Diffraction

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13 Terms

1
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define diffraction (2)

  • when a wave hits an obstacle, it bends around the obstacle

  • same effect at a hole - wave spreads out around the other side of the hole

2
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give an example of diffraction

water

3
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explain Huygens principle of secondary wavelets (3)

  • starting from a known point - every point on a wavefront is a source of wavelets

  • the wavelets spread out in a spherical forward direction at the same speed (as the original wave)

  • the new wavefront is tangent to all the wavelets

4
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State the Fresnel-Huygen principle of secondary wavelets (2)

  • Every point on a wavefront acts as a secondary source of a spherical wavefront of the same frequency

  • The magnitude of the displacement at any point beyond is the superposition of all the secondary wavelets at that point having regard for their amplitudes and relative phases

5
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compare and contrast Fresnel and Fraunhofer diffraction patterns (3)

  • Fresnel - the source of light and screen is at a finite distance from the object - near-field - near object point WHEREAS Fraunhofer - source of light and scree is at an infinite distance from the obstacle - far field - distant observation point

  • Fresnel - observed anywhere in the diffracted beam apart for the in-focus image plane WHEREAS Fraunhofer - observed in the in-focus image plane of a source

  • Fraunhofer - important in optical systems including the eye

6
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how can Fraunhofer’s diffraction be demonstrated

through a single slit experiment

7
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explain the above experiment (2)

  • Adjustable slit is placed on the table of a spectroscope and a monochromatic light source is
    viewed through it using the spectroscope telescope.
    • Slit is narrowed a broad diffraction pattern spreads out either side of the slit, only disappearing when
    the width of the slit is equal to or less than 1 wavelength of the light used

8
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why are circular aperture diffraction patterns important

most optical instruemnts including the eye have circular apertures

in a lens system corrected for abberation the detial in an image is limitd by diffraction - unwantd spread of light as it passes through pupil affects sharpness of image

9
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explain the circular aperture diffraction patterns in the eye and why it is important

  • most optical instruments including the eye have circular apertures

  • when light passes through these circular apertures (pupil) it does not form a perfect point image but instead spreads out into a pattern called an Airy disk.

  • The size of this diffraction pattern determines the resolution limit of optical systems, affecting how well we can distinguish two closely spaced objects.

10
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explain in more detail what an airy disk is (2)

  • The amplitude distribution for
    diffraction due to a circular aperture
    forms an intensity pattern with a
    bright central circular area
    surrounded by concentric circular
    bands of rapidly decreasing intensity - ( Airy Disc) .
    • 84 % of the light arrives within the
    central peak called Airy disc.


11
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explain resolution in imaging systems and its limits (5)

  • imaging systems have a limit on determining detail in the image

  • the closer the object points are the closer are their images are in the image plane of the optical system

  • a - images are easily observed as separate images

  • b - slight overlap

  • c- complete overlap - no longer able to distinguish as two separate images

12
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state rayleigh’s criterion - for the diffraction limit to resolution

Rayleigh Criterion for the diffraction limit to
resolution states that:

  • 2 images are just resolvable when the center of the diffraction pattern of one is directly over the first minimum of the diffraction pattern of the other

13
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what is the calculation / formula used to calculate this

θ=1.22 x λ / D
λ is the wavelength of light

D (m) is the diameter of the
aperture

θ is in radian

re-arranged: d = 1.22 x λ / 0