Due to lack of mathematical symbols: Italic “E” will serve as epsilon/strain symbol, Italic “p” for raw, “B” for beta, etc.
Mu
Design Moment Capacity / Ultimate Moment Capacity
Mn
Nominal Moment Capacity
C
compressive force (Concrete)
T
Tensile force (Steel)
C [d-a/2] or T [d-a/2]
Mn = _____
ø
Reduction factor
øs
diameter of stirrups
Recommended reduction factor according to Table 421.2.1 Strength Reduction Factors, ø
ø → 0.65-.090
a
distance from the fiber of maximum compressive strain
depth of compression block
B1c
a = _____
b
beam width
c
Distance from the fiber of maximum compressive strain to the neutral axis. Measured perpendicular to the neutral axis.
depth of neutral axis
d
effective depth
dt
distance of the centroid of the extreme tension bars to the extreme compression fiber
cc
concrete cover
0.85fc’ab
C’ = _____
Formula for the resultant force of the rectangular stress at the compressive block.
Whitney’s Rectangular Stress Distribution
fsAs
T = ____
Formula for the resultant force located at the centroid of the tensile block.
Table 422.2.2.4.3
Values of B1 for Equivalent Rectangular Concrete Stress Distribution
0.85 ←→ 0.65
Limits of B1
B1 = 0.85
fc’ = 17 → 28 MPa
B1 = 0.85 - 0.05/7 (fc’-28)
fc’ > 28 MPa
fc’ < 55 MPa
B1 = 0.65
fc’ > 55 MPa
fy
yield strength/stress of the Steel Reinforcement
grade ng bakal
usually in ksi
English
System of unit used when the Grade is less than 100 ksi.
Metric
System of unit used when the Grade is greater than 100 ksi.
0.002
421.2.2.1
For Grade 415/420 deformed reinforcement, it shall be permitted to take Ety equal to ____.
200 000 MPa
Es (Modulus of elasticity of steel)
0.003 [(d-c)/c]
Es (Tensile strain in steel)
εt
Net tensile strain
εc
compressive strain of the concrete = 0.003
εty
fy/Es = yield strain
0.003 [(dt-c)/c]
Et = _____
Neutral Axis
Where strain is equal to zero (0).
Compression controlled
(Spiral=0.75, Other=0.65)
Classification for when the hoops/anilyo on the tensile block is not yielding.
Et < Ety
fs < fy
Transition
(Spiral= 0.75 + 0.15 [(fs-fy)/(1000-fy)], Other= 0.65 + 0.25 [(fs-fy)/(1000-fy)])
Ety < Et < 0.005
fy < fs < 1000
Tension controlled
(Spiral=0.90, Other=0.90)
Classification for when the hoops/anilyo on the tensile block is yielding.
Et > 0.005
1000 < fs
Transition
Et > Ety
Et < 0.005
ρ
steel reinforcement ratio
ρact
As/bd
ρmin
1.4/fy ; √fc’/4fy or (0.25√fc’)/fy
*whichever is higher
ρmax
[by the code]
(0.85fc’/fy) (3/7) B1 (dt/d)
pmax
[tension controlled]
(0.85fc’/fy) (3/8) B1 (dt/d)
3/7 dt
c if Et = 0.004
3/8 dt
c if Et = 0.005 (T.C.)
m
fy/0.85fc’
As/bd
p = ___
εt = 0.004
Maximum reinforcement (by the code)
εt = 0.005
Maximum reinforcement for maximum tension control (T.C.)
As min
Minimum area of flexural reinforcement.
As
Area of steel reinforcement
10 mm
Minimum stirrup size according to code.
25 mm
CS2 = ____
25 mm; dB; 4/3 d(aggregates)
CS1 = ____
dB
25 mm; dB; 4/3 d(aggregates)
Which is the largest of the three clear spacings (1).
ACI (American Concrete Institute)
Where did the philippines referenced their code?
600[(d-c)/c]
fs = ____
h
depth/height of the beam
fs
tensile strength/stress of the Steel Reinforcement
fc’
compressive strength/stress of the concrete
steel cover
effective concrete cover
cc+øs