Unit 10 - Non-parametric statistics

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when is non-parametric procedure used?

nominal (categorical) and ordinal (ranked)

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common parametric procedure asumptions

parametric procedures can tolerate some violations:

- interval or ratio data: the data being analyzed should be measured on an interval or ratio scale,

- N (0,1): The data should follow a normal distribution, or approximately normal, which means that it has a bell-shaped curve

- Homogeneity of variance: The variance, or the spread of the data, should be the same across different groups or conditions being compared.

severe violation:

- highly skewed distribution (not following norm distribution)

- increased probability of committing type i error

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what if data was interval or ratio?

- data is highly skewed

- outliers will pull the group mean into one direction

- convert raw data to RANKS

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advantage of converting raw data into ranks

- eliminates large differences between individual scores

- maintains a normal type I error data

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chi square

- involves nominal (categorical) variables.

- looks at 2 distributions of categorical data to see if they differ from each other.

- inferential procedure

- 1 IV (1 way chi square)

- 2 IV (2 way chi square)

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assumptions of one way chi square

- 2 or more categories

- categories are mutually exclusive

- independent categories

- all responses included

- each expected frequency must be at least 5 (we need to ensure that the expected number of cases in each category is not too small, as small expected frequencies can lead to unreliable results.)

- participants belong to different levels of 1 variable

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example of one way chi square

is handedness related to brain organization

theory: many history geniuses were left handed

<p>is handedness related to brain organization </p><p>theory: many history geniuses were left handed</p>
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steps of one way chi square

step 1: create a model of the relationship

- what is the expected frequency between two variables

- create a null hypothesis

- describe the distribution of frequencies in the population if the predicted relationship does not exist

- no directional hypothesis

- if no difference between frequency, there is no relationship

step 2: translate the null hypothesis into the expected frequency for each category

- fE = expected frequency

- the larger difference between fo and fE , the lower chance the difference is due to sampling error

step 3: compare calculated critical chi-square values

step 4: no measuring EFFECT SIZE. just conclude regaridng frequencies

<p>step 1: create a model of the relationship</p><p>- what is the expected frequency between two variables</p><p>- create a null hypothesis </p><p>- describe the distribution of frequencies in the population if the predicted relationship does not exist </p><p>- no directional hypothesis</p><p>- if no difference between frequency, there is no relationship</p><p>step 2: translate the null hypothesis into the expected frequency for each category </p><p>- fE = expected frequency </p><p>- the larger difference between fo and fE , the lower chance the difference is due to sampling error</p><p>step 3: compare calculated critical chi-square values</p><p>step 4: no measuring EFFECT SIZE. just conclude regaridng frequencies </p>
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degree of freedom for chi square

k-1

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what is two way chi square refer to as?

test of independence

- counting the frequencies along 2 variables, and has same assumption as one way

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example of two way chi square

what is the relationship between personality type and cardiovascular

<p>what is the relationship between personality type and cardiovascular</p>
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perfectly independent relationship in two way chi square

there's no pattern

<p>there's no pattern</p>
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perfectly dependent relationship in two way chi square

clear pattern

<p>clear pattern</p>
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what's the statistical hypothesis for two way chi square

null hypothesis: category membership on one variable is independent of category membership (not correlated)

alternative hypothesis: category membership on the 2 variables is DEPENDENT

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Mann-Whitney U test

determines whether 2 uncorrelated means differ significantly when data are nonparametric

(memory: the 'u' reminds you of 'uncorrelated')

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Steps for the Mann-Whitney U

1. Assign raw scores to rank:

- If there are ties, assign the average rank to the tied observations.

2. Compute the sum of ranks

3. Compute U1 and U2:

- U1 is the smaller of the two sums of ranks and represents the sum of ranks for the group with the smaller sample size.

- U2 is the larger of the two sums of ranks and represents the sum of ranks for the group with the larger sample size.

4. Determine Mann-Whitney Uobtained:

- Use a two-tailed test to calculate the Mann-Whitney Uobtained value.

- The Uobtained value is the smaller of U1 and U2.

5. Find critical U-value:

- Look up the critical U-value in the Mann-Whitney U table

6. Compare Ucritical to Uobtained:

- If Uobtained is less than or equal to Ucritical, the test is significant.

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Wilcoxon Signed Rank Test

nonparametric procedure used for 2 related samples that are ranked data (same participants are evaluated twice)

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steps for Wilcoxon Signed Rank Test

1. Determine the difference scores for each pair of scores:

- Calculate the difference between the two related samples or the two measures of the same sample.

2. Determine the N (i.e number) of the non-zero scores:

- refer to the differences between the paired samples that are not equal to zero.

3. Assign ranks to the non-zero differences scores (ignore the sign of each difference)

- the smallest difference receiving a rank of 1.

4. Separate the ranks (using the sign of the difference score): - Assign the positive ranks to the positive differences

- negative ranks to the negative differences.

5. Compute the sum of the ranks for positive and negative ranks:

- sum of the ranks for the positive differences

- sum of the ranks for the negative differences.

6. Determine the Wilcoxon T obtained:

- calculate the smaller of the two sums of ranks, which is the Wilcoxon T obtained. (e.g if the sum of ranks for the positive differences is 60 and the sum of ranks for the negative differences is 45, then the Wilcoxon T obtained is 45, which is the smaller of the two sums of ranks.)

7. Find T critical through the Wilcoxon table

8. Compare T obtained with T critical:

- If T obtained < than T critical, then the difference between the two related samples is significant.

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what is the parametric equivalent to wilcoxon t-test?

paired t-test

H0: In the population the median difference is zero

H1: In the population the median difference is NOT zero

("not zero" means that there is a difference between the two populations being compared)

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Kruskal-Wallis test

The non-parametric equivalent to the 1 way ANOVA (not repeated measures)