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rate law expression of zero order
R = K
rate law expression of first order
R = K[A]
rate law expression of 2nd order
R = K[A]^2
integrated rate eq. of zero order
[A]t = [A]0 - kt
integrated rate eq. of first order
ln ([A]0/[A]t) = kt
integrated rate eq. of 2nd order
1/[A]t - 1/[A]0 = kt
half life equation of zero order
[A]0/2k
half life equation of 1st order
ln2/k or .693/k
half life equation of 2nd order
1/k[A]0
plot that gives straight line for zero order rxn
[A] vs. t (slope is negative)
plot that gives straight line for 1st order rxn
ln[A] vs. t (slope is negative)
plot that gives straight line for 2nd order reaction, what is the slope
1/[A] vs. t (slope is positive)
slope of the line for zero order reaction
-k
slope of the line for 1st order reaction
-k
slope of the line for 2nd order reaction
k
k units for zero order
conc/time
k units for 1st order
/time
k units for 2nd order
/conc*time
all radioactive decay is what order
1st order
rate law expression
R = k[A]^m
when the [A] doubles how does the rate change for the reaction if it was zero, 1st, or second
zero: rate remains unchanged. first: rate doubles. second: rate quadruples
rate
how fast reactants are used up or products are formed, look at in (change in observed property)/(change in time)
rate expressed for reactants vs products
(note: c = product, a = reactant) rate = delta[C]/delta t = -delta[A]/delta t
create a math expression for this reaction in terms of A. 2A + B --> C. What does this mean
rate = -delta[A]/(2*delta t). Means that A is decreasing two times faster than the formation of C and decreasing twice as fast as B.
what are the units of rate
concentration/time
why is the initial rate the fastest
greatest change in time due to collision theory, that there are more reactants to react with
collision theory
process by which most chemical reactions are thought to occur. particles must collide w/ sufficient E and correct orientation in order for rxn to continue to products.
what gives you the instantaneous rate
plot the [ ] vs time and take tangent to curve at desired point
rate depends on what 4 factors
1. nature of reactant 2.concentration of reactant 3. temperature 4.catalysts
how does nature of reactant affect rxn rates
chemical identity, physical state (the more surface area of a solid or liquid will increase the rxn rate), reactions between ions (no bonds to break)
how does concentration of reactants affect rxn rates
rate law (first, second, zero order)
how does temperature affect rxn rates
collision theory (reactants moving faster) and integrated rate law (for every 10 degrees rxn rate doubles because molecules move faster and collide more often)
how does catalyst affect rxn rates
(both heterogeneous and homogeneous) catalyst lower the activation energy hill and participates in rxn yet it is fully recoverable after the rxn, can also speed up a reaction
reaction mechanism
series of steps by which a reaction is thought to occur; how many steps it takes a rxn to occur
rate is always...
positive
the rxn mechanism is comparable to what
comparable to the route taken by the rxn
the chemical equation specifies what
the origin and destination, but not the route traveled
elementary steps or elementary reactions
series of simple reactions
overall rxn represents what 2 things
represent the progress of reaction at a molecular level(series of elementary steps, which make up the reaction mechanism), and Hess's Law.
hess's law (two things)
the sum of elementary steps = overall rxn. The rxn goes only as fast as the slowest step
what does it mean if a rxn is single step (plus example)
the coefficients of reactants are the orders. Occurs in single step so... 2A + B --> C overall 3rd order rxn. R = k[A]^2[B]
bimolecular
2 different substances coming together
R = [NO]^2[Br], single elem. step, is this mechanism likely for this reaction
no, termolecular (3 different things coming together)
what is the rate determining step in a multi-elementary step rxn
the slowest step or the step with the highest Ea.
what must the rate determining step have
coefficients of the rate determining step must match the orders in the rate law. sum of steps must equal overall rxn
do rate laws include intermediates
no
what does it mean if the mechanism has an initial fast step
more difficult to derive rate law for mechanism if first step isn't the rate determining step as intermediate would then be a reactant in the rate determining step
if there is an equilibrium with an intermediate what do you do
substitute the intermediate
half life rxn for second order depends on what
concentration of [ ]0
integrated rate equation
allowed to find [ ] at particular time or amt of time that has elapsed
first order runs (with eq.)
those in wh/ rate depends on [reactants] raised to the first power. A --> products. Rate = -delta[A]/delta t. or k[A]
second order rxns
those wh/ rate depends on [reactants]^2. A --> product. rate = -delta[A]/delta t. or k[A]^2
half life rxn
time required the conc. of a reactant to decrease to half of its initial conc.
what does the collision theory explain
the effect of time and [ ] on rate of reaction explained
what two properties must a molecule possess in order to react according to the collision theory
1. must collide w/ proper orientation and sufficient energy. 2. anything wh/ increases # of collisions/unit time will also increase react rate
enthalpy is proportional to what
Potential energy
how does activation energy change
with change in temperature and use of catalyst
activation energy (what does it change with)
minimum energy required to raise the E of reactants to that of the activated complex, specific to rxn at a specific temperature
how is activation energy determined
determined experimentally