Redox reactions and Oxidation states and ionic equations

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Last updated 12:11 PM on 9/10/26
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<p>Oxidation state rules</p>

Oxidation state rules

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  1. When lithium chloride dissolves in water, Li+ and Cl− ions are produced.
    The charge on the lithium ion is …1? and its oxidation state is …2?.

    The charge on the chloride ion is …3? and its oxidation state is …4?.


    1. This question refers to the following chemical reaction:

      4Al (s)+3O2(g)→2Al2O3(s)

      5. Which element is gaining electrons and Which element is losing electrons?

 In this reaction, the aluminium has been ..6? and the oxygen has been …7?.


  1. This question refers to the following chemical reaction:

    Mg (s)+ZnCl2(aq)→MgCl2(aq)+Zn (s)

    On the left hand side of the equation, zinc ions in the aqueous solution have a charge of …8? and so the oxidation state of zinc is …9?

    By looking at the oxidation states of all species in the reaction in this way, we can deduce that:
    ∙ The oxidation state of zinc went from …10? to ..11?.
    ∙ The oxidation state of magnesium went from …12? to …13?.



  1. (1+). 2. (+1). 3. (1-). 4. (-1)

    1. Gain: Alumnium. Lose: Oxygen

    2. Oxidised. 7. Reduced

(Explanation: Aluminium oxide is an ionic compound made up of Al3+ cations and O2− anions.
Remember that Group 1 metals in ionic compounds have a charge of 1+, Group 2 metals have a charge of 2+ and Group 3 metals like aluminium have a charge of 3+. )

  1. 2+. 9. (+2). 10. (+2). 11. (0). 12. (0). 13. (+2)


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<ol><li><p><span>Oxidation can be defined as … (3 things)</span></p></li><li><p>What is a redox reaction?</p></li><li><p>Image question?</p></li><li><p><span style="font-size: var(--ck-content-font-size);"><span>For the following three reactions, state the oxidising agent in each case by determining which element is the more electronegative.</span><span><br></span><span><br></span><span>Reaction 1: 3Be (s)+N2(g)→Be3N2(g)</span><span><br></span><span>4.1 Oxidising agent: ?</span></span></p></li></ol><p class="sc-fQpSrZ sc-kWRDzD bvYkPV fMenCk"></p><p class="sc-fQpSrZ sc-kWRDzD bvYkPV fMenCk"><span style="font-size: var(--ck-content-font-size);"><span>Reaction 2: 2K (s)+Br2(g)→2KBr</span><span><br></span><span>4.2 Oxidizing agent:?</span></span></p><p class="sc-fQpSrZ sc-kWRDzD bvYkPV fMenCk"><span style="font-size: var(--ck-content-font-size);"><span><br></span><span>Reaction 3: P4(s)+6Cl2(g)→4PCl3(l)</span><span><br></span><span>4.3 Oxidising agent: ?</span></span></p><p></p><ol start="5"><li><p><span style="font-size: var(--ck-content-font-size);"><span>Which of the following compounds has a metal in the +2 oxidation state?</span><span><br></span></span></p><p class="sc-fQpSrZ sc-hjIwmx fmbeOa esnGGx"><span style="font-size: var(--ck-content-font-size);"><span>Select all that apply</span></span></p><p><span style="line-height: 0.75rem;"><span>Correct answersYour answers</span></span></p><p class="sc-fQpSrZ bvYkPV"><span style="font-size: var(--ck-content-font-size);"><span>A: NaCl</span></span></p><p class="sc-fQpSrZ bvYkPV"><span style="font-size: var(--ck-content-font-size);"><span>B: Li3N</span></span></p><p class="sc-fQpSrZ bvYkPV"><span style="font-size: var(--ck-content-font-size);"><span>C: K2S</span></span></p><p class="sc-fQpSrZ bvYkPV"><span style="font-size: var(--ck-content-font-size);"><span>D: CaO</span></span></p><p class="sc-fQpSrZ bvYkPV"><span style="font-size: var(--ck-content-font-size);"><span>E: Na2O2</span></span></p></li><li><p class="sc-fQpSrZ bvYkPV"><span style="font-size: var(--ck-content-font-size);"><span>What is the oxidation state of the metal in the following compounds? </span><span><br></span><span><br></span><span>6.1 Li2O: ?</span></span></p></li></ol><p class="sc-fQpSrZ sc-kWRDzD bvYkPV fMenCk"><span style="font-size: var(--ck-content-font-size);"><span>6.2 NaCl:?</span></span></p><p class="sc-fQpSrZ sc-kWRDzD bvYkPV fMenCk"><span style="font-size: var(--ck-content-font-size);"><span>6.3 Mg3N2: ?</span></span></p><p class="sc-fQpSrZ sc-kWRDzD bvYkPV fMenCk"><span style="font-size: var(--ck-content-font-size);"><span>6.4 KI: ?</span></span></p><p class="sc-fQpSrZ sc-kWRDzD bvYkPV fMenCk"><span style="font-size: var(--ck-content-font-size);"><span>6.5 CaF2: ?</span></span></p><p></p>
  1. Oxidation can be defined as … (3 things)

  2. What is a redox reaction?

  3. Image question?

  4. For the following three reactions, state the oxidising agent in each case by determining which element is the more electronegative.

    Reaction 1: 3Be (s)+N2(g)→Be3N2(g)
    4.1 Oxidising agent: ?


Reaction 2: 2K (s)+Br2(g)→2KBr
4.2 Oxidizing agent:?


Reaction 3: P4(s)+6Cl2(g)→4PCl3(l)
4.3 Oxidising agent: ?


  1. Which of the following compounds has a metal in the +2 oxidation state?

    Select all that apply

    Correct answersYour answers

    A: NaCl

    B: Li3N

    C: K2S

    D: CaO

    E: Na2O2

  2. What is the oxidation state of the metal in the following compounds?

    6.1 Li2O: ?

6.2 NaCl:?

6.3 Mg3N2: ?

6.4 KI: ?

6.5 CaF2: ?


  1. Gain of oxygen, loss of e-, increase in oxidation state

  2. A reaction where one substance is oxidised and another substance is reduced. (There is no net gain or loss of electrons)

    1. 4.1(nitrogen). 4.2(bromine). 4.3(chlorine)

  1. D

  2. 6.1 (+1). 6.2. (+1). 6.3. (+2). 6.4 (+1). 6.5 (+2)


<ol><li><p>Gain of oxygen, loss of e-, increase in oxidation state</p></li><li><p>A reaction where one substance is oxidised and another substance is reduced. (There is no net gain or loss of electrons)</p><ol start="4"><li><p>4.1(nitrogen). 4.2(bromine). 4.3(chlorine)</p></li></ol></li></ol><ol start="5"><li><p>D</p></li><li><p>6.1 (+1). 6.2. (+1). 6.3. (+2). 6.4 (+1). 6.5 (+2)</p></li></ol><p></p>
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<p>Answer image question?</p><p>Note: work out the oxidation state of the elements in the ion, and then work out the oxidation state for the other element in the compound.</p><ol start="2"><li><p><span>Copper sulfate has the following chemical formula:</span><br><span>CuSO4</span><br><span>Using your knowledge of the sulfate ion, deduce the oxidation state of copper.</span><br><br>3. <span>Give the full name of the most common form of copper sulfate, which has the formula CuSO4.</span></p><ol start="4"><li><p><span>Give the full name of the molecule </span><br><span>UF4 and deduce the oxidation states.</span></p></li></ol></li></ol><p></p>

Answer image question?

Note: work out the oxidation state of the elements in the ion, and then work out the oxidation state for the other element in the compound.

  1. Copper sulfate has the following chemical formula:
    CuSO4
    Using your knowledge of the sulfate ion, deduce the oxidation state of copper.

    3. Give the full name of the most common form of copper sulfate, which has the formula CuSO4.

    1. Give the full name of the molecule
      UF4 and deduce the oxidation states.


  1. +1

  2. Cu: +2

  3. Copper (II) Sulfate

  4. F: -1 U: +4. Name: Uranium (IV) Fluoride


<ol><li><p>+1</p></li><li><p>Cu: +2</p></li><li><p>Copper (II) Sulfate</p></li><li><p>F: -1 U: +4. Name: Uranium (IV) Fluoride</p></li></ol><p></p>
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<p>using the image, tell me what a disproportionation reaction is?</p><p>Disproportionation reactions are …2?</p>

using the image, tell me what a disproportionation reaction is?

Disproportionation reactions are …2?

  1. Where an element is both oxidised and reduced in the same reaction

  2. Redox reactions


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<p>Answer image question</p><p>Note: Half equations show the electron transfer during reduction or oxidation, rather than showing the entire reaction.</p>

Answer image question

Note: Half equations show the electron transfer during reduction or oxidation, rather than showing the entire reaction.

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<p>Balance this half equation using these rules?</p>

Balance this half equation using these rules?

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<p>Answer image question?</p><p>Note: for the two half equation reactions, to make an overall reaction you need to first ensure the number of electrons are equal for both reaction and if not multiple each reaction to make them equal. Then you combine all the reactants for both equations on one side and the products on the other. Then you cancel out the electrons and hydrogens and there is your answer.</p>

Answer image question?

Note: for the two half equation reactions, to make an overall reaction you need to first ensure the number of electrons are equal for both reaction and if not multiple each reaction to make them equal. Then you combine all the reactants for both equations on one side and the products on the other. Then you cancel out the electrons and hydrogens and there is your answer.

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