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Inverse of a 2 by 2
Reciprocal of the determinate times matrix w/ d and a swapped and b and c with negative
AX = C → X = A^-1 C. ORDER MATTERS
As long as there’s a determinate, there’s an inverse
Add matrices
[2 1] + [4 3] = [6 4]
lit js add terms. Must hv same dimensions to do so
Also 3[2 1] can be rewritten as [6 2] js multiply out
Multiply matrices
It’s gotta be the column of the first matrices is same dimension of row as other.
So you can do a 1 × 3 by a 3 × 4 , but not a 1 × 3 by a 4 × 3.
Inside dimensions must match
The outside dimension is the answers dimensions, so in the example above, a 1 by 4.
solving for C11: row 1 with column 1. 1A times 1A + 1B times 2A etc. 21 would be row 2 of 1st w/ column 1 of 2nd.
The order you multiply MATTERS. If you change the order the answers different.
Matrix parts
Matrix A is a 2 by 2
Elements A11, A12, A21, A22
Matrix is written ROW BY COLUMN
A matrix is like a table.
Determinate of a 2 by 2
ad-bc
Determinate of a 3 by 3
a (ei - fh) -b (di - fg) + c(dh - eg)
shortcut(risky)
sum of products of right diagonals minus sum of products of left diagonals
Area of a triangle
Make a 3 by 3 w/ column 1 as x column 2 as y column 3 all as 1. That determinant times ½ is the area.
Co-linear points
Same 3 by 3 as a triangle. If the determinate is 0 (so the area is 0) they are collinear
How to transform matrices
It would be an b x 2 by a 2 × 2, so it works column each for x and y
Reflect along y axis (invert): [-1 0, 0 1]
X axis (upside down): [1 0, 0 -1]
Sign swap for diff axis x starts positive tho
Multiply this matrix by the points matrix to transform all the points
Cramer’s rule on a 3 variable system
Make a matrix for the x y and z side. Find that determinant D
Replace the x with what each equation equals
Like if 2x + 3y + 4z = 6. [2 3 4] → [6 3 4]. Do this for all equations to make a matrix to solve for Dx
Repeat this but for y and z.
Dx/d is x coordinate and so on for y and z
If it’s a system to rewrite as a matrix:
{ax + by = c} → [a b : c] but it’s 3 dots
What does it mean when | x | instead of [ x ]
Ask Nikhil fr