5A Acids and Bases

0.0(0)
studied byStudied by 1 person
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
Card Sorting

1/24

encourage image

There's no tags or description

Looks like no tags are added yet.

Study Analytics
Name
Mastery
Learn
Test
Matching
Spaced

No study sessions yet.

25 Terms

1
New cards

What is molarity dependent upon?

moles and volume

2
New cards

What happens at equivalence points in a titration?

When a species has one of their hydrogens dissociated

3
New cards

Every time ur increasing by 10 dB, you’re effectively ______ to the difference in intensity

Adding another zero.

4
New cards

Stronger acids _____ so Ka is ___.

What are the levels for Ka in strong and weak acids?

  1. Completely dissociate

  2. HIGH

SA: Ka>1

WA: Ka<1

5
New cards

What are the common strong acids? What about the common strong bases?

knowt flashcard image
6
New cards

What is Kw at 25 degrees Celsius? What is it also equal to?

Kw = 1 × 10-14

Kw= Ka x Kb

7
New cards

If [H+] increases, pH ____.

Decreases

8
New cards

A SA has a ___ Ka and a ____ pKa.

  1. High

  2. Low

9
New cards

If we are given pH and solution concentration, how do we solve for the Ka?

  1. Write out Ka as alike any other equilibrium constant (products/reactants)

  2. Replace missing concentrations with “x” as that is the change which is also subtracted from our initial solution concentration

  3. Assume “x” is small at the bottom

  4. Since we know [H+] based on the pH and both H and A- are equal to x, they both will be equal to H concentration

<ol><li><p>Write out Ka as alike any other equilibrium constant (products/reactants)</p></li><li><p>Replace missing concentrations with “x” as that is the change which is also subtracted from our initial solution  concentration</p></li><li><p>Assume “x” is small at the bottom</p></li><li><p>Since we know [H+] based on the pH and both H and A- are equal to x, they both will be equal to H concentration</p></li></ol><p></p>
10
New cards

What is the formula fro normality and how do we get it?

equivalents (eq/L)

<p>equivalents (eq/L)</p>
11
New cards

What is the formula for gram-equivalent weight? What is the unit?

g/eq

<p>g/eq</p>
12
New cards

If we know we are dealing with a titration and are asked what the concentration of the unknown is, what do we do?

Use MV=MV with the titrant known concentration and volume with analytes unknown volume and unknown concentration as a variable

13
New cards
<p>Fill dis out</p>

Fill dis out

knowt flashcard image
14
New cards
<p>Fill dis out</p>

Fill dis out

knowt flashcard image
15
New cards

What is the pH of a 10-3 M HCl solution when titrated with NaOH at:

Initial:

Half eq:

Eq pt:

Initial: 3

Half eq: 3.5

Eq pt: 7 (because we end up just making water and salt)

16
New cards

How would we find the number of Cl ions at equivalence point with a titration involving HCl and NaOH?

Cl- will stay the same throughout the titration so use the concentration of Cl- from the concentration of HCl and its volume and use Avogadro’s number!

17
New cards

What is the pH of a 10-3 M CH3COOH (pKa =5) solution when titrated with NaOH at:

Initial:

Half eq:

Eq pt:

Initial: 4

Half eq: 5

Eq pt: pH>7

18
New cards

Lets say that 40 mL was needed to reach the equivalence point, if we just add 20 mL instead, we are ____.

At half equivalence!

19
New cards

How do you know to use the common ion effect and Ksp to solve a solubility question like this one?
"Solid silver chloride (Ksp = 1.8 × 10⁻¹⁰) was added to the vascular fluid to increase osmotic pressure. Assuming the vascular fluid is approximately 1.6 × 10⁻² M NaCl, what is the maximum amount of silver chloride that can be added before a precipitate forms?"

🧪 Use the Ksp + common ion strategy when:

  • You’re dealing with a sparingly soluble salt (like AgCl).

  • The solution already contains a common ion (Cl⁻ from NaCl).

  • The question asks for the maximum amount that can dissolve without precipitation.

🧠 Strategy Steps:

  1. Write the dissociation equation:
     AgCl(s) ⇌ Ag⁺ + Cl⁻

  2. Use the Ksp expression:
     Ksp = [Ag⁺][Cl⁻]

  3. Plug in [Cl⁻] from NaCl:
     Ksp = (x)(1.6 × 10⁻²) = 1.8 × 10⁻¹⁰
     Solve for x = [Ag⁺] = max solubility

  4. This x is the maximum [Ag⁺] that can be added before AgCl starts to precipitate.


20
New cards

Weak electrolytes are characterized by their ____.

Weakly Polar covalent bonds

21
New cards

If something is accepting protons from water and creating hydroxide ions in solution, it is a ___ Bronsted Lowry __.

  1. Strong

  2. base

22
New cards

If a question asks for the ratio of a species with one less hydrogen to one with one more hydrogen, what is it most likely asking us to do?

Use HH equation using a pH and pKa given somewhere in the passage

23
New cards

What does interpolation involve when dealing with concentrations?

Interpolation brings something towards the standard, so if we are measuring concentration and some species is way above the normal, we interpolation by diluting the sample.

24
New cards

If given a pKa and we are asked for a buffer which pH would be suitable?

A pH that is ± 1 pH

So if pKa is 8 we can’t use pH 6 but we can use pH 7 or pH 8.5!

25
New cards

If we are asked to consider whether the keto or enol version of something is preferred at a certain pHand has previously mention pKa, what is it actually asking?

at that pH, and considering their pKa would the species be protonated or deprotonated?

If the pKa is higher than the pH it is more likely protonated, so choose the version that has more H!