when finding a 3x3 determinant, you can take the top elements, eliminate their (answer and answer), then find the 2d determinant of the remaining values and multiply by the respective top row value
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\+,-,+
the signs of the 3 2d determinants are in order (sign, sign, sign)
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area
the magnitude of the cross product of the two vectors is the () of the parallelogram bounded by the vectors
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anti-commutative
(two words): the idea that if u = a x b and v = b x a, then u = -v. In another way, reversing the arguments reverses/negate/flips 180 degrees the resulting vector
Cross products have this property
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0
a vector cross-product’d with itself is
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non-associative
since ((a x a) x b) = 0 but (a x ( a x b)) != 0, cross product is
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0
the cross product of two vectors that are linear combinations of each other is
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x2*y3 -* x3y2
the i value of the cross product made from vectors x and y is
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x3\**y1 - x1*\*y3
the j value of the cross product made from vectors x and y is
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x1\**y2 - x2**y1
the k value of the cross product made from vectors x and y is