Atomic structure

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43 Terms

1
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Why is the mass number (top number) a decimal?

  • Because of the presence of isotopes

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Define isotopes

  • Atoms of the same element with different numbers of neutrons and masses

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Why do all isotopes of an element react in the same way?

  • They have the same electron configuration

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What does abundance tell you?

  • How common each isotope is

  • E.g. 69% of copper atoms are copper 63

  • 31% of copper atoms are copper 65

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How can we determine the mass number and abundance of isotopes ?

  • Use a machine called a mass spectrometer

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Outline the stages of the time of flight mass spectrometer

  • Take a sample of the element your interested in. Place it in the sample chamber

  • The sample contains all of the different isotopes of that element

  • Atoms go through a process of ionisation. Converting all the atoms into positive ions

  • These positive ions are now attracted to a negatively charged plate

  • The negatively charged plate causes the ions to accelerate increasing kinetic energy of the ions

  • All of the ions with the same charge will have the same kinetic energy

  • Once the ions pass through the negative plate. They stop accelerating

  • They then drift down the flight tube at different velocities .With lighter ions moving faster than heavier ions

  • After reaching the detector, each positive ion gains an electron from the detector.( An ion with a single positive charge will gain a single electron)

  • This transfer of electrons causes a current to flow

  • Ions of the lighter isotope will have a greater velocity and reach the detector first

  • Size of current produced when each isotope hits the detector is proportional to its abundance

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Why is the interior of the mass spectrometer a vacuum?

  • To prevent the ions from colliding with air molecules

  • As this can cause the ions to be deflected and slowed down

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Explain electron impact

  • Its a method of ionisation

  • A vapourised sample is injected at a low pressure

  • Electron gun fires high energy electrons at the sample

  • Knocking out outer electron

  • E.g. Ti → Ti+ + e-

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Explain electrospray ionisation

  • Sample is dissolved in a volatile solvent

  • Injected through a needle connected to a high voltage

  • Molecules gain H+

  • E.g.: Mg + H+ →MgH+

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Interpretating the mass spectrum

  • 2 peaks show that Copper has 2 main isotopes with an abundance of 69.2% and 30.8%

  • M/Z = Ratio of the mass of each ion to its charge

  • All of the ions have a single positive charge so the M/Z ratio is basically the relative mass of the ion

<ul><li><p>2 peaks show that Copper has 2 main isotopes with an abundance of 69.2% and 30.8%</p></li><li><p>M/Z = Ratio of the mass of each ion to its charge </p></li><li><p>All of the ions have a single positive charge so the M/Z ratio is basically the relative mass of the ion</p></li></ul><p></p>
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What happens when mass spectrometry is carried out on a molecule?

  • A range of peaks are formed due to fragmentation

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What does fragmentation do?

  • When fragmentation happens a bond breaks, forming a molecular ion and a radical.

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What can the fragmentations be used for?

  • They can help identify the molecule

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Mass spectrum for carbon dioxide

  • The peak at 44 shows you a molecule that has an mr of 44. It can be assumed that it is co2. This peak is called a molecular ion M+

  • The rest of the peaks depict other parts of the molecule that have been ionised

  • The other peaks give you the mr of the atoms in the molecule that help figure out what that the molecule is

  • The peak at 12 (mr of carbon) tells you there is a carbon in the molecule

<ul><li><p>The peak at 44 shows you a molecule that has an mr of 44. It can be assumed that it is co2. This peak is called a molecular ion M<sup>+</sup> </p></li><li><p>The rest of the peaks depict other parts of the molecule that have been ionised </p></li><li><p>The other peaks give you the mr of the atoms in the molecule that help figure out what that the molecule is </p></li><li><p>The peak at 12 (mr of carbon) tells you there is a carbon in the molecule</p></li></ul><p></p>
15
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How can the maximum number of electrons an energy level can hold be calculated

  • 2n2

  • n being the energy level

  • E.g. the first energy level can hold 2 electrons 2(1)2

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Electrons in energy levels are found in regions called……

  • Atomic orbitals

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Define atomic orbital

  • A region around the nucleus that can hold up to 2 electrons with opposite spins

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Shape of the s orbital

  • spherical

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Shapes of p orbitals

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20
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What happens to the energy of the shells as you move further from the nucleus ?

  • energy of the shell increases

  • weaker electrostatic force of attraction between nucleus and electrons means electrons on shells further from the nucleus require more energy to stay in these positions

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Order of orbital filling

  • 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6

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Rules for filling atomic orbitals

  • Orbitals with the lowest energy are filled first

  • Can have 2 electrons in each orbital but they must have opposite spins

  • Fill 4s before 3d

  • Fill orbitals with the same energy singly, before pairing. Because electrons in the same orbital repel

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Name 2 elements exempt from orbital filling rules and why

  • Chromium and copper

  • When filling the orbitals for these 2 elements put only 1 electron in 4s and the rest in 3d

  • Because 3d subshell is most stable when its completely or half full

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Electron configuration is always written in order of …..

  • shells not filling

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Whats the shorthand configuration for sodium

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What is the shorthand configuration for sulphur?

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When an atom forms an ion which subshell does it loose or gain electrons from or in

  • The subshell with the highest energy

28
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What is the electron configuration of an Mg atom and an Mg2+ ion?

  • Mg atom=1s2 2s2 2p6 3s2

  • Mg2+ ion = 1s2 2s2 2p6

  • Mg loses 2 electrons from the 3s subshell to form a positive ion

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What happens when a D block element becomes an ion and why

  • It loses electrons from 4s subshell before 3d

  • The 4s subshell always filled before 3d. As 4s has lower energy than 3d

  • Once the 4s subshell contains electrons it has a higher energy than 3d subshell

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Electron configuration for Fe and Fe2+

  • Fe = 1s2 2s2 2p6 3s2 3p6 3d6 4s2

  • Fe2+ = 1s2 2s2 2p6 3s2 3p6 3d6

  • Fe is a d block element

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What do you need to remove an electron from an atom?

  • Energy

32
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Define first ionisation energy

  • Energy needed to remove one mole of electrons from one mole of atoms in their gaseous state to form one mole of 1+ ions in their gaseous state

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First ionisation energy equation for Mg

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What is meant by successive ionisation energies?

  • Once you have removed 1 electron you can continue to remove electrons and measure the ionisation energy each time

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Define second ionisation energy

  • Energy required to remove one mole of electrons from one mole of 1+ ions in their gaseous state to form one mole of 2+ ions in their gaseous state

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Second ionisation equation for Mg

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The stronger the attraction between the outer electrons and the positive protons in the nucleus…

  • The greater the ionisation energy

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Factors affecting ionisation energy

  • Atomic radius (distance between outer electrons and nucleus)

  • Charge on the nucleus (the greater the amount of protons, the greater the force of attraction)

  • Shielding (More shells reduce the attraction)

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Explaining the successive ionisation energies of oxygen

  • For the first to six electrons there was a gradual increase in the ionisation energy

  • This is because all 6 electrons were removed from oxygens outer shell (low attraction between nucleus and outer electrons so little ionisation energy needed)

  • But the remaining 2 electrons were on the shell closest to the nucleus. Higher ionisation energy was needed to remove the 7th and 8th electron

<ul><li><p>For the first to six electrons there was a gradual increase in the ionisation energy</p></li><li><p>This is because all 6 electrons were removed from oxygens outer shell (low attraction between nucleus and outer electrons so little ionisation energy needed)</p></li><li><p>But the remaining 2 electrons were on the shell closest to the nucleus. Higher ionisation energy was needed to remove the 7th and 8th electron</p></li></ul><p></p>
40
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Explain the trend for first ionisation energy down a group

  • FIE decreases down a group

  • Atomic radius increases-meaning the outer electron is further from the nucleus/weaker force of attraction

  • Number of energy levels increase-more shielding

  • Although charge on the nucleus increases its effect is cancelled by the other 2 factors

41
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Explain the trend for FIE across a period

  • FIE generally increases

  • Nuclear charge increases- higher number of protons/stronger attraction→ more energy is needed

  • Strong attraction also decreases atomic radius as outer electrons are pulled closer to the nucleus

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FIE of elements in period 2

  • In period 2 the FIE of oxygen and boron actually decreases

  • This is due to their electron configuration

  • Oxygen has a pair of electrons in its p subshell. Less energy required to remove these electrons as they repel each other

  • Boron has one electron in its p subshell whereas Be doesn’t have a p subshell.

  • It is easier to remove that one electron in boron’s p subshell as it is further away from the nucleus

<ul><li><p>In period 2 the FIE of oxygen and boron actually decreases </p></li><li><p>This is due to their electron configuration</p></li><li><p>Oxygen has a pair of electrons in its p subshell. Less energy required to remove these electrons as they repel each other </p></li><li><p>Boron has one electron in its p subshell whereas Be doesn’t have a p subshell.</p></li><li><p>It is easier to remove that one electron in boron’s p subshell as it is further away from the nucleus </p></li></ul><p></p>
43
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