AP Calculus AB - Implicit Differentiation and Related Rates

0.0(0)
studied byStudied by 0 people
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
Card Sorting

1/31

flashcard set

Earn XP

Description and Tags

Flashcards covering implicit differentiation, related rates, and tangent line approximations, based on the provided lecture notes, for AP Calculus AB review.

Study Analytics
Name
Mastery
Learn
Test
Matching
Spaced

No study sessions yet.

32 Terms

1
New cards

What rule is essential for implicit differentiation?

The chain rule.

2
New cards

What are the applications of derivatives discussed?

Related rates problems, velocity, and acceleration.

3
New cards

If , then what is the value of at the point ?

Undefined

4
New cards

If cos (xy) = y-1, then what is the value of dy/dx when and y = 1?

0

5
New cards

If ex − y = xy3 + e2 − 18, what is the value of dy/dx at the point (2, 2) ?

Answer C This option is correct. During the implicit differentiation, both the product rule and the chain rule are needed.

6
New cards

If 3x2 + 2xy + y2 = 1, then = ?

(A) (B) (C) (D) (E)

7
New cards

If , then when x=-1, is ?

(A) (B) (C) -1 (D) -2 (E) nonexistent

8
New cards

In related rates, what does the chain rule allow us to do?

Relate the rates of change of different variables.

9
New cards

If x2+xy=10, then when what is dy/dx?

(A) (B) -2 (C) (D) (E)

10
New cards

If , then in terms of x and y, what is dy/dx?

(A) (B) (C) (D) (E)

11
New cards

If sin x = ey, 0 < x < π , what is dy/dx in terms of x?

cot x

12
New cards

If y=ln(x2+y2) , then the value of at the point (1, 0) is

2

13
New cards

If x2+y2=25, what is the value of at the point (4,3) ?

-4/3

14
New cards

The points and are on graph of a function that satisfies the differential equation . Which of the following must be true?

is a local minimum of f.

15
New cards

What is the slope of the line tangent to the curve at the point ?

Answer B Correct. The slope of the tangent line is the value of at the point. During the implicit differentiation to find , both the power rule and the chain rule are needed. The point is on the curve, since and satisfy the equation . At this point, .

16
New cards

If , then the value of at the point is

Answer C Correct. The point is on the curve because , satisfies the implicit equation of the curve. The chain rule is the basis for implicit differentiation.

17
New cards

If , then

Answer D Correct. The chain rule is the basis for implicit differentiation as well as the differentiation of a composite function.

18
New cards

If , then

Answer B Correct. The chain rule is the basis for implicit differentiation.

19
New cards

If , then the value of at the point is

Answer A Correct. The point is on the curve because , satisfies the implicit equation of the curve. The chain rule is the basis for implicit differentiation.

20
New cards

If , then

Answer D Correct. The chain rule is the basis for implicit differentiation as well as the differentiation of a composite function.

21
New cards

If , then

Answer C Correct. The chain rule is the basis for implicit differentiation.

22
New cards

If , then ⅆ ⅆ

Answer A Correct. Both the product rule and the chain rule are used during the implicit differentiation to find the value of ⅆ ⅆ . ⅆ ⅆ ⅆ ⅆ ⅆ ⅆ ⅆ ⅆ ⅆ ⅆ ⅆ ⅆ

23
New cards

What is the slope of the line tangent to the curve at the point ?

Answer C Correct. Both the product rule and the chain rule are used during the implicit differentiation to find the value of at the point .

24
New cards

If what is the value of at the point

Undefined

25
New cards

Let y = f (x) be a twice-differentiable function such that f (1) = 2 and . What is the value of at x = 1 ?

Answer C This option is correct. The answer is obtained by using the chain rule when doing implicit differentiation.The second derivative is found in terms of y and , which can then be written completely in terms of y.The condition f (1) = 2 means that y = 2 when x = 1.

26
New cards

The slope of the tangent to the curve at (2, 1) is

-1

27
New cards

Functions , , and are differentiable with respect to time and are related by the equation . If x is decreasing at a constant rate of 1 unit per minute and y is increasing at a constant rate of 4 units per minute, at what rate is w changing with respect to time when and ?

Answer A Correct. One way to verify that a function is a solution to a differential equation is to check that the function and its derivatives satisfy the differential equation. The differential equation in this option involves and . The correct derivative must be computed and the algebra correctly done to verify that the differential equation is satisfied.

28
New cards

At time , a cube has volume and edges of length . If the volume of the cube decreases at a rate proportional to its surface area, which of the following differential equations could describe the rate at which the volume of the cube decreases?

(E)

29
New cards

Description of removable discontinuity

A removable discontinuity occurs at if exists, but does not exist or is not equal to the value of the limit.

30
New cards

How a tangent line approximates function's value?

tangent line value at will be an underestimate if the graph of is concave up on the interval .

31
New cards

What does the value of when would be an approximation to?

Would be an approximation to , as follows.

32
New cards

Tangent line to the graph of at

An equation of the line tangent to the graph of at is .