Equation: LiOH + HCl → H2O + LiCl
Step 1: LiOH = -481.93, HCl = -167.159, H2O = -285.830, LiCl = -408.7
Step 2. Products = -285.830 + -408.7 = -694.53; Reactants = -481.93 + -167.159 = -649.089
Step 3: Products - Reactants; (-694.53) - (-649.089) = -45.44 kJ/mole
Step 4: Exothermic, -ΔH
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