CHEMISTRY ALEVEL TEST NOV

0.0(0)
studied byStudied by 0 people
0.0(0)
full-widthCall Kai
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
GameKnowt Play
Card Sorting

1/33

encourage image

There's no tags or description

Looks like no tags are added yet.

Study Analytics
Name
Mastery
Learn
Test
Matching
Spaced

No study sessions yet.

34 Terms

1
New cards

How many electrons can fill the first 4 shells?

1: 2

2: 8

3: 18

4: 32. This is using the formula 2n²

2
New cards

What is an atomic orbital?

A region around the nucleus that can hold up to two electrons, with opposite spins.

3
New cards
<p>What orbital does this picture show?&nbsp;</p>

What orbital does this picture show? 

S- orbital

4
New cards
<p>What orbital does this picture show?</p>

What orbital does this picture show?

P- orbital

5
New cards

What is the number of orbitals making up s- orbital, p-orbital and d-orbital?

S- orbital: 2

P- orbital: 3

d- orbital: 5

6
New cards

What is the number of electrons that can fill the s-subshell, p-subshell and d-subshell?

S-subshell: 2

P-subshell: 6

d-subshell: 10

7
New cards

Use SANDI to describe what happens to ionisation energy across a period.

The number of protons in the nucleus increases, so greater nuclear charge. The increased nuclear charge pulls electrons closer, so the atomic radius decreases. Electrons are added to the same shell, so shielding remains approximately constant. The NUCLEAR attraction between the nucleus and outer electrons increases, therefore first ionisation energy increases across the period.

8
New cards

Use SANDI to describe what happens to the ionisation energy down a group.

The number of protons in the nucleus increases, which increase the nuclear charge, but this is outweighted by extra distance and shielding. The distance increases as outer electrons occupy higher principal energy levels (greater atomic radius). Shielding increases because each element has more filled inner electron shells. Attraction decreases, since outer electrons experience greater shielding and are further from the nucleus. I.E therefore decreases down the group because outer electrons are less strongly attracted to the nucleus.

9
New cards

What is general formula?

the simplest algebraic formula for a member of the homologous series

10
New cards

What is structual formula?

the minimal detail that shows the arrangement of atoms in a molecule

11
New cards

Displayed formula

the relative positioning of atoms and the bonds between them

12
New cards

Skeletal formula

the simplified organic formula, shown by removing hydrogen atoms from alkyl chains, leaving just a carbon skeleton and associated functional groups

13
New cards

homologous series

a series of organic compounds having the same functional group but with each successive member differing by CH2

14
New cards

functional group

a group of atoms responsible for the characteristic reactions of a compound

15
New cards

alkyl group

formula CnH2n+1

16
New cards

aliphatic compound 

a compound containing carbon and hydrogen joined together in straight chains, branched chains or non-aromatic rings

17
New cards

alicyclic compound

an aliphatic compound arranged in non-aromatic rings with or without side chains

18
New cards

aromatic compound

a compound containing a benzene ring

19
New cards

saturated 

single carbon–carbon bonds only

20
New cards

unsaturated

the presence of multiple carbon–carbon bonds, including C=C, C C / and aromatic rings

21
New cards

Homolytic fission

The breaking of a covalent bond with each bonding atom receiving one electron from the bonded pair forming two radicals.

22
New cards

Describe and explain the effect of chain length on the boiling point of hydrocarbons using ideas about intermolecular forces.

As the chain length of a hydrocarbon increases, its boiling point increases because there are more electrons and a larger surface area, leading to stronger London dispersion forces between molecules.

23
New cards

Describe and explain the effect of branching on the boiling point of hydrocarbons using ideas about intermolecular forces.

More branching in a hydrocarbon decreases the boiling point because branched molecules have a smaller surface area in contact with others, so fewer London dispersion forces form and less energy is required to overcome them.

24
New cards

State why branched chain alkanes and cycloalkanes are more useful than straight chain alkanes

They burn more efficiently.

25
New cards

Can you describe the problems associated with radical substitution

  • Substitution at any point on a carbon chain leading to a mixture of

    isomers

  • Multiple substitutions on a carbon chain leading to di, tri

    haloalkanes etc

  • Multiple termination steps leading to other products

26
New cards

How to convert Celsius to kelvin

Add 273

27
New cards

What is the formula for concentration (mol/dm³)

mol/vol

28
New cards

3 ways to calc moles?

n = m/mr

n = v/24 (rtp)

n = c x v

29
New cards

cm³ - dm³

divide 1000

30
New cards

cm³ - m³ 

divide by 1000000

31
New cards

dm³ - m³

divide 1000

32
New cards

m³ - dm³

x1000

33
New cards

ideal gas equation

pv = nRT

R = 8.31

34
New cards

cm3 to dm3

divide by 1000