1/3
Looks like no tags are added yet.
No study sessions yet.
∫sec²ax dx
∫sec
(tan ax) / a +c
∫cosec²ax dx
∫cosec
(-cot ax)/ a +c
∫sec ax tanax dx
∫sec ax tan
(sec ax)/ a +c
∫cosec ax cot ax dx
∫cosec ax cot ax
(-cosec ax)/ a +c