Chapter 8: Reactions of Alkenes

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16 Terms

1
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Hydrohalogenation

-the addition of HCl or HBr to a multiple bond to give an alkyl halide product

-Markovnikov addition: HBr

-Anti-markovnikov addition: HBR and ROOR

-1 chiral center=pair of enantiomers possible

<p>-the addition of HCl or HBr to a multiple bond to give an alkyl halide product</p><p>-Markovnikov addition: HBr</p><p>-Anti-markovnikov addition: HBR and ROOR</p><p>-1 chiral center=pair of enantiomers possible</p>
2
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Acid Catalyzed Hydration

- used to convert alkenes to alcohols

- Markov regioselevtivity

- carbocation rearrangements are possible

- When a new chiral center is generated, a racemic mixture of enantiomers is expected

H20, H+, H2SO4 (aq)

<p>- used to convert alkenes to alcohols</p><p>- Markov regioselevtivity</p><p>- carbocation rearrangements are possible</p><p>- When a new chiral center is generated, a racemic mixture of enantiomers is expected</p><p>H20, H+, H2SO4 (aq)</p>
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Oxymercuration-Demercuration

-Will not undergo carbocation rearrangements

-Nucleophile attacks the most substituted position

-Markovnikov addition

1. Hg(OAC)2, H20

2. NaBH4

<p>-Will not undergo carbocation rearrangements</p><p>-Nucleophile attacks the most substituted position</p><p>-Markovnikov addition</p><p>1. Hg(OAC)2, H20</p><p>2. NaBH4</p>
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Hydroboration Oxidation

-Anti-Markovnikov addition

-Undergoes Syn addition

-BH2 is installed at less substituted position and OH is installed at the less substituted position

-1 chiral center= racemix mixture

-2 chiral centers= syn addition

1. BH3, THF

2. H202, NaOH

<p>-Anti-Markovnikov addition</p><p>-Undergoes Syn addition</p><p>-BH2 is installed at less substituted position and OH is installed at the less substituted position</p><p>-1 chiral center= racemix mixture</p><p>-2 chiral centers= syn addition</p><p>1. BH3, THF</p><p>2. H202, NaOH</p>
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Catalytic Hydrogenation

-reduces alkenes to alkanes

Zero chiral centers: syn requirement is not relevant. Only one product formed

One chiral center: Both possible enantiomers are formed

Two chiral centers: The requirment for syn addition determines which pair of enantiomers is obtained. (Be careful of meso compounds)

1. H2, Ni

<p>-reduces alkenes to alkanes</p><p>Zero chiral centers: syn requirement is not relevant. Only one product formed</p><p>One chiral center: Both possible enantiomers are formed</p><p>Two chiral centers: The requirment for syn addition determines which pair of enantiomers is obtained. (Be careful of meso compounds)</p><p>1. H2, Ni</p>
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Halogenation

-involves the addition of X2 (either Br2 or Cl2) across an alkene.

-For most simple alkenes, halogenation appears to proceed via an anti-addition

-The stereochemical outcome for halogenation reactions is dependent on the configuration of the starting alkene

1. Br2 or Cl2

<p>-involves the addition of X2 (either Br2 or Cl2) across an alkene.</p><p>-For most simple alkenes, halogenation appears to proceed via an anti-addition</p><p>-The stereochemical outcome for halogenation reactions is dependent on the configuration of the starting alkene</p><p>1. Br2 or Cl2</p>
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Halohydrin Formation

-Installs OH at the more substituted position

<p>-Installs OH at the more substituted position</p>
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Anti Dihydroxylation

What's added: OH and OH

Regioselectivity: N/A

Stereoselectivity: anti

Intermediate: don't worry about it

Rearrangement: not possible

anti-addition becomes irrelevant with one chiral center

1. RCO3H

2. H3O+

<p>What's added: OH and OH</p><p>Regioselectivity: N/A</p><p>Stereoselectivity: anti</p><p>Intermediate: don't worry about it</p><p>Rearrangement: not possible</p><p>anti-addition becomes irrelevant with one chiral center</p><p>1. RCO3H</p><p>2. H3O+</p>
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Syn Dihydroxylation

1. OsO4

2. NaHSO3, H2O

or

1. KMnO4

2. NaOH cold

<p>1. OsO4</p><p>2. NaHSO3, H2O</p><p>or</p><p>1. KMnO4</p><p>2. NaOH cold</p>
10
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Oxidative Cleavage

-the C=C bond is completely split apart to form two C=O bonds. Therefore, issues of stereochemistry and regiochemistry become irrelevant.

1. O3

2. DMS or Zn/H20

<p>-the C=C bond is completely split apart to form two C=O bonds. Therefore, issues of stereochemistry and regiochemistry become irrelevant.</p><p>1. O3</p><p>2. DMS or Zn/H20</p>
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Oxidative Cleavage by KMNO4

-KMNO4 is a strong oxidizing agent

-If KMNO4 makes a aldehyde it is further oxidized to RCO2H

-IF KMNO4, makes a formaldehydte it is oxidized to formic acid but it decomposes to CO2 which is the final product

<p>-KMNO4 is a strong oxidizing agent</p><p>-If KMNO4 makes a aldehyde it is further oxidized to RCO2H</p><p>-IF KMNO4, makes a formaldehydte it is oxidized to formic acid but it decomposes to CO2 which is the final product</p>
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Oxidation/Reduction

Oxidation: number of oxygen increases OR number of hydrogen decreases

<p>Oxidation: number of oxygen increases OR number of hydrogen decreases</p>
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TsCl, pyridine can be used on a ____and ____alcohol

primary and secondary but not tertiary

14
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Primary alcohol undergoes ____while secondary and tertiary undergo ____

E2, E1 (H2SO4)

15
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Primary alcohol undergoes _____while secondary and tertiary undergo____

SN2, SN1 (HBr)

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If FINAL carbons is less than STARTING carbons during synthesis, use...

1) O3

2) DMS