Chem Semester 1 Final

5.0(1)
studied byStudied by 5 people
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
Card Sorting

1/70

flashcard set

Earn XP

Description and Tags

screaming crying why do we have to pay for quizlet

Chemistry

Study Analytics
Name
Mastery
Learn
Test
Matching
Spaced

No study sessions yet.

71 Terms

1
New cards
Cation
metals lose e-
always smaller than original molecule
2
New cards
Anion
nonmetals gain e-
always larger than original molecule
3
New cards
Atomic/Ionic Radius
increases as you go down because more e- shells

decreases as you go across because stronger nuclear charge pulls e- in closer
4
New cards
Ionization Energy
decreases as you go down because it's easier to remove an e- farther from the nucleus

increases as you go across because the e- are closer to the nucleus so it's harder to remove them
5
New cards
Electronegativity
decreases as you go down, atoms become more metallic and want to get rid of e-

increases as you go across, atoms become more nonmetallic and want to gain e- to form an octet

*noble gases excluded because they have an octet
6
New cards
Exceptions to Ionization Energy
all of 3A and 6A because of e- pairing
(consult orbital diagram notes for further explanation)
7
New cards
Coloumbic Forces
1. charge of ion
2. size/atomic radius of ion

high charge + small radius = larger lattice energy and stronger attraction and vice versa
8
New cards
Ionic Compounds
- formed when metal transfers VE to nonmetals
- ions arrange themselves in a crystal lattice
- held together via strong electrostatic attractions
- high melting point
- if dissolved in a polar solvent, will form an electrolytic solution
9
New cards
Covalent Compounds
- formed when nonmetals share VE to achieve octet
- covalent bonds form molecules
- held together via IMF, not chemical bonds
- low melting points
- never forms an electrolytic solution

*network covalent compounds don't dissolve
10
New cards
Substitutional Alloy
formed between 2 atoms of similar atomic radii
11
New cards
Interstitual Alloy
formed from 2 metals of vastly different radii
- smaller atom fills up empty spaces between larger atoms and results in a more durable structure
12
New cards
Bond Strength
triple > double > single

stronger bond = shorter length
13
New cards
2 domains: 2 bonding pairs
linear
180°
sp
14
New cards
3 domains: 3 bonding pairs
trigonal planar
120°
sp2
15
New cards
3 domains: 2 bonding pairs, 1 nonbonding pair
bent
16
New cards
4 domains: 4 bonding pairs
tetrahedral
109.5°
sp3
17
New cards
4 domains: 3 bonding pairs, 1 nonbonding pair
trigonal pyramid
18
New cards
4 domains: 2 bonding pairs, 2 nonbonding pairs
bent
19
New cards
ΔHrxn=ΣΔHbroken + ΣΔHformed
bond enthalpy: energy absorbed/released in a rxn

need the lewis structure for this one

ΔHrxn > 0 --> endothermic rxn
ΔHrxn < 0 --> exothermic rxn
20
New cards
Formal Charges
FC = # of VE in free atom - # of bonds - # of unbonded e-
21
New cards
Resonance Structures
occurs when e- shift to form alternative lewis structures
22
New cards
Resonance Stability
- all atoms must have complete octet
- formal charges kept @ minimum
- if formal charges are present, the negative charge is on the more electronegative element
23
New cards
Net Ionic Equations
1. write the balanced chemical equation
2. write the complete ionic equation
3. cancel out the common ones basically, then you get the net ionic equation
24
New cards
Limiting/Excess Reagents
1. write the equation
2. figure out what's limiting: convert grams to moles then use balanced chemical equation to figure out what's limiting
3. calculate how much was used and how much is left
25
New cards
Molarity
M = n/v

n = moles of solute

v = volume of solution in L
26
New cards
Solution Stoichiometry
idk man just figure out what you’re given and do the stoichiometry
27
New cards
Preparing Solutions: From Scratch
use M = n/v
28
New cards
Preparing Solutions: From Stock Solution
use M1V1 = M2V2
29
New cards
Factors That Influence Pressure

1. volume: lower volume = higher pressure
* does not increase particle speed
2. moles of gas: more moles of gas = higher pressure
3. temperature: higher temp = higher pressure
30
New cards
Gas Laws
P1V1 = P2V2

V1/T1 = V2/T2

P1/T1 = P2/T2

\
PV = nRT

* remember the difference between both R constants; this one is 0.08206 L\*atm / mol\*K

ideal gas conditions: high temp & low pressure
31
New cards
Mole Fractions
you can either use PV = nRT with only the moles of the gas you want, or calculate total pressure then multiply by the fraction of moles of gas
32
New cards
Kinetic Molecular Theory
* volume of individual gases is negligible relative to the total volume
* kinetic energy is only affected by temperature

\
graph is molecular speed vs fraction of molecules

lower temp: shift left w/ steeper curve

higher temp: shift right w/ less steep curve
33
New cards
Effusion/Diffusion
any atom/molecule with a smaller mass will effuse/diffuse faster
34
New cards
Polar Molecules
polar bonds: nonmetal bonded to F, O, N, Cl

* fluorine is the most electronegative element

\

a symmetrical molecule or a molecule with no polar bonds is nonpolar

\
an asymmetrical molecule with at least 1 polar bond is polar
35
New cards
IMFs
* **not** a chemical bond

strong IMF = low vapor pressure = high melting/boiling point
36
New cards
Ionic Bonds
* formed when a positive ion bonds w/ a negative ion via electrostatic attraction

\
Ion Dipole: attraction between a polar molecule & ion
37
New cards
Hydrogen Bonds
* strongest IMF
* only occurs in polar molecules with H is bonded to F, O, or N and is attracted to lone pairs on another molecule
* any molecule capable of H-bonding is also capable of D-D
38
New cards
Dipole-Dipole
* all polar molecules are capable of exerting these
* occurs when lone pairs on more EN atom are attracted to the partially positive atom on the other molecule
39
New cards
London Dispersion Forces (including shape of molecule)
* present in all molecules
* having more electrons makes it more polarizable (easier to separate charges) which means a stronger LDF
* the larger the molecule, the stronger the LDF

\
if 2 molecules have the same formula, the one with a more linear structure will have a stronger LDF due to more surface area of interaction
40
New cards
Empirical Formulas
1: write mass %s as grams

2: convert to moles

3: divide all values by the smallest mole value

4: round to the nearest whole number unless it ends in 0.20, 0.25, 0.33, or 0.5

5: divide the molar mass of the compound by the empirical mass to get the ratio

e.g. molar mass is 162.1, empirical mass is 81 so since 162.1/81 = 2, the molecular formula will be C10H14N2 instead of C5H7N
41
New cards
Hydrated Salts
always written as salt \* XH2O where X = whole number

\
1: determine mass of dry salt and of H2O

2: convert both to moles

3: divide mole values by the smallest mole value, which should always be the salt
42
New cards
Orbital Diagrams
just make sure one arrow is up and one is down

* more stable when they are either 1/2 full or completely full
* make sure each orbital has at least 1 electron before pairing up any
43
New cards
Electromagnetic Radiation
C = λν

\
C = speed of light: 3.0 x 10^8 m/s

λ = wavelength in m (convert nanometers to m)

ν = frequency in 1/s or Hz

\
6\.02 x 10^23 photon/mol
44
New cards
Planck's Equation
E = hν

\
E = energy per photon in J/photon

h = Planck’s Constant: 6.63 x 10^-34 J*****s

ν = frequency in 1/s or s^-1

\
6\.02 x 10^23 photon/mol
45
New cards
Thermochemistry
system: the object which heat measurement is in reference to

surrounding: everything that isn’t the system

\
endothermic: system temp increases, surrounding temp decreases

\
exothermic: system temp decreases, surrounding temp increases

\
* exothermic: __**ex**__udes heat
46
New cards
Molar Enthalpy in relation to energy
ΔHsol = q/n

\
q = energy in KJ

n = moles of solute

\
measured in KJ/mol
47
New cards
Phase Change Using ΔHfus and ΔHvap
ΔHfus: melt/freeze 6.01 KJ/mol

ΔHvap: vaporize/condense 40.7 KJ/mol

\
melting & vaporizing are endothermic so positive ΔH

freezing & condensing are exothermic so negative ΔH

\
1: bring to phase change temp (either 0 or 100C) using

q = MCΔT

2: phase change calculations using q = nΔHvap/fus

3: bring to final temp using q = MCΔT

4: add up all the energy changes
48
New cards
Enthalpy of Rxn: Stoichiometry
A+B -> C+D
endo: energy is a reactant

exo: energy is a product

\
ΔH is measured in KJ/ __**mol rxn**__
49
New cards
Enthalpy of Formation
ΔHrxn = nΣΔHproducts - nΣΔHreactants

* pure elements will always have ΔHformation of 0 KJ/mol
50
New cards
Hess's Law
just cancel things out, reverse the signs if necessary, and add them all up
51
New cards
Entropy
ΔS = nΣΔSproducts - nΣΔSreactants

* usually measured in J/mol\*K
* positive ΔS = increasing disorder (favorable)
* negative ΔS = decreasing disorder
52
New cards
Factors That Affect Entropy

1. temperature: higher temp = higher ΔS due to more molecular movement
2. # of particles: more moles = higher ΔS
3. size of molecule: larger molecule = more atoms = higher ΔS due to more vibrational motion
4. physical state: gas has highest ΔS
53
New cards
Gibbs Free Energy (all equations)
ΔG = ΔH - TΔS

* Gibbs is in KJ/mol so convert ΔS to KJ instead of J

ΔG = -RTln(K)

* this R constant is 8.314 J/mol\*K or 0.008314 KJ/mol\*K

ΔG = nΣΔGproducts - nΣΔGreactants

\
\-ΔG means spontaneous rxn & means K>1

\+ΔG means nonspontaneous rxn & means K
54
New cards
Spontaneity Table
\-ΔH and + ΔS = spontaneous @ all temps

\+ΔH and -ΔS = nonspontaneous @ all temps

\-ΔH and -ΔS = spontaneous only @ low temps

\+ΔH and +ΔS = spontaneous only @ high temps
55
New cards
Reaction Quotient
Q = \[C\]^c\[D\]^d/\[A\]^a\[B\]^b

\
Q is unitless and measures the ratio of products to reactants at all conditions but equilibrium
56
New cards
Equilibrium Expression
Keq = \[C\]^c\[D\]^d/\[A\]^a\[B\]^b

\
Keq is unitless and measures the ratio of products to reactants at equilibrium
57
New cards
Rates of Rxn
basically slope; measured in M/s
58
New cards
Criteria for Rxn to Occur
* particles must collide in order to react
* particles must collide in correct orientation (Tetris)
* particles must collide w/ enough energy to meet activation energy requirement
59
New cards
Rates of Rxn Graphs
activation energy: reactants to peak

ΔH: reactants to products

\
endo: reactants lower than products

exo: reactants higher than products
60
New cards
Factors Affecting Rxn Rate

1. concentration: higher concentration = faster rxn
2. temperature: higher temp = faster rxn
3. surface area: exposing more surface area = faster rxn (basketball vs ping pong balls example)
4. catalyst: adding a catalyst = faster rxn (duh)
* catalyst lowers activation energy
61
New cards
Q < K
too many reactants!
shift right to produce more products
62
New cards
Q > K
too many products!
shift left to produce more reactants
63
New cards
negative ΔG correlates with:
spontaneous reaction
more products than reactants present
K > 1
64
New cards
positive ΔG correlates with:
nonspontaneous reaction
more reactants than products present
K < 1
65
New cards
Rate Laws
Rate (M/s) = k[A]^x[B]^y
A and B are the concentration/molarity of the reactants
x and y are the rate orders
k is the rate constant with units dependent upon order

If the overall order (sum of x and y) is 0, the units of k are M/s
66
New cards
What affects kinetic energy?
temperature
67
New cards
What are the units of k?
0th order: M/s

1st order: 1/time

2nd order: 1/M\*time
68
New cards
Integrated Rate Law for 0th Order:
\[x\] = -kt + \[x\]initial
69
New cards
Integrated Rate Law for 1st Order:
ln\[x\] = -kt + ln\[x\]initial
70
New cards
Integrated Rate Law for 2nd Order:
1/\[x\] = kt + 1/\[x\]initial
71
New cards
What do you use integrated rate laws for?
if you are only given time and concentration data and are asked to determine rate order