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projectile motion overview
a projectile is an object not in contact with the ground that is allowed to move under the influence of gravity and no other external force
acceleration of the object is constant - uniform acceleration
human body can be considered a projectile whenever it is airborne
running, jumping, falling, etc.
due to constant acceleration on everything due to gravity we can use equations to predict where an object that is in flight will be if we know certain variables
an object in flight on earth will always follow a parabolic path
use calculus to derive the equations of motion and use these equations to solve for an objects kinetic values as it travels through space
parabolic flight path
need to think about force vercotrs and derive equations of motion
we know that when we throw an object it will follow a parabolic path
when object is released or thrown it has only one force of gravity acting on it
need to consider x and y components separately
if object is thrown vertically acceleration equation would be ay(t) = -9.81m/s2
to determine velocity and displacement we would need to integrate acceleration
projectile features
at apex vertical velocity is zero
apex is the higher point achieved
if a projectile takes off and lands at the same height then
apex occurs at ½ the total flight time
vertical component of velocity at the beginning of the flight is equal but opposite to the vertical component at end of flight
horizontal projective kinematics
horizontal velocity stays constant throughout the flight
results in horizontal displacement defined by the time that it takes the object ot rise and fall vertically
both vertical and horizontal kinematics of a projectile that defines the parabolic flight path
Vx(t) = V0x
to find the equation for displacement we find the integral
dx(t) = voxt + dox
horizontal and vertical velocity
both components together demonstrate why the object has a parabolic path
adding both components allows us to see resultant velocity vectors in the direction of the parabolic flight
as we would expect
optimal angles of release
optimal angle for height is different than for distance
assuming magnitude of velocity cannot be altered
optimal angle for height is 90º or straight up
optimal angle for distance is 45º
looking at initial velocity to optimizer both time in air and horizontal displacement
vertical projectile motion equations
ay(t) = -9.81 m/s2
Vy(t) = -9.81 m/s2 + Voy
dy(t) = -9.81 m/s2 + Voy + doy
horinzontal projectile motion equations
ay(t) = 0 m/s2
Vy(t) = Vox
dy(t) = Vox + dox
common equipment for projectile motion
jump mat
measures time in air and outputs jump height
used operational amplifiers with acceleration and velocity to calculate jump height
force plate
measures time n the air and calculates initial velocity
iPod (IMU integrated w/I phone)
jump time app
measures period of time when accelerometer doesn’t measure any force
time in air and equations to determine jump height
projectile motion equation strategies
determine what is asked for and draw diagram
list all known variables
include those given in the question and those that can be solved without calculation
derive the equations off option and choose equation that allows you to use your variables to solve for the answer ot the question
may take more than one step to solve for other unknowns first
plug in variables and solve for answer
check if variables seem reasonable