Physics Unit 1

acceleration

change in velocity over time

car speeding up

same velocity + same acceleration

car slowing up

velocity and acceleration are opposites

UAM (Uniform Accelerated Motion)

vx = v0 + at—>

vx² = v0^2 + 2a(xf-xi)

delta x = 1/2at² + v0t + x0

starts at rest: inital velocity is 0

comes to a stop: velocity is 0 mls

how far?: find displacement

how long?: time

How fast?: find velocity

at what rate: acceleration

UAM Steps

1. Identify variables —> Guess

2. Identify what its asking for

3. identify which equation will help

4. plug in your variables

5. check numbers

Free Fall

when an object is only acted upon by gravity

• ignore air resistance (friction due to air)

• Free Fall—> straight up and down (y axis)

acceleration is constant: -9.8 m/s squared (-10 m/s squared)

Throwing a ball (Free Fall)

When throwing a ball, it has an initial velocity and soon slows down until it reaches the peak, but then comes down with an acceleration of -9.8 m/s squared

Position vs Time Graphs

just graph where each point is at time (time, position)

rise/run

Slope: velocity

Velocity Time Graph

the velocity at each time the object (time, velocity)

Slope: acceleration

Area: Displacement

frame of referece

the point of view that affects how a person measures + reports motion

How to change frames of references?

To change from object A’s frame of reference to Object B’s frame of reference, we have to subtract Object B’s velocity from Object A’s velocity

In Frame of reference

each object stands still in its own frame of reference

Segmented Motion

Each interval of constant acceleration is called a segment so if the constant acceleration changes into a another constant acceleration, we have two segments

Projectile Motion

special type of free fall that takes place when the object has both horizontal and vertical motion

x acceleration: 0

y acceleration: -10 m/s squared

Projectile Motion is 2 Motions

One motion: horizontal constant velocity

Second Motion: vertical constant acceleration

Horizontal Motion Equation

x = x0 + v0x(t)