational numbers

Fractions

New cards
52

Reals

All numbers you can think of (Ļ€, e, 1/3, āˆš2, 500, -2)

New cards
53

Set notation

{x:x āˆˆ R, a<x<b}

New cards
54

Interval notation

x āˆˆ (a,b)

( is not including

[ is including

New cards
55

Differentiation in first prinicples

<p></p>
New cards
56

Average speed

Total distance

ā€”ā€”ā€”ā€”ā€”ā€”ā€”

Time

New cards
57

Average velocity

Total displacement

ā€”-ā€”ā€”ā€”ā€”ā€”ā€”ā€”ā€”

Time

New cards
58

Velocity- time graph into acceleration-time

Acceleration= gradient of velocity

New cards
59

Circle property diameter

The triangle formed from the ends of a diameter has a right angle

New cards
60

Circle property chord

The perpendicular from the centre to a chord bisects the chord

New cards
61

Circle property tangent

A tangent to the circle meets a radius at a right angle

New cards
62

Sin2x

2sinxcosx

New cards
63

Cos2x

  1. SinĀ²x-cosĀ²x

  2. 1-2sinĀ²x

  3. 2cosĀ²x-1

New cards
64

Tan2x

2tanx


1-tanĀ²x

New cards
65

CosecĀ²x

1+cotĀ²x

New cards
66

SecĀ²x

1+tanĀ²x

New cards
67

Cosecx

1


Sinx

New cards
68

Secx

1


cosx

New cards
69

Cotx

1


tanx

New cards
70

Tanx

Sinx


cosx

New cards
71

Cotx

Cosx


sinx

New cards
72

Moment- clockwise

Negative NM

New cards
73

Moment- anticlockwise

Positive NM

New cards
74

What is a resultant moment

The sum of all moments acting on a particle (negative and positive)

New cards
75

Finding resultant moment

  1. Decide which force direction is clockwise and anticlockwise.

  2. Work out each moment.

  3. Sum all together and subtract clockwise moments.

  4. The overall value is the resultant moment.

New cards
76

When a moment is in equilibrium

The resultant force is 0N and the resultant force about any point is 0NM

New cards
77

Solving problems with moments in equilibrium

  1. Identify ALL perpendicular distances and ALL forces from the pivot

  2. Use the fact that resultant force is 0 in the equation and the fact that the resultant moment is 0 in the other equation

  3. If you have an unknown force you can pick a pivot point that is on the same ā€œline of actionā€ so that unknown force is 0NM

  4. Solve equations

<ol><li><p>Identify ALL perpendicular distances and ALL forces from the pivot</p></li><li><p>Use the fact that resultant force is 0 in the equation and the fact that the resultant moment is 0 in the other equation</p></li><li><p>If you have an unknown force you can pick a pivot point that is on the same ā€œline of actionā€ so that unknown force is 0NM</p></li><li><p>Solve equations</p></li></ol>
New cards
78

Method for Solving A Level Maths Question on Tilting Rods using Moments

1. Identify all forces acting on the rod. 2. Calculate the moment for each force (Moment = Force x perpendicular distance). 3. Determine the pivot point. 4. Sum the clockwise moments and anticlockwise moments. 5. Set the total moments equal to zero for equilibrium. 6. Solve the resulting equation for unknown forces.

New cards
79

AĀ³ x AĀ²

3+2=5 so A^5

New cards

Explore top notes

note Note
studied byStudied by 17 people
... ago
5.0(2)
note Note
studied byStudied by 7 people
... ago
5.0(1)
note Note
studied byStudied by 66 people
... ago
4.0(1)
note Note
studied byStudied by 17 people
... ago
5.0(1)
note Note
studied byStudied by 18 people
... ago
5.0(2)
note Note
studied byStudied by 16 people
... ago
5.0(1)
note Note
studied byStudied by 7 people
... ago
5.0(1)
note Note
studied byStudied by 1240 people
... ago
4.9(9)

Explore top flashcards

flashcards Flashcard (26)
studied byStudied by 29 people
... ago
5.0(3)
flashcards Flashcard (33)
studied byStudied by 113 people
... ago
5.0(1)
flashcards Flashcard (53)
studied byStudied by 4 people
... ago
5.0(1)
flashcards Flashcard (20)
studied byStudied by 7 people
... ago
5.0(1)
flashcards Flashcard (46)
studied byStudied by 61 people
... ago
5.0(1)
flashcards Flashcard (100)
studied byStudied by 2 people
... ago
5.0(1)
flashcards Flashcard (145)
studied byStudied by 15 people
... ago
5.0(1)
flashcards Flashcard (32)
studied byStudied by 22 people
... ago
5.0(1)
robot