Midterm 4 Practice

studied byStudied by 0 people
0.0(0)
Get a hint
Hint

If F is a vector field, then div F is a vector field. True or False

1 / 27

flashcard set

Earn XP

Description and Tags

Conceptual Questions!

28 Terms

1

If F is a vector field, then div F is a vector field. True or False

False: div F results in a scalar function

New cards
2

If F is a vector field, then curl(F) is a vector field.

True: curl(F) results in a vector function

New cards
3

If f has continuous partial derivatives of all orders on ℝ3, then div(curl(∇f)) = 0.

True:

<p>True:</p>
New cards
4

If f has continuous partial derivatives of all orders on ℝ3 and C is any circle, then

∫∇f · dr = 0.

TRUE: if function is continuous and derivatives exist then line integral in a closed path is zero

New cards
5

If F = P i + Q j and Py = Qx in an open region D, then F is conservative.

FALSE: To satisfy the conservative property, the region D should be open AND simply connected

New cards
6
term image

FALSE

New cards
7

If F and G are vector fields and div F = div G, then F = G

FALSE: Check this counter-example

<p>FALSE: Check this counter-example</p>
New cards
8

The work done by a conservative force field in moving a particle around a closed path is zero.

TRUE: A force is conservative exactly when the work it does on an object is zero for every possible closed path the object can take.

New cards
9

If F and G are vector fields, then curl(F + G) = curlF + curlG

TRUE: Try an example!

<p>TRUE: Try an example!</p>
New cards
10

If F and G are vector fields, then curl(F · G) = curlF · curlG

FALSE: Intuitively, you can see this will be false because F · G = scalar. curl is defined for vectors only

New cards
11

If S is a sphere and F is a constant vector field, then ∫∫s F · ndS = 0

TRUE: ∫∫s F · ndS = ∫∫∫v div F dudydz if F is constant then div F = 0 therefore, ∫∫d F · ndS = 0

New cards
12

There is a vector field F such that curl(F) = xi + yj + zk

FALSE: Every vector function G satisfies the property: div(curlF) = 0 if curl(F) = xi + yj + zk, then div(curl(F)) = 3 Since this results in a non zero scalar, the statement is false

<p>FALSE: Every vector function G satisfies the property: div(curlF) = 0 if curl(F) = xi + yj + zk, then div(curl(F)) = 3 Since this results in a non zero scalar, the statement is false</p>
New cards
13
<p>The area of the region bounded by the positively oriented, piecewise smooth, simple closed curve C is A= - ∮c ydx</p>

The area of the region bounded by the positively oriented, piecewise smooth, simple closed curve C is A= - ∮c ydx

TRUE: The area pf the region bounded by positively oriented, piecewise smooth, simply closed curve C can be represented with A= ∮c ydx and A= ∮c ydx = - ∮c ydx

<p>TRUE: The area pf the region bounded by positively oriented, piecewise smooth, simply closed curve C can be represented with A= ∮c ydx and A= ∮c ydx = - ∮c ydx</p>
New cards
14

is curl(f) a ...

a) scalar field b) vector field c) not meaningful

c) not meaningful

New cards
15

is grad(f) a ...

a) scalar field b) vector field c) not meaningful

b) vector field

New cards
16

(F is a vector function) is div(F) a ...

a) scalar field b) vector field c) not meaningful

a) scalar field

New cards
17

is curl(grad(f)) a ...

a) scalar field b) vector field c) not meaningful

b) vector field

New cards
18

is grad(F) a ...

a) scalar field b) vector field c) not meaningful

c) not meaningful

New cards
19

is grad(div(F) a ...

a) scalar field b) vector field c) not meaningful

c) vector field

New cards
20

is div(grad(f)) a ...

a) scalar field b) vector field c) not meaningful

a) scalar field

New cards
21

is grad(div(f)) a ...

a) scalar field b) vector field c) not meaningful

c) not meaningful

New cards
22

is curl(curl(F)) a ...

a) scalar field b) vector field c) not meaningful

b) vector field

New cards
23

is div(div(F)) a ...

a) scalar field b) vector field c) not meaningful

c) not meaningful

New cards
24

is (grad(f)) x (div(F)) a ...

a) scalar field b) vector field c) not meaningful

c) not meaningful

New cards
25

is div(curl(grad(f))) a ...

a) scalar field b) vector field c) not meaningful

a) scalar field

New cards
26

If all the component functions of F have continuous partials, then F will be conservative if

curl(F) = 0

New cards
27

A vector field G exists in R^3 if...

div(curl G) = 0

New cards
28

Fundamental Theorem of Line Integral

knowt flashcard image
New cards

Explore top notes

note Note
studied byStudied by 26 people
Updated ... ago
5.0 Stars(2)
note Note
studied byStudied by 79 people
Updated ... ago
5.0 Stars(1)
note Note
studied byStudied by 10 people
Updated ... ago
5.0 Stars(1)
note Note
studied byStudied by 8100 people
Updated ... ago
4.8 Stars(53)
note Note
studied byStudied by 122 people
Updated ... ago
5.0 Stars(2)
note Note
studied byStudied by 19 people
Updated ... ago
5.0 Stars(1)
note Note
studied byStudied by 391 people
Updated ... ago
4.1 Stars(7)
note Note
studied byStudied by 645 people
Updated ... ago
5.0 Stars(3)

Explore top flashcards

flashcards Flashcard21 terms
studied byStudied by 2 people
Updated ... ago
5.0 Stars(1)
flashcards Flashcard132 terms
studied byStudied by 36 people
Updated ... ago
5.0 Stars(1)
flashcards Flashcard77 terms
studied byStudied by 4 people
Updated ... ago
5.0 Stars(1)
flashcards Flashcard71 terms
studied byStudied by 23 people
Updated ... ago
5.0 Stars(1)
flashcards Flashcard67 terms
studied byStudied by 10 people
Updated ... ago
5.0 Stars(1)
flashcards Flashcard40 terms
studied byStudied by 79 people
Updated ... ago
5.0 Stars(1)
flashcards Flashcard20 terms
studied byStudied by 5 people
Updated ... ago
5.0 Stars(1)
flashcards Flashcard79 terms
studied byStudied by 26 people
Updated ... ago
5.0 Stars(2)