Electron Donating and Electron withdrawing groups

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Aromaticity and Benzene rxtns

Last updated 9:06 PM on 8/9/26
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14 Terms

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Ortho position

1,2 position

<p>1,2 position</p>
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Meta position

1,3 position

<p>1,3 position</p>
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Para Position

1,4 position

<p>1,4 position </p>
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Strongly deactivating groups are. (EWG)

CN, NR3, and NO2

they are META directors

<p>CN, NR3, and NO2 </p><p>they are META directors </p>
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moderate deactivating groups (EWG)

Ketone / acyl group

Ester

Carboxylic acid

Sulfonic acid

META directors

<p><strong>Ketone / acyl group</strong></p><p><strong>Ester</strong></p><p><strong>Carboxylic acid</strong></p><p><strong>Sulfonic acid</strong></p><p>META directors </p>
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weakly deactivating groups (EWG)

F, Cl, Br, I

these are the exception

ORTHO/PARA directors

<p>F, Cl, Br, I</p><p>these are the exception</p><p>ORTHO/PARA directors </p>
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Weakly activating groups (EDG)

alkyl group

ORTHO PARA directors

<p>alkyl group </p><p>ORTHO PARA directors </p>
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moderate/strong activating groups (EDG)

Thioether (sulfide)

Thiol

Ether / alkoxy group

Alcohol / hydroxyl group

Ester

Amide

ORTHO PARA directors

<p><strong>Thioether (sulfide)</strong></p><p> <strong>Thiol</strong></p><p><strong>Ether / alkoxy group</strong></p><p><strong>Alcohol / hydroxyl group</strong></p><p><strong>Ester</strong> </p><p><strong>Amide</strong> </p><p>ORTHO PARA directors </p>
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most strongly activating (EDG)

Primary amine

Secondary amine

Tertiary amine

ORTHO PARA directors

<p><strong>Primary amine</strong></p><p><strong>Secondary amine</strong></p><p><strong>Tertiary amine</strong></p><p>ORTHO PARA directors </p>
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When multiple substituents are on ring which is the director?

The more activating/EDG of the two

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Acyl groups are

meta directors

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What needs to be present for a benzylic oxidation to occur

must have at least one benzylic hydrogen

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Aromaticity rules

1. The compound must be cyclic.

2. The ring must be fully conjugated and planar (none of the atoms comprising the ring are sp3

.......hybridized).

3. The system must satisfy Huckel’s rule (# of pi electrons = 4n+2; n is any integer).

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Anti aromatic breaks which rule

huckles rule but follow all others