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Newton’s 1st law
The law of Inertia: An object at rest will stay at rest and an object in motion will stay in motion unless acted upon by an unbalanced force
Newton’s 2nd law
The force applied to a mass is proportional to the acceleration the mass will experience
F=ma
Newton’s 3rd law
For every action there is an equal and opposite reaction
Action Reaction forces
Each force on a force diagram will have an action reaction pair
ex: Action: tire pushes on road Reaction: road pushes the tire
Fg
mass (always down)
Fn
Surface (perpendicular)
Ft
Rope, string (along the rope)
Ff
Friction (brakes on a car, not the engine) (opposite of motion)
Fa
In contact that makes object move (direction of push/pull)
Fg=
mg
Fnet=
ma
Fair
Only if problem mentions it (Opposite direction of motion)
Balanced forces
No acceleration (constant or 0 v), net force is 0
Inertia
Tendency of an object to resist changes in its motion.
Frictional force
Amount of force opposing motion
Unit: N
Kinetic friction
the object is in motion
Static friction
the object is motionless
Coefficient of friction
Ratio of force of friction to force normal
Unit: N/N or nothing
Variable: μ
Fs
Range of values dependent on the magnitude of the horizontal force being applied
Fk=
μFn
Fs < or equal to
μFn
Coefficient of friction (μ) is the slope
Can’t be greater than 1
Whenever two objects interact
each exerts a force on the other as a result of the interaction
Pairs of forces in interaction are:
Equal in magnitude
Opposite in direction
Same in kind
An object in equilibrium (balanced forces)
remains at rest
moves in constant speed/straight line
Newton’s 2nd law of motion a=
fnet/m (fnet is also =mgsin)
According to Newton’s 2nd law of motion, (when the angle changes)
a increases when the angle increases, because mgsin also increases
net force and a have a direct relationship
According to Newton’s 2nd law of motion, (when the mass changes)
a decreases, when mass increases
increasing mass also increases the net force
inversely related
Elevator problem: a=
(fn-fg)/m
Elevator problem: a is upward
Fn>Fg
Elevator problem: a is downward
Fn<Fg
If either (multiple) mass increases
then the gravitational force between the two objects increases by the same proportion (direct relationship)
If the distance between the centers of mass increases,
then the gravitational force between the two objects decreases by the square of the proportion
fgy=mgsin
points down the ramp (causes sliding)
fgx=mgcos
pushes into the ramp (balanced by the normal force)
“Constant” force means
acceleration