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define diffraction (2)
when a wave hits an obstacle, it bends around the obstacle
same effect at a hole - wave spreads out around the other side of the hole
give an example of diffraction
water
explain Huygens principle of secondary wavelets (3)
starting from a known point - every point on a wavefront is a source of wavelets
the wavelets spread out in a spherical forward direction at the same speed (as the original wave)
the new wavefront is tangent to all the wavelets
State the Fresnel-Huygen principle of secondary wavelets (2)
Every point on a wavefront acts as a secondary source of a spherical wavefront of the same frequency
The magnitude of the displacement at any point beyond is the superposition of all the secondary wavelets at that point having regard for their amplitudes and relative phases
compare and contrast Fresnel and Fraunhofer diffraction patterns (3)
Fresnel - the source of light and screen is at a finite distance from the object - near-field - near object point WHEREAS Fraunhofer - source of light and scree is at an infinite distance from the obstacle - far field - distant observation point
Fresnel - observed anywhere in the diffracted beam apart for the in-focus image plane WHEREAS Fraunhofer - observed in the in-focus image plane of a source
Fraunhofer - important in optical systems including the eye
how can Fraunhofer’s diffraction be demonstrated
through a single slit experiment
explain the above experiment (2)
Adjustable slit is placed on the table of a spectroscope and a monochromatic light source is
viewed through it using the spectroscope telescope.
• Slit is narrowed a broad diffraction pattern spreads out either side of the slit, only disappearing when
the width of the slit is equal to or less than 1 wavelength of the light used
why are circular aperture diffraction patterns important
most optical instruemnts including the eye have circular apertures
in a lens system corrected for abberation the detial in an image is limitd by diffraction - unwantd spread of light as it passes through pupil affects sharpness of image
explain the circular aperture diffraction patterns in the eye and why it is important
most optical instruments including the eye have circular apertures
when light passes through these circular apertures (pupil) it does not form a perfect point image but instead spreads out into a pattern called an Airy disk.
The size of this diffraction pattern determines the resolution limit of optical systems, affecting how well we can distinguish two closely spaced objects.
explain in more detail what an airy disk is (2)
The amplitude distribution for
diffraction due to a circular aperture
forms an intensity pattern with a
bright central circular area
surrounded by concentric circular
bands of rapidly decreasing intensity - ( Airy Disc) .
• 84 % of the light arrives within the
central peak called Airy disc.
explain resolution in imaging systems and its limits (5)
imaging systems have a limit on determining detail in the image
the closer the object points are the closer are their images are in the image plane of the optical system
a - images are easily observed as separate images
b - slight overlap
c- complete overlap - no longer able to distinguish as two separate images
state rayleigh’s criterion - for the diffraction limit to resolution
Rayleigh Criterion for the diffraction limit to
resolution states that:
2 images are just resolvable when the center of the diffraction pattern of one is directly over the first minimum of the diffraction pattern of the other
what is the calculation / formula used to calculate this
θ=1.22 x λ / D
λ is the wavelength of light
D (m) is the diameter of the
aperture
θ is in radian
re-arranged: d = 1.22 x λ / 0