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Trends in group 7: Electronegativity
Electronegativity decreases
The number of principle energy levels increases
There is a weaker attraction between the nucleus and outer electron in a covalent bond
Trends in group 7: Boiling point
Boiling point increases
The size of the atom increases, so there are more electrons
There are more London forces between the molecules that need to be broken
Fluorine at Room Temperature: F2
Pale yellow gas
Chlorine at Room Temperature: Cl2
Pale green gas
Bromine at room temperature: Br2
Dark red/orange liquid
Iodine at Room Temperature: I2
Dark purple/black solid
What happens when a halogen acts as an oxidising agent?
It gains an electron and is reduced
½ X2 + e- → X-
Why does the ability of a halogen to act as an oxidising agent decrease as you go down the group?
Atomic radius increases
Shielding increases
Gains an electron less easily
Observation when a chlorine ion displaces a bromine gas
No visible change
Observation when a chlorine ion displaces a iodine gas
No visible change
Observation when a bromine ion displaces a chlorine gas
Yellow solution
Observation when a bromine ion displaces a iodine gas
No visible change
Observation when a iodine ion displaces a chlorine gas
Aqueous solution - Brown
Organic solution - Purple
Observation when a iodine ion displaces a bromine gas
Aqueous solution - Brown
Organic solution - Purple
Ionic equations for displacement reactions
2Br- + Cl2 → 2Cl-+ Br2
2I- + Cl2 → 2Cl- + I2
2I- + Br2 → 2Br- + I2
Reagents and conditions to identify halide ions in solution
Reagents - Silver Nitrate
Conditions - Acidified
Observation of silver halides
AgF - No visible change
AgCl - White ppt
AgBr - Cream ppt
AgI - Yellow ppt
How to distinguish between AgCl and AgBr
Add dilute Ammonia as AgCl dissolves, AgBr does not
How to distinguish between AgBr and AgI
Add concentrated Ammonia as AgBr dissolves, AgI does not
Ionic equations of silver halide ions
Ag+(aq) + Cl-(aq) → AgCl(s)
Ag+(aq) + Br-(aq) → AgBr(s)
Ag+(aq) + I-(aq) → AgI(s)
Disproportionation
Oxidation and Reduction of the same element
What is the correct sequence to test for inorganic ions?
Carbonate
Sulfate
Halide
Carbonate test
React CO32- with Nitric Acid
2H+ + CO32- → H2O + CO2
If present we would get on observation of Effervescence
Sulfate test
Add Barium nitrate
Ba2+(aq) + SO42-(aq) → BaSO4
If Sulfate ions are present we would observe a white ppt
Test for cations
Ammonium salt is heated with aqueous sodium hydroxide to produce ammonia gas
NH4+(aq) + OH-(aq) → NH3(g) + H2O
Observation - Turns moist litmus paper blue