Chapter 6: Mechanical Properties (Part 1)

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Last updated 5:06 AM on 7/11/26
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70 Terms

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Strain

  • the change in dimension of a material per unit length

  • dimensionless

  • m/m or cm/cm

  • result of the application of stress to a material

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Stress

  • a force acting on an area

  • normal stresses act perpendicular to the area (tensile stress → pull apart, compressive stress → squeeze inwards)

  • shear stresses act parallel to the area

<ul><li><p>a force acting on an area</p></li><li><p>normal stresses act perpendicular to the area (tensile stress → pull apart, compressive stress → squeeze inwards)</p></li><li><p>shear stresses act parallel to the area</p></li></ul><p></p>
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Elastic strain

  • fully recoverable strain that develops upon applied stress, and is completely recovered when the stress is removed

  • no permanent deformation

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Plastic deformation/strain

when a material does not return to its original shape after stress is removed

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Uniaxial Tensile Test

  • Measure the resistance of a material to a slowly applied stress

  • Used to determine many material properties

  • typical specimen: ASTM E8 Standard

  • Amount of stretching measured using a strain gauge or extensometer

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Hooke’s Law Equation

σ = EΔ

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Strain rate

How fast you pull an object apart

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Engineering stress formula

S = F/ A0

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Engineering Strain formula

e = Δl / l0

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What is the typical stress-strain in metals? What is the deformation mechanism?

<40%

Bond stretching followed by dislocation multiplication and motion

<p>&lt;40%</p><p>Bond stretching followed by dislocation multiplication and motion</p>
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Work Hardening

dislocation multiplication

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What is the typical stress-strain in ceramics? What is the deformation mechanism?

~500 MPa

much better in compression than tension

stretching of strong ionic/covalent bonds, few slip systems, no plasticity

failure after stress exceeds bond strength

<p>~500 MPa</p><p>much better in compression than tension</p><p>stretching of strong ionic/covalent bonds, few slip systems, no plasticity</p><p>failure after stress exceeds bond strength</p>
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What is the typical stress-strain in elastomers? What is the deformation mechanism?

  • large, reversible deformation

  • uncoiling and alignment of long polymer chains followed by stretching of covalent bonds

  • almost no linear range

<ul><li><p>large, reversible deformation</p></li><li><p>uncoiling and alignment of long polymer chains followed by stretching of covalent bonds</p></li><li><p>almost no linear range</p></li></ul><p></p>
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What is the typical stress-strain in thermoplastics? What is the deformation mechanism?

bond stretching, rotating, and disentangling, followed by chains siding past one another and rearranging permanently

<p>bond stretching, rotating, and disentangling, followed by chains siding past one another and rearranging permanently</p>
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Poisson’s Ratio Equation

v = - elateral / elongitudinal

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For metals, Poisson’s ratio is


0.25 1<= v <= 0.50

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Yield Strength

the point where the material transitions from elastic to plastic deformation

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What is the relationship between elastic and plastic strains?

Δtota = Δplastic + Δelastic

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As plastic deformation begins, stress value drops from the “upper yield point” (S2). What does this mean experimentally/physically?

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Certain low-carbon steels display this “yield point phenomenon.” Why do they display this phenomenon?

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Luders Bands

  • visible, slanted lines that appear on the surface of some mild steels and other low-carbon alloys during tensile test

  • caused by dislocation motion being interfered with by interstitial atoms clustered around dislocations during slip

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Is plastic deformation good or bad for load-bearing applications?

Bad, must design components so stress under operation is much less than yield strength at the temperature at which the material will be used

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For shaping materials into components, you must apply stresses well above or below yield strength?

above

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True or False: Young’s Modulus is dominated by atomic bonds, rather than microstructure (grain size, phases, GB)

True

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Necking

one region of specimen deforms more than the rest and the cross-sectional area decreases

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How does engineering stress decrease?

area is smaller at neck, so a lower force is required to continue deformation

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Uniform deformation vs Non-uniform deformation

refer to graph for answer

<p>refer to graph for answer</p><p></p>
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Ultimate Tensile Strength

  • strength at highest applied force or maximum stress on engineering stress-strain diagram

  • deformation becomes unstable in a local area and doesn’t remain uniform

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What do true stress and true strain account for?

the changing dimension of the tensile specimen during deformation

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True Stress

Force acting per instantaneous cross-sectional area of specimen

σT = F/A

<p>Force acting per instantaneous cross-sectional area of specimen</p><p>σ<sub>T</sub> = F/A</p>
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True Strain

Integrating the incremental changes in length relative to the instantaneous length

ΔT = ln(L/L0)

<p>Integrating the incremental changes in length relative to the instantaneous length</p><p>Δ<sub>T</sub> = ln(L/L<sub>0</sub>)</p>
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Which metals do you expect to have higher melting temperatures?

metals with higher elastic modulus tend to have stronger atomic bonding, so they have higher temperatures

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Modulus of resilience

elastic energy a material can absorb prior to yielding

Er = (1/2)(yield strength)(strain at yielding)

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Tensile toughness

  • energy absorbed by the material prior to fracture

  • area under “true” stress-strain curve

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<p>Which material has more toughness?</p>

Which material has more toughness?

B

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<p>Which material has a larger E/ “stiffness”?</p>

Which material has a larger E/ “stiffness”?

Steel

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Ductility

ability of a material to be permanently deformed without breaking when a force is applied

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%Elongation formula

%elongation = ((lf - l0 ) / l0 ) * 100%

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%Reduction in area formula

%RA = ((A0 - Af ) / A0) * 100%

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Elastic limit

  • max stress a material can experience and still return to its original shape after the load is removed

  • below: elastic deformation

  • above: some permanent plastic deformation remains

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What does yield strength correspond to?

stress at which plastic deformation starts

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How can we control yield strength?

  1. other dislocations (strain hardening)

  2. grain size (grain strengthening)

  3. point defects (solid-solution strengthening)

  4. precipitations (second phases such as carbides in steel)

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Why does the yield strength decrease at higher temperatures?

  • decreased dislocation density

    • energy assists formation of ideal crystal structure

    • dislocations don’t interfere with each other

  • increase in grain size via grain growth

    • recrystallization: new and defect-free grains grow

  • strengthening due to ultra-fine particles may decrease

    • precipitates grow in size

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Hardness test

measure of the resistance to penetration of the surface of a material by a hard object

qualitative measure of the properties of the material

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Why can’t we establish a quantitative unit for hardness (ex. MPa)?

the stress near indenter is non-uniform

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Brinell Hardness

  • uses spherical indenter and measures diameter of indent

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Rockwell Hardness

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Brinell Hardness Number (BHN)

<p></p>
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Why is elastic deformation also measured in a Rockwell Hardness test?

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Why might a metal/alloy be more brittle for impacts?

Insufficient time for slip to occur

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Impact test

  • used to evaluate brittleness of a material under impact loading

  • material is strained at a much higher rate than tensile test

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Strain rate

how fast deformation is happening

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Vickers Hardness

HV = 1.854 (P/dÂČ)

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Knoop Hardness

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Tensile toughness

area under a stress-strain curve before fracture

ability of a material to absorb energy during a slow tensile test

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Impact toughness

ability to absorb energy during an impact

measured using Izod and Charpy tests

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Fracture toughness

ability of a material containing flaws to withstand an applied load

(flaw: pre-existing crack or void)

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<p>At low temperature, are there more or fewer thermal vibrations?</p>

At low temperature, are there more or fewer thermal vibrations?

fewer

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At low temperature, do dislocations have an easier or more difficult time moving?

more difficult → no assistance from the thermal vibrations

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As temperature decreases, what happens to ductility and strength?

ductility decreases, strength increases

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<p>As the strain rate increases, is there more or less time for dislocations to move?</p>

As the strain rate increases, is there more or less time for dislocations to move?

less time

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If we observe a material to exhibit good ductility at room temperature, how can we know about low temperatures without repeating tensile tests?

Perform an Izod or Charpy test

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Charpy test

  • mgh → m = mass of pendulum

  • pendulum hits behind the notch in the material

  • impact energy measured by this test is the work done to fracture the specimen

  • more ductile the material → more plastic deformation → higher the Charpy energy

  • more brittle → less plastic deformation → less Charpy energy

<ul><li><p>mgh → m = mass of pendulum</p></li><li><p>pendulum hits behind the notch in the material</p></li><li><p>impact energy measured by this test is the work done to fracture the specimen</p></li><li><p>more ductile the material → more plastic deformation → higher the Charpy energy</p></li><li><p>more brittle → less plastic deformation → less Charpy energy</p></li></ul><p></p>
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The Charpy energy compared to the energy under the stress-strain curve is ___________________

usually smaller

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Why should we be interested in impact and fracture toughness?

  • important for load bearing structures

  • need to know if material will survive the conditions that the structure will see in service

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Izod test

  • like a cantilever beam

<ul><li><p>like a cantilever beam</p></li></ul><p></p>
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Ductile to Brittle Transition Temperature (DBTT)

  • transition temps are determines using Charpy and Izod tests

  • ex. Titanic → snapped easily from impact of iceberg due to low temperatures

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Require DBTT above or below operating temperatures?

below

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True or False: FCC crystal structure typically exhibits higher absorbed energies and no transition temperature

True because dislocations can still move on many close-packed slip systems