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Computer logic and organization exam II
Computer logic and organization exam II
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23 Terms
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1
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Binary (Base 2)
Uses digits 0 and 1. Example: 1011₂ = 11₁₀.
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Decimal (Base 10)
Uses digits 0-9. Example: 245₁₀ = 245.
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Hexadecimal (Base 16)
Uses digits 0-9 and A-F. Example: 3F₁₆ = 63₁₀.
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Octal (Base 8)
Uses digits 0-7. Example: 57₈ = 47₁₀.
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Binary to Decimal Conversion
Multiply each bit by 2^position, starting from the right. Example: 1101₂ = (1×2³) + (1×2²) + (0×2¹) + (1×2⁰) = 13₁₀.
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Decimal to Binary Conversion
Divide the decimal number by 2, recording the remainders. Example: 13₁₀ → 1101₂.
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Binary to Hexadecimal Conversion
Group bits in sets of 4 and convert. Example: 10101100₂ → A C₁₆.
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Binary to Octal Conversion
Group bits in sets of 3 and convert. Example: 10101100₂ → 5 3 4₈.
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Signed Magnitude Representation
First bit is the sign (0 = positive, 1 = negative). Example: +5 → 00000101, -5 → 10000101.
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Two's Complement Representation
Write positive binary equivalent, invert all bits, and add 1 to the result. Example: -5 in two's complement: 5 = 00000101, Invert: 11111010, Add 1: 11111011.
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AND Gate
1 if both A and B are 1.
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OR Gate
1 if at least one input is 1.
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NOT Gate
Flips input (0 ↔ 1).
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XOR Gate
1 if inputs differ.
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NAND Gate
0 only if both are 1.
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NOR Gate
1 only if both are 0.
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2-Variable K-map
AB \ CD with values for combinations of inputs.
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Steps to Simplify Boolean Expressions
Group adjacent 1s in powers of 2 (1, 2, 4, 8...) and derive a simplified Boolean expression.
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SR Latch (Set-Reset Latch)
Inputs: S (Set), R (Reset); Outputs: Q (Stored value), Q' (Complement).
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Half-Adder
Adds two single-bit numbers with outputs: Sum (S) & Carry (C).
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Full-Adder
Adds two bits plus a carry-in with outputs: Sum (S) & Carry-out (Cout).
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Boolean Expression for Half-Adder
Sum = A ⊕ B; Carry = A * B.
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Boolean Expression for Full-Adder
Sum = A ⊕ B ⊕ Cin; Cout = (A * B) + (Cin * (A ⊕ B)).