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Electrolysis half equations to learn
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Chemistry
10th
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1
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copper chloride (aq)
ions present:
Cu²⁺, Cl⁻, H⁺, OH⁻
anode reaction:
2Cl⁻ → Cl₂ + 2e⁻
cathode reaction:
Cu²⁺ + 2e⁻ → Cu
2
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sodium chloride (aq)
ions present:
Na⁺, Cl⁻, H⁺, OH⁻
anode reaction:
2Cl⁻ → Cl₂ + 2e⁻
cathode reaction:
2H⁺ + 2e⁻ → H₂
3
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sodium sulphate (aq)
ions present:
Na⁺, SO₄²⁻, H⁺, OH⁻
anode reaction:
4OH⁻ → O₂ + H₂O + 4e⁻
cathode reaction:
2H⁺ + 2e⁻ → H₂
4
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water acidified with sulphuric acid (H₂SO₄)
ions present:
H⁺, OH⁻, SO₄²⁻
anode reaction:
4OH⁻ → O₂ + H₂O + 4e⁻
cathode reaction:
2H⁺ + 2e⁻ → H₂
5
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molten lead bromide
ions present:
Pb²⁺, Br⁻
anode reaction:
2Br ⁻ → Br₂ + 2e⁻
cathode reaction:
Pb²⁺ + 2e⁻ → Pb