Class 10 Science - Electricity Concepts & Important Questions

0.0(0)
Studied by 0 people
call kaiCall Kai
Locked
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
GameKnowt Play
Card Sorting

1/17

flashcard set

Earn XP

Description and Tags

Vocabulary flashcards covering core concepts, formulas, SI units, circuit diagrams, and experimental setups from Class 10 Physics Electricity.

Last updated 12:26 AM on 9/25/26
Name
Mastery
Learn
Test
Matching
Spaced
Call with Kai
Chat

No analytics yet

Send a link to your students to track their progress

18 Terms

1
New cards

S.I. Unit of Resistivity

The standard unit of electrical resistivity, expressed as Ohm-metre (Ω m\Omega\,\text{m}).

2
New cards

Electric Current

The amount of electric charge QQ flowing through a particular area of cross-section per unit time tt, mathematically expressed as I=QtI = \frac{Q}{t}.

3
New cards

Ampere (A\text{A})

The S.I. unit of electric current; defined as the current flowing through a conductor when one coulomb of electric charge passes through any cross-section in one second (1 A=1 C s−11\,\text{A} = 1\,\text{C\,s}^{-1}).

4
New cards

Conventional Current Direction

The direction of flow of positive charge (from point A to point B), which is conventionally taken as opposite to the direction of flow of negatively charged electrons.

5
New cards

Number of Electrons in One Coulomb

The total count of electrons constituting one coulomb of charge, calculated as n=1 C1.6×10−19 C=6.25×1018 electronsn = \frac{1\,\text{C}}{1.6 \times 10^{-19}\,\text{C}} = 6.25 \times 10^{18}\text{ electrons}.

6
New cards

Electrical Resistivity (ρ\rho)

The resistance offered by a metallic wire of unit length (1 m1\,\text{m}) and unit cross-sectional area (1 m21\,\text{m}^2), given by the formula ρ=R×Al\rho = \frac{R \times A}{l}.

7
New cards

Factors Affecting Electrical Resistance

The resistance of a conducting wire is directly proportional to its length (R∝lR \propto l), inversely proportional to its area of cross-section (R∝1AR \propto \frac{1}{A}), and depends on the nature of its material.

8
New cards

Electric Energy

The work done or energy supplied by an electrical source to maintain current flow, given by E=P×t=VIt=I2Rt=V2tRE = P \times t = V I t = I^2 R t = \frac{V^2 t}{R} with S.I. unit Joule (J\text{J}).

9
New cards

Electric Power

The time rate at which electric energy is consumed or dissipated by an electrical device, given by P=Wt=VI=I2R=V2RP = \frac{W}{t} = V I = I^2 R = \frac{V^2}{R} with S.I. unit Watt (W\text{W}).

10
New cards

Kilowatt-hour (kWh\text{kWh})

The commercial unit of electrical energy equal to 3.6×106 J3.6 \times 10^6\,\text{J} (1 kWh=1000 Wh=1000 J/s×3600 s1\,\text{kWh} = 1000\,\text{Wh} = 1000\,\text{J/s} \times 3600\,\text{s}).

11
New cards

Ohm's Law

States that the current flowing through a conductor is directly proportional to the potential difference across its ends (V=IRV = IR), provided physical conditions like temperature remain constant.

12
New cards
<p>Slope of V-I Graph</p>

Slope of V-I Graph

The slope obtained from plotting potential difference (VV) against current (II), which represents the electrical resistance (RR) of the conductor at a given temperature.

13
New cards

1 Volt (V\text{V})

The potential difference between two points when 1 joule1\,\text{joule} of work is done in moving 1 coulomb1\,\text{coulomb} of charge from one point to another (V=WQV = \frac{W}{Q}).

14
New cards

Cell or Battery

An electrical source or device that maintains a potential difference across a conductor in a closed circuit.

15
New cards
<p>Series Resistor Network Analysis</p>

Series Resistor Network Analysis

A circuit configuration where total equivalent resistance is Rs=R1+R2R_s = R_1 + R_2; for 10 Ω10\,\Omega and 20 Ω20\,\Omega in series with a 3 V3\,\text{V} source, Rs=30 ΩR_s = 30\,\Omega and current I=0.1 AI = 0.1\,\text{A}.

16
New cards
<p>Combination Resistor Network Analysis</p>

Combination Resistor Network Analysis

A network formed by resistors in series and parallel branches where equivalent resistance is given by 1R=1R4+1R1+R2+R3\frac{1}{R} = \frac{1}{R_4} + \frac{1}{R_1 + R_2 + R_3}, yielding R=7.5 ΩR = 7.5\,\Omega for four 10 Ω10\,\Omega resistors.

17
New cards
<p>Resistance Factor Testing Setup</p>

Resistance Factor Testing Setup

An experimental arrangement with an ammeter, cell, key, and test gap XY used to measure current through wires of differing lengths, cross-sections, and materials.

18
New cards
<p>Ohm's Law Verification Circuit</p>

Ohm's Law Verification Circuit

A circuit layout consisting of a resistance wire, an ammeter in series, a voltmeter in parallel, and a variable number of cells connected across gap XY to measure V/IV/I ratio consistency.